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LEVEL-274 Find the value of p, if the mean of the following distribution is 20.2: 151719 20+ p 2345p

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Calculation of Mean

xififixi15230173511947620 +p5p20+p20+p5p236138Total∑fi∑fi= 15 +5p∑fixi∑fixi= 295 +20+p20+p5pWe have:

∑fi∑fi= 15 +5p,​∑fixi∑fixi=295 +(20 +p)5p​.

∴Mean =∑fixi∑fi∑fixi∑fi

20=295+(20+p)5p15+5p⇒20×(15+5p)=295+(20+p)5p⇒300+100p=295+100p+5p20=295+(20+p)5p15+5p⇒20×(15+5p)=295+(20+p)5p⇒300+100p=295+100p+5p

⇒300-295+100p-100p=5p2⇒5=5p2⇒p2=1⇒p=1.

Answer to p = 1. hoga

kya hoga Answer batoo



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