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1) let the edge of the cube = a cm

volume(v)= a^3

a^3 = 729

a^3 = (9cm)^3

a = 9cm

2)lateral surface area = 4 a^2= 4* 9^2= 4* 81=324cm^2

total surface area = 6a^2= 6* 9^2= 6*81=486 cm^2

let the second no. be x first no.=6x6x+x=637x=63x=63÷7x=9

let second no. is Xso first no. is 6X and total is 636x+x=637x=63x=9so first =6*9=54first no. 54, second no. 9

no if divide the exponent is subtracted

Ans :- It depends upon how you define "coldest." WithPlutoout of the race, the farthest "real" planet fromthe SunisNeptune. Neptuneand its neighbor, Uranus, are known as the "ice giants," since they are composed of huge amounts of rock and water, ammonia, and methane ice crystals.

Area of square = side*side = 16*16 = 256Area of Reactangle = Area of squareLength*Breadth = 25632*Breadth = 256Breadth = 256/32 = 8 cm

56=2(16+b)56=32+2b56-32=2b24=2bb=24/2b=12cm

Length of square = 16 cmPerimeter of Square = 4*16= 64 cmArea of square = 16*16= 256 cm^2

Let length of Reactangle be lBreadth of Reactangle = 10 cmPerimeter of Reactangle= 2(l + 10)= 2l + 20

Perimeter of Reactangle = Perimeter of Square

Hence,2l + 20 = 642l = 44l = 44/2 = 22 cm

Area of Reactangle = 22*10= 220 cm^2

Therefore,Length of Reactangle = 11 cm Square has more area.

a) 28/40 = 7/10=14/20=42/60

b) 20/28=5/7=35/49=70/98

c) 2/9=6/27=12/54=2/18

d) 15/18=5/6=20/24=25/30

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3/5 is the correct answer

3/5 and 2/4... make the denominator equal

= 3*4/5*4 and 2*5/4*5= 12/20 and 10/20

clearly 12> 10 so, 3/5 > 2/4

1 lakh * 10 = 10 lakh

10me 1 multiple karoge to 10lakh to hojayega

1×10=10 lakh righthe please like and share

100000*10=1000000meaning of this question

1*10=10 lack is answer

640 kilogram may be....

640 kilogram........

640 kilograms .

b) 640 kg is the right answer of the following

640 kilogram is correct answer

640 kilograms .

73 km 155 m + 24 km 19 m + 31 km 90 m= 128 m 264 m

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IN ||ABCDAD=9cm,CF=4cm||ABCD=AD×CF[°.°l×b] =9×4 =36.......(1)In this way,||ABCDCD=12cm,AE=??||ABCD=AE× CD =AE×12.....(2)

By (1)and(2)AE×12=36 AE=36/12 •°• AE=3cm

Total number of cards = 52Number of black face cards = 6

P(black face card) = 6/52

4 is the area ..............

...

Let the radius of the base of the cone(DB) = R

Height of the base of the cone(AD) = H

Slant height of the base of the cone(AB) = L

Again, let the radius of the base of the cone(GE) = r

Height of the base of the cone(AG) = h

Slant height of the base of the cone(AE) = l

Now, from the figure

Height of the remaining part of the cone GD = H - h

Given that the right circular cone is divided by a plane parallel to its base in two equal volumes,

So, the volume of the small cone is half of the volume of the whole cone.

=> πr2h/3 = (1/2)*πR2H/3

=> r2h = R2H/2

=> r2h/R2H = 1/2

=> r2/R2= H/2h ..............1

Again, we know that EF || BC,

So, ΔAEG ∼ ΔABD

=> GE/DB = AG/AD

=> r/R = h/H

=> (r/R)2= (h/H)2

=> r2/R2= h2/H2...........2

From equation 1, we get

H/2h = h2/H2

=> H/2h = (h/H)2

=> (1/2)*(h/H) = (h/H)2

=> 1/2 = (h/H)3

=> h/H = (1/2)1/3

=> h/H = 1/21/3

=> H = h*21/3

Now, h/(H - h) = h/(h*21/3- h)

=> h/(H - h) = h/{h(21/3- 1)}

=> h/(H - h) = 1/(21/3- 1)

=> h : (H - h) = 1 : (21/3- 1)

So, the ratio of the line segment into which the axis of the cone is divided by the plane is 1 : (21/3- 1)

(i)In a deck, there are 26 red cards(including two red kings). There are 2 red kings and 2 black kings.so total number of cards= 26+2=28so the probability of drawing a red or a king is 28/52=7/13

(ii) There are 6 face cards in red- the king, queen and jack of hearts and diamonds.So, the probability is 6/52=3/26

(iii) the probability of drawing 2 of spades is 1/52

(iv) There are two 10 cards in black suit: 10 of spades and 10 of clubs. So the probability is 2/52=1/26

(sinθ - cosθ +1 )/(sinθ +cosθ -1)

dividing numerator and denominator by cosθ

[(sinθ - cosθ +1 )cosθ]/[(sinθ +cosθ -1)/cosθ]=(tanθ -1 + secθ )/(tanθ +1 - secθ)=(tanθ + secθ -1)/(tanθ - secθ+1)

As, sec²θ- tan²θ = 1(secθ -tanθ)(secθ +tanθ) = 1

putting this in numerator,[(tanθ + secθ -(sec²θ- tan²θ)]/(tanθ - secθ+1)=[(tanθ + secθ) -(secθ- tanθ)(secθ+tanθ)]/(tanθ - secθ+1)=(tanθ+secθ)[1- (secθ - tanθ)]/(tanθ - secθ+1)=(tanθ+secθ)[1- secθ + tanθ)]/(tanθ - secθ+1)=(tanθ+secθ)

Now, multiplying and dividing by(secθ- tanθ)[(tanθ+secθ)×(secθ- tanθ)]/(secθ- tanθ)=(sec²θ- tan²θ)/(secθ- tanθ)= 1/(secθ- tanθ)=1/1/cos-sin/cos=sin+1/cos

Height of smaller cone = 5cm