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f ( 11 ) 9 \times 81 ^ { x } = \frac { 1 } { 27 ^ { x - 3 } } |
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Answer» 9×81^x = 1/(27)^(x-3) => 3²×3^4x = 1/3^3(x-3)=> 3^(4x+2) = 3^(9-3x) so, 4x+2 = 9-3x=> 7x = 9-2 = 7=> x = 7/7 = 1 |
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