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2. Find the greatest number that will divide each of 90, 108 and 126 without leaving aremainder |
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Answer» Find the HCF of 90, 108 and 126. 90 = 2x3x3x5 108 = 2x2x3x3x3 126 = 2x3x3x7 HCF = 2x3x3 Thus 18 is the greatest number that can divide 90, 108 and 126 without leaving a remainder. |
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