x = 2 × 2 × 2 × 17 which are prime factors of x.10. Show that any p

1.	x = 2 × 2 × 2 × 17 which are prime factors of x.10. Show that any positive odd integer is of the form 6q 1 or 64+ 3 orinteger.NCERTCase-II1:dd integer and h = 6 Then, bv Euclid,s algorithm,r, for sa-gorithm, a 6Hence
Answer» Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder. according to Euclid's division lemmaa=bq+ra=6q+r where a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5 but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.

x = 2 × 2 × 2 × 17 which are prime factors of x.10. Show that any positive odd integer is of the form 6q 1 or 64+ 3 orinteger.NCERTCase-II1:dd integer and h = 6 Then, bv Euclid,s algorithm,r, for sa-gorithm, a 6Hence

Answer»

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemmaa=bq+ra=6q+r

where a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5

but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.