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23. Which term of the AP 3, 14, 25, 36, willbe 99 more than its 25th term?[CBSE 2011]

Answer»

In this AP,a=3 d=14-3=11 tn=a+(n-1)dt25=3+(25-1)11t25=3+24(11)t25=267 tn=t25+99tn=267+99 tn=366 3+(n-1)11=366(n-1)11=363n-1=33 n=34



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