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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
LUULDWrite all prime numbers between 50 and 100.100 having no primen |
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Answer» 53, 59, 61, 67, 71, 73, 79, 83, 89, 97are the prime numbers between 50 and 100. Prime numbers between 50 to 100 are 53,59,61,67,71,73,79,83,89,97 53, 59, 61, 67, 71, 73, 79, 83, 89, 97are the prime numbers between 50 and 100. |
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| 2. |
Find the (HCF x LCM) for the numbers 100 and 190 |
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Answer» HCF = Factors of 100 = 1,2,4,5,10,20,25,50,100 Factors of 190 = 1,2,5,10,19,38,95,190 Thus, the HCF is 10. LCM = Prime factors of 100 = 2 × 2 × 5 × 5 Prime factors of 190 = 2 × 5 × 19 Thus LCM = 2 × 2 × 5 × 5 × 19 = 1900 LCMxHCF=1900*10=19000 |
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| 3. |
P. =% 126, S.P. =% 94.50 |
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| 4. |
C.P. =% 126, S.P. =% 94.50 |
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Answer» CP = 126 SP = 94.50 CP > SP PERCENTAGE LOSS = (126-94.5)*100/126 = 31.5*100/126 = 25% |
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| 5. |
Exercise 10.7. Find the HCF by Prime factoria. 48, 24 |
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Answer» 48=2×2×2×2×324=2×2×2×3 HCF=2×2×2×3=24 |
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| 6. |
15. The sum of two numbers is 48 and lell plou16. If (a, b) is the mid-point of the line segment joining the points A(10, - 6), Bk 4a -2b 18, find the value of k and the distance AB.Or |
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| 7. |
3. Find the prime factorisation of-a. 24 |
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Answer» correct answer |
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| 8. |
If (a, b) is the mid-point of the line segment joining the points A(10,- 6) and Bk, 4) anda- 2b 18, find the value of k and the distance between AB |
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| 9. |
8x3Bk ..4 = 13 |
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| 10. |
Three equal circles, each of radius 2 cm touch one anobeFind the area enclosed in between them |
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| 11. |
7. Four equal circles, each of radius 5 cm,touch each other, as shown in the figure.Find the area included between them.Take 3.14.] |
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Answer» area included between them = area of square - (4× area of one quadrant)100-(π×25)100-25π21.5 |
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| 12. |
Three congruent circles with centres A, B and C and radius 10 cm each touch each otherexternally as shown in the figure. Find the radius of the shaded region.(3 1.73, Tt 3.14) |
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| 13. |
Three equal circles, each of radius 6 cm,touch one another as shown in the figure.Find the area enclosed between them(Takeπ= 3.14 and √3=1.732] |
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| 14. |
(x+2) (x-4) use algebric identities solve |
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Answer» (x+a)(x+b)=x2+(a+b)x+abput this identity then you will get the answer x2 -2x-8 X²+(a+b)x+ab =x²+(2-4)x+2×4=x²+6x+8 X2 - 2x - 8 is rightMay this help you x² -4x +2x -8x² -2x -8 is correct answer |
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| 15. |
Solve algebric expressions4 + 8m + 10m - 4 - 7 + m |
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Answer» 8m+10m+m+4-4-7 = 19m-7 |
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| 16. |
237 Two circles of radius 4cms and 3cms touch each other. Distance between theircentre will be(a) 7 Cms (b) 7 Cms or 1 Cm (c) 1Cm |
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Answer» (b) 7cm or 1cmIf two circles touch internally then the distance between their centres is equal to the difference of their radii.4 - 3 = 1cmIf two circles touch externally then the distance between their centres is equal to the sum of their radii.4 + 3 = 7cmTherefore either 7cm or 1cm. thanku |
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| 17. |
1. Find the [HCE LCM] for the numbers 100 and 190 |
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Answer» HCF×LCM=multiplication of two numbers =100×190=19000 |
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| 18. |
Find the ratio of surface areaand volume of the sphere ofunit radius |
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| 19. |
126 withoutleavine,ind the greatest number that will divide each of 90, 108 andremainder |
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Answer» Find the HCF of 90, 108 and 126. 90 = 2x3x3x5 108 = 2x2x3x3x3 126 = 2x3x3x7 HCF = 2x3x3 Thus 18 is the greatest number that can divide 90, 108 and 126 without leaving a remainder |
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| 20. |
The product of two numbers is 360. Their LCM is 60. Find the HCE. |
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Answer» The relation between LCM and HCF of two numbers a and b is=LCM(a,b)=a×b/HCF(a,b).∴HCF=360/60=6 it is wrong |
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| 21. |
EXAMPLE 13 Find k so that y* + 2x + k is a factor of 2x + x - 14x² + 5x + 6. Also, find allthe zeroes of the two polynomials.INCERT EXEMPLAR] |
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| 22. |
AFind HCEby prime24.& LCM offactorizationthe following nomethod : 12 18 & |
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Answer» 12=2*2*318=2*3*324=2*2*2*3 HCF 6LCM 144 lcm is 72 , had is 6 12=2*2*318=2*3*324=2*2*2*3*HCF=6LCM=144 12=(2)*2*(3) 18=(2)*3*(3) 24=(2)*2*2*(3) HCF=2*3=6 LCM=HCF*2*3*2*2 = 6*24 =144 |
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| 23. |
6. If (a, b) is the mid-point of the line segment joining the points A (10,- 6), Bk 42- 25 = 18, find the value of k and the distance AB.INCERT EXEMPLAR29. Fu |
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Answer» Given,(a,b) is the midpoint of the a(10,-6) and b(k,4).a-2b=16.we know that, Midpoint = (x1+x2/2), (y1+y2/2)(a,b)=(10+k/2),(-6+4/2)(a,b)=(10+k/2),(-2/2)(a,b)=(10+k/2),(-1)by comparing on both sidesa=10+k/2 , b=-1we know that,a-2b=16=> 10+k/2 -2(-1)=16=> 10+k/2+2=16=>10+k/2=14=>10+k=28=>k=18 |
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| 24. |
2),Q(-2,-a square ABCD) Name the type of triangle PQR formed by the points P(V2,INCERT EXEMPLARand R(-V6, 6)1 An |
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| 25. |
76. An icecream cone full of icecream having radius 5 cm and height 10 cm as shown inFig. 14.77. Calculate the volume of icecream, provided that its 1/6 part is leftINCERT EXEMPLAR]unfilled with icecream.5 cm10 cmFig. 14.77 |
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Answer» Please like the solution 👍 ✔️ |
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| 26. |
INCERT Exemplarle population of a town was decreasing every year due to migration, poverty and unemployment.he present population of the town is 6,31,680. Last year the migration was 4% and the yearINCERT Exemplar]Prce oltrhe article14. Thbefore last, it was 6%. What was the population two years ago? |
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| 27. |
B 1020 लेगा 11594 की HCE 3 |
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Answer» माना |
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| 28. |
Formulaanabe rumberRaliomal mumberAlgebric cpconfraction-laat Torahonal numberwhole numberconsective Numble.Natural numberBLinearDegreePolyanimalpolyonima). |
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Answer» you which class I don't know your question I don't understand your hand writing |
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| 29. |
Find the greatest number that divides 280 and 490 without leaving any remainder |
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| 30. |
6. Find the greatest number which divided 105 and 180 without leaving anyremainder. |
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Answer» ans me Hcf of 105and180=15 then the answer is 15 |
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| 31. |
. Find the smallest number that can be divided by14 and 15 without leaving any remainder. |
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Answer» The smallest number that can be divided by 13, 14 and 15 is LCM of these numbers Prime Factors of given numbers 13 = 1*1314 = 2*715 = 3*5 Smallest number is 13*14*15= 2730 somthing i cant understand |
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| 32. |
Find the HCE of 39142 |
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Answer» Thanks 🙏 Thanks 🙏 |
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| 33. |
2. Find the greatest number that will divide each of 90, 108 and 126 without leaving aremainder |
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Answer» Find the HCF of 90, 108 and 126. 90 = 2x3x3x5 108 = 2x2x3x3x3 126 = 2x3x3x7 HCF = 2x3x3 Thus 18 is the greatest number that can divide 90, 108 and 126 without leaving a remainder. |
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| 34. |
The length of a hall is 18 m and its width is13.5 m. Find the least number of square tileseach of side 25 cm, required to cover the floorof the hall,(i) without leaving any margin.(ii) leaving a margin of width 1.5 m allaround. |
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Answer» 1. Without leaving any margin: Length of the Hall = 18 Mtrs = 1800 cms. Width of the Hall = 13.5 Mtrs = 1350 cms. Area of the Hall = Length x Width = 1800 x 1350 = 2430000 Sqr. Cm. Area of the squre tiles = Side x Side = 25 x 25 = 625 Sqr. cm. So the no. of tiles required = 2430000/625 = 3888 Nos. So cost of the tiles = Rs. 6 x 3888 = Rs. 23328. Ans: 1: 3888 Tiles and Rs. 23328. 2. Leaving a margin of 1.5 Mtrs all around: Actual length of the Hall after leaving a margin = 18 - 2 x 1.5 = 18 - 3 = 15 Mtrs = 1500 cms. Actual width of the Hall after leaving a margin = 13.5 - 2 x 1.5 = 13.5 - 3 = 10.5 Mtrs = 1050 cms. Area of the Hall = Length x Width = 1500 x 1050 = 1575000 Sqr. Mtrs. Area of the tile = 25 x 25 = 625 Sqr. Cms. So the no. of tiles required = 1575000 / 625 = 2520 Nos. So cost of the tiles = Rs. 6 x 2520 = Rs. 15120. Ans: 2: 2520 Tiles and Rs. 15120. |
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| 35. |
aFind the HCE OF 20, 28,60? |
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Answer» The factors of 20 are: 1, 2,4, 5, 10, 20 The factors of 28 are: 1, 2,4, 7, 14, 28 The factors of 60 are: 1, 2, 3,4, 5, 6, 10, 12, 15, 20, 30, 60 Then the greatest common factor is 4 factor of 20 are 1,2,4,5710,20 so hfc = 4 is the answer |
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| 36. |
3. Find the rate of discount when(i) M.Р = Rs 300 and S.P = Rs 240 |
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Answer» Discount=300-240=60 D%=60\300×100D%=20% |
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| 37. |
Given the following subbactionwhich at theproblem find outono. does not stand forCARTHO22) - means Xx means t |
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Answer» 7 5 3 - 5 3 1/ 2 2 2// C=7, A=5 R=3, T=1; |
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| 38. |
111. The interest on Rs.300 for 3 years is Rs.27. The rate of simple interest isA. 3%B. 10%C. 243%D. 5% |
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Answer» the correct answer is A.3% 3% is the 💯% correct answer option, a 3% is the right answer A) is the correct answer opt (a) is a correct answer a is the right answer |
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| 39. |
thetwicFind the measure of all the angles of a parallelogram, if one angle is 24° less thanofthe smallest angle. |
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| 40. |
Find the measure of eacn angie or the parallelogram.the measure of all the angles of a parallelogram, if one angle is 24° less than the twiceofthe smallest angle. |
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| 41. |
16. If 'x' means 'รท' and '--' means 'X', then42+7x5+10-2 |
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Answer» 42*7÷5+10*2= 78.8 please like the solution 👍 ✔️ |
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| 42. |
weighs 9 gramsow many cubes each ot edge7 A cardboard carton iscm5 cm can be placed inside this carton to fill it?2 Tho house covers an area of 140 m2. The050 |
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Answer» volume of cardboard carton=60×30×30cm^3=54000cm^3volume of cube=5×5×5cm^3=125cm^3number of cubes=54000/125=432 |
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| 43. |
That means the required number is 18 more than the L.C.M.nquired number = 360 +18= 378Exercise 4.5(v) 35 and 1091. Using prime factorisation, find the LCM of:20,35 ( 42.86 (l) 12,30,81(v) 220, 440,(iv) 120,502. Find the LCM of the following by inspection :4 and 16 (1) 7 and 28 (ii) 24 and 72 (iv) 36 and 72 (v) 35 an3. Find the LCM of the following by inspection :2x3 and 3 x 2 ) 2x 3 x 5 and 2 x 34. Using the common division method, find the LCM. of:(iii) 22 x 7 x 5' and( 54,81(iii) 224, 280, 336*5 and 2 x 7'() 117, 221Find the greatest -digit number which is eactly divisible by 12, 16, 20 and 24.Find the least digit number which on dividing by 6, 9, 12 and 18 leaves a remau&emainder 31. Find the smallest number acuy divisible by 12,20,24 and 32Find the smallest number wuch divided by 15, 20 and 51and 25 leaves a remainder 5 inein each orProperties and Relationship of H.C.F. and L.C.M.rally observed the following properties while doing prevtibet is to greater than any of the numbers.numbers is not less than any of the numbers.doing previous exerciseYou would have maturally observed the following1. The HC.F. of given number is tot greater tha2 The LCM of given numbers is not less than3. HCF. of two co-prime taumbers is 1.LCM of two or more come trumbersli a number is a factor the HCHCF of two numbers is always a fa7. The product of HC andThe HCFXLCMThe LCM and HCF.then find the second thumbco primetimes is the productof aand bis d and their LCM isis always a factor of thew.CMand two wambers is equal to the produAxleb er Second rumberHCE. Tambers are 180 and 6 respecthuice product of the nunnumbersFirst number SecondSecondorespectively. If first52NN-XLC6180 |
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Answer» exercise 4.5answer 7 find the smallest number exactly divisible by....... is 2 |
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| 44. |
2)Farm thecontrom s ro |
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Answer» x²-2x-45=0 is the right answer sum of root=1-3√5+1+3√5= 2product of root=(1-3√5)(1+3√5){(a+b)(a-b)=a^2-b^2}(1)^2-(3√5)^2=1-9×5= -44so quadratic equation=x^2-(sum of root)x + product of root=0x^2-(2)x+(-44)=0x^2-2x+44=0 |
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| 45. |
2) If 't Means'xMeansX Means-+ Means't then that will be value16:64-1412 - 1 |
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Answer» 16+64/8-4*216+8-816 The answer for this question is 2 16 is the most correct ans 16+64/8-4*2=16+8-4*2=16+8-8=24-8=16 May this answer helps you 😊 16 is the correct answer |
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| 46. |
The ratio of cost of bottle and lunch box are 13:7.The coast of bottle is Rs 300 more tha the cost of lunch box .what is the cost of lunch box. |
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Answer» Let cost of bottle be 13x and cost of lunch box be 7x Then,13x = 7x + 30013x - 7x = 3006x = 300x = 300/6 = 50 Cost of the lunch box = 7*50 = Rs 350 |
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| 47. |
0GF,295+ ०0६09 न 509, UIS € + oST, U T :PRASSFIISH 06,300 — 9IS € + S UL T पु धन्य 2६. शा| [abllele] D9gV7 =0Vd/ |
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Answer» Tan45=1sin60=√3/2cot30=√3sec45=√2hencetan^245+3sin^260-cot^230+sec^2451+3*3/4-3+21+9/4-19/4 |
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| 48. |
Is the following number rational or irrational? |
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Answer» irrational no. is the right answer plz accept as best No, π is not arational number. Hence,2πis not. Only 7, and multiples of 7 can giverational numbers. π is anirrational number,i.e it is non repeating but also never ending decimalnumber. We know that the number π is irrational. So, -2π is also irrational. it is irrational number. Basically.pi is an irrational no. We can't predict its correct value so if we multiply anything with any sign to it we will get an irrational no. So that's my answer 😊 |
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| 49. |
Is the following number rational or irrational?0.692 |
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Answer» rational no. is the right answer. Alternatively, anirrational numberis anynumberthat is notrational. It is anumberthat cannot be written as a ratio of two integers (or cannot be expressed as a fraction). For example, the square root of 2 is anirrational numberbecause it cannot be written as a ratio of two integers. rational no. is the right answer The correct answer of this question rational no 0.692 can writte in the form of p/q so the no is rational no It is rational. It can be expressed in the form of p/q, where p and q have no common factors other than 1 and q≠0. 0.692 is a rational numberbecause it not repeating number again and again it is a rational number since it has an end |
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| 50. |
A train 400m long is travelling at the speed of 72km/h how will it take to cross a telephone pole ? |
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Answer» The train is 400 m long and speed is 72 km/h so require time for cross a telephone pole 400×3600/(72000) = 20 seconds |
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