Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
नायर ————— e ——————E——————— % v W12 हजार + 13 सौ + 2 दहाई बराबर »() 12132 (2) 13320 \ |
|
Answer» 12000+1300+20=13320.00 आठ हजार पांच सौ बीस |
|
| 2. |
Ex.40 Find ZOBA in given figure198°Sol. |
| Answer» | |
| 3. |
(1) Find AtifA-Sol. Let A -1-4 |
|
Answer» Let A=, |
|
| 4. |
X can do a piece of work in 25 days and Y can finish it in 20 days. They work together for 5 days andthen Y leaves. In how many days will X finish the remaining work |
|
Answer» Can you send me screen shot |
|
| 5. |
23. Which term of the AP 3, 14, 25, 36, willbe 99 more than its 25th term?[CBSE 2011] |
|
Answer» In this AP,a=3 d=14-3=11 tn=a+(n-1)dt25=3+(25-1)11t25=3+24(11)t25=267 tn=t25+99tn=267+99 tn=366 3+(n-1)11=366(n-1)11=363n-1=33 n=34 |
|
| 6. |
2. Find a cubic polynomial with the sum of zeroes, sum of the product of its zeroestaken two at a time and product of its zeroes as(ii) 2,-5, -20(ii)3(v) 23,CBSE SP 2011 |
|
Answer» (i) Let α, β and ɣ be the roots of the cubic polynomialGiven (α + β + ɣ) = 3(αβ+ βɣ + ɣα) = – 8 and (αβɣ) = –13The cubic polynomial with roots α, β and ɣ is x³ – (α + β + ɣ)x² + (αβ+ βɣ + ɣα)x – (αβɣ) = 0⇒ x³– (3)x² + ( – 8)x – (13) = 0⇒ x³ – 3x² – 8x + 13 = 0 (ii) Let α, β and ɣ be the roots of the cubic polynomialGiven (α + β + ɣ) = 2(αβ+ βɣ + ɣα) = – 5 and (αβɣ) = –20The cubic polynomial with roots α, β and ɣ is x³ – (α + β + ɣ)x² + (αβ+ βɣ + ɣα)x – (αβɣ) = 0⇒ x³– (2)x² + ( – 5 )x – ( – 20) = 0⇒ x³ – 2x² – 5x + 20 = 0 thanks tell me 3rd part please (iii) Let α, β and ɣ be the roots of the cubic polynomialGiven (α + β + ɣ) = -4(αβ+ βɣ + ɣα) = 1/2 and (αβɣ) = –1/3The cubic polynomial with roots α, β and ɣ is x³ – (α + β + ɣ)x² + (αβ+ βɣ + ɣα)x – (αβɣ) = 0⇒ x³– (-4)x² + ( –1/2 )x – ( – 1/3) = 0⇒ 6x³ + 24x² – 3x + 2 = 0 Can we became friends and help each other on whatsapp |
|
| 7. |
1and find thediffevence betueen |
|
Answer» 7/10 -1/5= 7/10 -2/10= 5/10= 1/2 |
|
| 8. |
1and 3k + 2 are in A.P.? |
|
Answer» Let a1= 2k, a2= k+10, a3= 3k+2 are in AP, then Second term - first term = third term - second term K+10 -(2k) = 3k+2-(k+10) K+10-2k =3k+2-k-10 k -2k +10 = 3k-k +2-10 -k +10= 2k -8 -k-2k= -8-10 -3k = -18 k =18/3= 6 k= 6 |
|
| 9. |
¡spherical bowl of diarneter 7-2 cm isfilled completely with chocolate sauce. Thissauce is poured into an inverted cone of radius8 cm. Find the height of the cone if it is[201014.completely filled. |
|
Answer» volume of hemisphere = (2/3)*pi (7.2/2)^3volume of cone = (1/3)*pi (4.8)^2 (h) h = 4.05 cm. |
|
| 10. |
c) Mention two classes of Bryophyta with one example for each. |
|
Answer» the two classes of bryophyta are liverworts and mosses.Example of liverworts is marchantia polymorpha and one example of mosses is spaghnalles. |
|
| 11. |
Thesumoffirst8 terms of an A.P. is 100 and the sum of its first 19 terms is 551. Find the A.P24. The largest sphere is to be curved out of a right circular cylinder of radius 7 cm and height4 cm. Find the volume of the sphere.Or |
| Answer» | |
| 12. |
A shopkeeper sold a mixer costing 5000 to aconsumer giving him 5% discount. What is thetaxable value of the mixer? |
|
Answer» Selling Price = 5000Discount = 5%Taxable Value = 5000 - 5000x5% = 5000-250 =4750 |
|
| 13. |
55. What should be the printed price of an article costing:4000, so that there10% profit even after giving 12% discount on the printed price? |
|
Answer» Let printed price be PCP = 4000SP = 4000 + 4000x10/100SP = 4400 SP = P - Px12/1004400 = Px 88/100P= 5000Marked price is RS 5000 |
|
| 14. |
A retailer buys 40 pens at the marked price of 36 pens from a wholesaler.If he sells these pens giving a discount of 1%, what is the profit percent? |
|
Answer» Let marked price of 1 pen = MPThen marked price of 36 pens = 36*MP For retailer cost price of 40 pens = 36 please give full details |
|
| 15. |
7. A and B together can do a piece of work in 12days, while B alone, can finish it in 30 days. In howmany days can A alone finish the work |
| Answer» | |
| 16. |
15. A and B together can finish a piece ofwork in 12 days. If 'A' alone can fin-ish the same work in 20 days, in howmany days B alone can finish it? |
| Answer» | |
| 17. |
there areten classes. Each class has four sections and each sectiohool,umber of students. If altogether there are 1600 students in the schoolany students are there in each section of a class?04 WORKBOOK (Mathematics Class-V) |
|
Answer» 10 classeseach class has 4 sections totally 10×4=40 sections40 sections has 1600 students 1 section has 1600/40=40students so each section has 40 students |
|
| 18. |
Out of 200 students from a school, 135 like Kabboddi and the tendo not like the game. If one student is selected at random from all thethe probability thot the student selected dosen't like Kabboddi.14. |
|
Answer» Probability = possible outcomes / total outcomes Total students = 200Students like Kabbaddi = 135 Then,Students don't like Kabaddi= 200 - 135 = 65 Probability of student selected at random don't like Kabbaddi= 65/200 = 13/40 |
|
| 19. |
mer of students in the class.22.) One says, "give me hundred, friend! I shall then become twice as rich as you" Therareplies. "If you give me ten, I shall be six times as rich as you". Tell me whatamount of their respective capital?INCER |
| Answer» | |
| 20. |
EXERCISE 3.11. Find the range of heights of any ten students of your class.2. Organise the following marks in a class assessment, in a tabular form.4,6,7. 5. 3.5. 4.5. 2, 6, 2, 5, 1,9,6, 5, 8, 4, 6,70 Which number is the highest?(11) Which number is the lowest?(mi) What is the range of the data? (iv) Find the arithmetic mean.3. Find the mean of the first five whole numbers.4. A cricketer scores the following runs in eight innings:Find the mean score.58, 76, 40, 35, 46, 45, 0, 100. |
| Answer» | |
| 21. |
find the volume of the largest cylinder forced when a rectangular plain of paper 22 cm by 15 cm is rolled along its longer side. |
| Answer» | |
| 22. |
Factorise5(Ăź) x3-3x2-9x-(iv) 2y3 + y-2y-1ăŚa CCn w |
|
Answer» please like my answer if you find it useful |
|
| 23. |
^ { 2 } 57 ^ { \circ } - \operatorname { tan } ^ { 2 } 33 ^ { \circ } + \operatorname { cos } 44 ^ { \circ } \cdot \operatorname { cosec } 46 ^ { \circ } - \sqrt { 2 } \operatorname { cos } 45 ^ { \circ } - \operatorname { tan } ^ { 2 } 60 ^ { \circ } |
| Answer» | |
| 24. |
क) के T Ny 4 हक ्९ में, जिसका कोण (0 समकोण है, 2 + (0 > 25 सेमी और 0 =5Rlsin P, cos P 3R tan P % T ज्ञात कीजिए। |
| Answer» | |
| 25. |
20, 7% tan (o +B) नि और (का एन fi-i—l a4 tan p =1 1 7 & % W |
| Answer» | |
| 26. |
33. मान ज्ञात कीजिए --(4-6) -५-2) |-6|18-935 |
|
Answer» -(4 - 6)^2 - 3(-2) + |-6|/ 18 - 9 ÷ 3 * 5 = - (-2)^2 + 6 + 6/ 18 - 3*5 = - (4) + 12/ 18 - 15 = 8/3 |
|
| 27. |
factorisen? +33 4 +6. |
| Answer» | |
| 28. |
17. 6 13 2 33 46 )(a) 6(a) eo(b) 6t(c) 65 |
| Answer» | |
| 29. |
6 i ^ { 50 } + 5 i ^ { 33 } - 2 i ^ { 15 } + 6 i ^ { 48 } = 7 i |
| Answer» | |
| 30. |
33(3-65/ (5Ifthen x is equal to |
|
Answer» 3-6=2x-1-3=2x-1 -2=2x x=-1 So, the value of x is -1. |
|
| 31. |
(1:taruH는たtained28. Prove that:OR |
|
Answer» L.H.S1+tan^2A/1+cot^2A=(1+sin^2A/cos2A)/(1+cos^2A/sin^2A)=((cos^2A+sin^2A)/cos^2A)/(sin^2A+cos^2A)/sin^2A=(1/cos^2A)/(1/sin^2A)=1/cos^2A*sin^2A/1=sin^2A/cos^2A=tan^2A M.H.S(1-tanA/1-cotA)^2=(1+tan^2A-2tanA)/(1+cot^2-2cotA)=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)=(sec^2A-2*sinA/cos A)/(cosec^2A-2cosA/sinA)=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)=sin^2A/cos^2A=tan^2A R.H.S=tan^2A Hence L.H.S=M.H.S=R.H.S |
|
| 32. |
A ribbon of length 0.8 metres is divided into 16 equal parts what is the length of each part ? |
| Answer» | |
| 33. |
m) Find the area ofmind the area of the rectanele with length equal to 7 m and breadth equa3.5 m |
|
Answer» Area of rect l×b3.5×7=24.5 |
|
| 34. |
\left| \begin{array} { c c c } { 13 } & { 16 } & { 19 } \\ { 14 } & { 17 } & { 20 } \\ { 15 } & { 18 } & { 21 } \end{array} \right| |
|
Answer» 👋 |
|
| 35. |
-11-1-33 का मान होगा |
|
Answer» (9/8)+(13/7)+(18/5)(9x7x5+13x8x5+18x7x8)/(8x7x5)answer 5.23 9/8+13/7+18/5=315+520+1008/280=1843/280= 6•58 6.58 is the correct answer of the given question 5.23 is d answer of this question the correct answer is 1843/280 |
|
| 36. |
6-(33-11/12)= |
|
Answer» =6-(33-11/12)=6-(396-11/12)=6-385/12=-313/12 -313\12 is the right answer 6-(33-11/12) =6-(396-11/12) =6-385/12 =-313/12 = -26.0833 -325/12 is the right answer |
|
| 37. |
ě equalsThe anti derivative of Vx + |
| Answer» | |
| 38. |
1.8VFind1) The equivalent resistance of the circuit |
| Answer» | |
| 39. |
If the mean of the following data is 17.45, find the value of P.x, 15 16 17 18 19 20 |
| Answer» | |
| 40. |
7683 + 3122 + 3102 |
|
Answer» 13907 this is the answee |
|
| 41. |
नानक,O Sv-4ye8=0T By 9-0 |
|
Answer» 5x-4y+8=0 be equation 1st 7x+6y-9=0 be equation 2nd solve these two equations to find the intersection point of these two equation 5x-4y=-8be equation 1st 7x+6y=9 be equation 2nd multiply 1st equation by 3 and multilply 2ndequation by 2 to get the coefficient of y equal using elimination method to solve x and y 5x(3)-4y(3) = -8×37x(2)+6y(2) = 9×2 15x-12y=-24 equation 3rd 14x+12y=18 equation 4th add these two equation 15x+14x-12y+12y=-24+18 29x=-6 x=-6/29 substitute x=-6/29 equation 1st 5x-4y=-8 5(-6/29)+-4y=-8 4y=(30/29)-8 4y=(30-29×8)/29 4y=-202/29 2y=-101/29 y=-101/58 we get the value of x and y now on representing these two line on graph i putthese two lines intersect at point p point p is (-6/29,-101/58) Like my answer if you find it useful! |
|
| 42. |
0 & 21002दस #प कर श्र |
| Answer» | |
| 43. |
Q. 79If the perimeter of regular polygon of n sides is equal toperimeter of a circle then the ratio of their areas1) OTan":Ann210 comme元_n元_n_n |
|
Answer» options 2 option 3 is the right answer. |
|
| 44. |
रस्म भा: - J Syt किमी कचि ; |SV A MGt B |
| Answer» | |
| 45. |
(ii) 2x? +7x+5^2 = 0+7 X +SV 2 |
|
Answer» x= -2 , x= -5/√2 is the correct answer of the given question X=-2 ORx=-5/root 2 is the correct answer to it √2x^2+7x+5√2=0√2x^2+2x+5x+5√2=0√2x(x+√2)+5(x+√2)=0(x+√2)(√2x+5)=0either x+√2=0, x= -√2or √2x+5=0, √2x= -5, x= -5√2= -5√2/2 dowjvdoanwjaowbqosbwkqos -5√2/2 is the right answer |
|
| 46. |
LEVEL-274 Find the value of p, if the mean of the following distribution is 20.2: 151719 20+ p 2345p |
|
Answer» Calculation of Mean xififixi15230173511947620 +p5p20+p20+p5p236138Total∑fi∑fi= 15 +5p∑fixi∑fixi= 295 +20+p20+p5pWe have: ∑fi∑fi= 15 +5p,∑fixi∑fixi=295 +(20 +p)5p. ∴Mean =∑fixi∑fi∑fixi∑fi 20=295+(20+p)5p15+5p⇒20×(15+5p)=295+(20+p)5p⇒300+100p=295+100p+5p20=295+(20+p)5p15+5p⇒20×(15+5p)=295+(20+p)5p⇒300+100p=295+100p+5p ⇒300-295+100p-100p=5p2⇒5=5p2⇒p2=1⇒p=1. Answer to p = 1. hoga kya hoga Answer batoo |
|
| 47. |
21. Which term of the A.P.4,9, 14, 19,...... is 10921.1462. 18th.22004. 160 |
|
Answer» Given:a=4d=9-4=5 an=109Formula an=a+(n-1)d 109=4+(n-1)5105=5n-5110=5nn=110/5n=22Therefore the 22nd term is 109 |
|
| 48. |
g (N oL LT/कर2 ली एड हद न i b मापा शमी 7 |
|
Answer» किसी बहुभुज के बाह्य कोणों का योग 360 अंश होता है |
|
| 49. |
13,(४) निम्नलिखित समकोण त्रिभुजों में कोण 4 और (7 के मान बताएँ।(i) % (“A)कलg N eyB A C 13w B |
|
Answer» i)sin A = BC /ACsin A = 3/6 = 1/2sin A = sin (30°)So A = 30° ii) tan A = AB/BCtan A = √3/1tan A = tan (60°)A = 60° |
|
| 50. |
oA 6८ शी 1500 becomes & BE2S 4tk 2 jrons:T Jincd the Kot of iutenesd:N ¢ B |
| Answer» | |