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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
8. In a circle of diameter 40 cm, a rhombus is inscribed with all its vertices on the circle.Findthearcs of the rhombus. |
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Answer» When a rhombus is inscribed with all its vertices than its diagonals will be the diameter of the circlelength of the diagonal= 40cmarea of rhombus = 1/2 x diagonals²= 1/2 x 40 x 40= 800 cm² hit like if you find it useful |
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| 2. |
-14*y^2 %2B 5*x^2 %2B 33*(x*y) |
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| 3. |
(-4)/33 %2B (-3)/((-11)) |
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Answer» the right answer is 0.15 |
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| 4. |
\frac \operatorname cos 70 ^ \circ \operatorname sin 20 ^ \circ %2B \operatorname cos 57 ^ 0 \operatorname cosec 33 ^ \circ - 2 \operatorname cos 60 ^ \circ |
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Answer» Like if you find it useful |
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| 5. |
(1) Draw a circle of suitable radius. Take point T on it. Draw a tangent throughpoint T.(2) Find the slope of the line passing through given points G(3,7) and K(-2, -3).(3) Prove that : cosec A-cot A=COS AV1cos A |
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Answer» Crop to your needed questions only single questions will be answered once |
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| 6. |
-5 %2B 2 %2B 3 %2B 5/34 |
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Answer» Apka ans hai 0.02895507 0.02 is the correct answer 0.0289855072 is the correct ans 0•0289 is the right answer. plz like my answer 0.289 is the correct answer 0.028985507 is the correct answer The right ans is 0.029 |
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| 7. |
In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length ofminor arc of the chord. |
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Answer» thanks |
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| 8. |
3*x %2B 5=-10*x %2B 34 |
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Answer» 3x + 5 = - 10 x + 343x + 10 x = 34 - 513 x = 29 x = 29 / 13hope this will help you 3x + 5 = -10x + 343x + 10x = 34 - 513x = 29x = 29/13 = 2.23 3 x + 5 = - 1 0 x + 3 43 x + 1 0 x = 3 4 - 51 3 x = 2 9x = 2 9 / 1 3= 2.230..... |
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| 9. |
ita= -) and B = [ -) ind 34-28if A =and B =دیاfind 3A-2B |
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Answer» ............................. 3A-2B=[-7 6] |7 -4| mene upload kiya h community me my question the length of a rectangular garden is twice it's breadth if perimeter is 36m find it length and breadth 3A-2b=(-7 6) (7-4) it is correct |
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| 10. |
J Multiply:स༠(34 + 5ab + 7 by (72 + 2b) |
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Answer» (3a² + 5ab + 7b²) × (7a + 2b) 21a³ + 6a²b + 35a²b + 10ab² + 49ab²+14b³ |
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| 11. |
i*i - 26 - 20 %2B 33 %2B 33 %2B 21 %2B 24 %2B 25 - 26 - 14 - 34 |
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Answer» It is a very easy ques your ans is 41 -9 is the correct answer of the given question - 9 is the correct answer of the question |
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| 12. |
2/17 %2B 5/34 |
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Answer» 5 by 34 +2 by 175+4 by 34 =9 by 34 9/34 is the correct answer 5(17)+2(34)/34(17)=85+68/578=153/578 5/34 + 2/17; 2/17 × 2/2=4/34; 5/34+4/34=9/34 5/34+2/17= 5+4/34=9/34 is the answer 9/34 is right answer of given question. 9/34 is the correct answer 9/34 is the perfect answer |
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| 13. |
R)104 +104 = |
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Answer» =104÷104(Number divided by itself is 1)=1 Hii.... 104÷104 =1=> a number divide by itself we get the answer is 1(one). so,that the answer is 1. ***thanks for asking these question... |
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| 14. |
3. In figure 5.23, G is the point of concur-rence of medians of A DEF. Take pointH on ray DG such that D-G-H andDG GH, then prove that GEHF is aparallelogram. |
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Answer» Proving that GEFH is a parallelogram. |
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| 15. |
What is meant by power of a lens? Write its SI unit. A student uses a lensof focal length 40 cm and another of 20 cm. Write the nature and pewer ofeach lens. |
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Answer» The degree of convergence or divergence of a lens is expressed as power of the lens. It is the reciprocal of the focal length of the lens taken in metres. Its S.I. unit is Dioptre( D ). 1 Dioptre is defined as the power of a lens whose focal length is 1 m. Student A:40cmp=1/fp=1/0.4 (40cm=40/100m)p=1x10/4p=+2.5Dconverging or convex lens.Student B:f=20cmP=1/fp=1/0.2(20cm=20/100)p=1x10/2p=5Dconverging or convex lens |
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| 16. |
ona are two students of class-9. Together they contributed 100 towards theold age home to help the old persons.() Write a linear equation which satisfies the given data and draw the graph.(a) What values are depicted in their plan? |
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| 17. |
Rs. 4000 at the rate of 5% for 2 years. |
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Answer» Principal =Rs.4000Rate=5percentTime=2 years simple interest=Principal×rate×time/100=4000×5×2/100=Rs.40is the ryt answer PRT/1004000×5×2/100₹400 400 is the ryt answer by mistake I have written 40 Atq-S.I=PRT/100 =4000×5×2/100 =400 this is very easy question theanswer is 400 |
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| 18. |
(ii) The length of a chord is 16 cm of a circle of diameter 20 cm. Find the perpendicular distance ofthis chord from the centre of the circle |
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| 19. |
Find the compound interest ofき256 in one year at 121% per annum, when the interest iscompounded half yearly |
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Answer» 33 |
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| 20. |
15. Find the compound interest on 1000 at the rate of 8% per annum foryears when interest is compounded half yearly. |
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Answer» a sum taken for 1.5 years at 8 per annum compounded half yearly |
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| 21. |
Find the amount and the compound interest oncompounded half-yearly.31250 for 12 years at 8% per annum. |
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Answer» 3/2 years = 18 monthsTime = 3 as we are taking half yearly31250(1+8/100)power331250×27/25×27/25×27/2539366=39366-31250=8116 wrong answer hai 39152 |
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| 22. |
Find the compound interest and the amounton Rs 4000 at 4% per annum for 1 year, wheninterest is compounded half-yearly. |
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| 23. |
Find the principal that will yield an interest or 60 in5 years at 4% per annum.10. |
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| 24. |
20. In how many years will 900 yield aninterest of 180 at the rate of 5% perannum? |
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| 25. |
ExompleCalculate the following.a. What principal will yield the, simpleinterest 616 in 4 years at 5 % perannum? |
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Answer» S.I = P*R*T/100 = (P*5.5*4)/100 => 616 = 22P/100=> P = 61600/22 = 2800rs |
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| 26. |
7. In what time will 10,000 amount to11,025 at 10% per annum compoundinterest compounded half yearly. |
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Answer» P=10000,A=11025,R=10%per annumR=5%half yearlyTime =nNow explanation is in the above pic.please like the solution 👍 ✔️ |
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| 27. |
What sum will yield Rs. 1716 as S.I. in 2^3/4 years at 10% pa. ? |
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| 28. |
K) What sum of money will amount to5,445 in 2 years at 10% per annumcompound interest? |
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| 29. |
(2)Write five solutions of the equation x + y7. |
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| 30. |
23 lo be addeol to fous tmes aNu ,aber, theDbe_Cvtainăesult.dsLea than tive times the nunkerFind the Nluimbes |
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Answer» thanks |
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| 31. |
5years ago a man was 7 timesas old as his son. after 5 years he will be thrice as old as his son. find their present age. |
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Answer» age of son = xage of man=7xpresent age of son=x+5present age of man =7x+5future age of son =x+10future age of man 7x+10According to question.7x+10=3(x+10)7x+10=3x+307x-3x=30-104x=20x=20/4x=5hence, present age of son = x+5=5+5=10and present age of man =7x+5=7×5+5=40. hope it help you..... |
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| 32. |
galmpeieWhat sum will yield Rs.1416 at 94% perannum after 5years?ll4:A500 amount to Rs 5400 in' |
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Answer» Total = sum(1+RT/100)1416 = sum(1+(9.5 x 5)/100)1416 = sum(1 + 0.475)sum = 960rs |
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| 33. |
16. A sum of 44,200 is divided between Johnand Smith, 12 years and 14 years oldrespectively, in such a way that if theirportions be invested at 10 percent per annumcompound interest, they will receive equalamounts on reaching 16 years of age.(1) What is the share of each out of44,200 ?(ii) What will each receive, when 16 yearsold ? |
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Answer» Let John's share be x & Smith's share be 44200-x : John's time =16 -12 = 4yrs Smith's time = 16-14 = 2yrs According to the question ; John's amount =Smith's amount x(1+(10/100))4 =(44200 -x)(1+ (10/ 100))2 x(11 /10)4 = (44200 -x) (11/10)2 x(11 /10)2 = 44200 - x 121 x / 100 = 44200 - x (121 x/ 100) + x = 44 200221 x / 100 = 44 200 221 x = 44200 * 100 221 x = 44 20 000 x = 44 20 000 / 221 x = 20 000 Hence , John's share = x = Rs 20,000 Smith's share = 44 200 - 20 000 = Rs 24200 |
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| 34. |
\frac { 81 } { 49 } \times \frac { 27 } { 196 } |
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Answer» 2187/9604=0.22 0.2277176177 this right answer of your question |
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| 35. |
\left. \begin{array} { l } { 81 \div 3 - 2 \times 0.5 } \\ { 12 \times 5 - 112 \div 2 } \\ { \text { a) } 6.5 } \end{array} \right. |
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Answer» thank u so much dear |
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| 36. |
\left. \begin{array} { l } { \text { "or } x \text { and } y : } \\ { 9 ^ { x } = 3 ^ { y - 2 } , 81 ^ { y } = 3 ^ { 2 } \times ( 27 } \end{array} \right. |
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| 37. |
:\left(\frac{81}{16}\right)^{-3 / 4} \times\left\{\left(\frac{25}{9}\right)^{-\frac{12}{2}} \div\left(\frac{5}{2}\right)^{-3}\right\} ] |
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Answer» [(81/16)⁻³/⁴×(25/9)⁻³/²]/(5/2)⁻³ =[(3⁴/2⁴)⁻³/⁴×(5²/3²)⁻³/²]/(5/2)⁻³ =[(3/2)⁻³×(5/3)⁻³]/(5/2)⁻³ =(3⁻³×5⁻³×2⁻³)/(2⁻³×3⁻³×5⁻³)=1. |
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| 38. |
5. Find the ratio of 200g to 1kg. |
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Answer» the ratio of 200g to 1 kg is 1:5 |
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| 39. |
Ali is twice as old as fatima. 5years ago Ali's 3 times Fatima's age.Find there present age |
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Answer» Ali = 2 * Fatima (Ali-5) = 3(Fatima-5) Ali - 5 = 3*Fatima - 15 2*Fatima = 3*Fatima - 10 Fatima = 10 Ali = 20 |
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| 40. |
TOUILLS UUTUU0.17 After 16 years, Fatima will be three times as old as she is now.Find her present age.ill lo 5 times as old as he was 8 years |
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| 41. |
r 16 years, Fatima will be three times as old as she is now. Find her present age. |
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| 42. |
After 16 years, Fatima will be three times as old as she is now. Find her present age. |
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| 43. |
After 16 years, Fatima will be three times as old as she is now. Find her present age. |
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| 44. |
A well of diameter 2 s dug 14 m deep. T eart aken out of it is spread evenly alaround it to form an embankment of height 40 c. Find the width of the embankment. |
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Answer» thank you thank you |
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| 45. |
A well with inner radius 4 m is dug 14 m deep. Earth taken out of it has been spreadevenly all around to a width of 3 m to form an embankment. Find the height of theembankment. |
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| 46. |
A well of diameter 3 m is dug 14 m deep. The soil taken out of it is spread evenly all around itto a width of 5 m to form an embankment. Find the height of the embankment |
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| 47. |
f ( 11 ) 9 \times 81 ^ { x } = \frac { 1 } { 27 ^ { x - 3 } } |
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Answer» 9×81^x = 1/(27)^(x-3) => 3²×3^4x = 1/3^3(x-3)=> 3^(4x+2) = 3^(9-3x) so, 4x+2 = 9-3x=> 7x = 9-2 = 7=> x = 7/7 = 1 |
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| 48. |
ORA well, of diameter 3m, is dug 14 m deep. The earth taken out of it has been spread evenlyall around it to a width of 4m, to form an embankment., Find the height of theembankment. (Use t 22/7) |
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| 49. |
20. A well with 14 m inside diameter is dug 8 m deep. The earth taken out of it has beevenly spread all around it to a width of 21 m to form an embankment. Find the heof the embankment |
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Answer» Diameter |
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| 50. |
Calculate the total surface area and lateral surface area of a cuboid with dimensions.1 -1.5 m.b-1.2 m.h 0.9 m. |
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