Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

;= (95 - 79) : (4L + 75) "9z

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2.

A) gl चारसानां sl adlh oyfendS Al (Rivers)4l परिधि पी,Qi

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નદીઓ જેના દ્વારા તેઓ પ્રવેશે છે તે લેન્ડસ્કેપને બદલી દે છે. તેઓ તેને ધોવાણ, પરિવહન અને નિવારણ દ્વારા બદલી દે છે. નદીના ચાલતા પાણીમાંથી નદીની પથારી અને કાંઠે - ખડકો, માટી, વનસ્પતિ - નદીમાં ચાલતા પાણીનો નાશ થાય છે. આ ધોવાણની પ્રક્રિયા છે

3.

8 B) Manohar wants to gift an article packed in box on his friend's birthday.For that he bought a box of dimensions 16 × 12 × 9 cm. He wantsto wrap a coloured paper around the box. Find the area of the paperrequired to wrap the box.

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4.

Find the derivative w.r.t. x: (1).(X square+a square)/X+a. (2).(π/4 sin square)/(X square+1) (3).X cube-27 (4).X invers4(3-4x invers 5) (5).(secx-1)/(secx +1). (6){X cube cosx(π/4)}/sinx.

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Thanks mem,। Please give me other questions?

5.

2.3a +1(ख) यदि 5600+ (200 > ८, तो सिद्ध कीजिये किR R R अधिsinf =

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6.

Do youu taihk cbiekLU022141

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Mathematical brackets are symbols, such as parentheses, that are most often used to create groups or clarify the order that operations are to be done in an algebraic expression.

It is not easy to keep a track of what steps we have to follow without using brackets.Brackets allow us to solve any equation in a systemic manner and avoids any confusion about the sign associated with the number.

7.

\left[ \begin{array}{cc}{\cos \theta} & {\sin \theta} \\ {-\sin \theta} & {\cos \theta}\end{array}\right]+\sin \theta \left[ \begin{array}{cc}{\sin \theta} & {-\cos \theta} \\ {\cos \theta} & {\sin \theta}\end{array}\right.

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8.

11. In a rational number, twice the numerator is 2 more than the denominator. If 3 is added to each,the numerator and the denominator, the new fraction is 2/3. Find the original number.

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9.

\frac { \sec \theta - \tan \theta - 1 } { \sec \theta + \tan \theta - 1 } = \tan \theta - \sec \theta

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10.

\frac{2 \sin \theta \tan \theta(1-\tan \theta)+2 \sin \theta \sec ^{2} \theta}{(1+\tan \theta)^{2}}=\frac{2 \sin \theta}{1+\tan \theta}

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by putting the value of angle we can verify it as well just put theta= 0°L. H. s = R. H.S

11.

Nidhi purchased two sarees forて2,150 each. She sold one sareeatalossof8%and the other at a gain. If she had a gain of 1230 on the wholetrasadonthe selling price of the second saree

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12.

Luxmi sold two sarees forき1980 each. On one, she lost 10%, while on the other she gained10%. Find her gain or loss per cent in the whole transaction30.ther he

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But I am not sure this is correct or not

yes next method is absolutely right

13.

| 30. एक डिब्बे में 100 नीले गोले, 50 लाल गोले और 50 काले गोलेहैं। 25% नीले गोले और 50% लाल गोले निकाल लिए गए, तबकाले गोलों का प्रतिशत है।[SSC CGL 2013]

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33.33 % is right answer for this question

100 is right answer for this question

33.33% is the right answer

Nile golo ka 25% nikalne ke Baad Nile gole = 75

laal golo ka 50% nikalne ke Baad laal gole = 25

or kale gole = 50

Kul gole 75 + 25 + 50 =125

kaale golo ka pratishat = 50/150 X 100 = 33.33% kale gole

ans is 33.33% kale gole

33.33% answer hi hoga.

50/150x1005000/15033.33%

33.33% काले गोलेis the correct and right answer

ANS. 33.33% black boal are left in this case

33.33% is the best answer me

33.33% is correct answer

14.

X4l PQRSHI PQ = 7 dHl &l

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PQ=QR=RS=SP= 7 cm QS = √(48+49) = √98 = 7√2 cm

15.

Manohar purchased two handbags for Rs.750 each. Hesold these bags, gaining 6% on one and losing 4% on theother. Find his gain or loss in the whole transaction

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16.

11. MAN PDQ:: WAN:?(1) YQD(3) NAW[SSC (CGL), 2015](2) YDQ(4) ZDQ

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17.

10.The HCF and LCM of two numbers are 12 and 924respectively. Then the number of such paris is :(SSC CGL -2011]a. Ob. 1c.2d. 3

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Answer:c)2Explanation

18.

9.Write two properties of rectangle.

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Ans :- All the properties of aparallelogramapply (the ones that matter here are parallel sides, opposite sides are congruent, and diagonals bisect each other).

Allanglesare rightanglesbydefinition.

The diagonals are congruent.

19.

During a sale, a shop offered a discount of 10% on themarked prices of all the items. What would a customerhave to pay for a pair ofjeans marked at 1450 andtwo shirts marked at 850 each?

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thank u

20.

The denominator of a fraction is 1 more than tand denominator are both increased by 5, it becomeswice its numerator. If the numerator3Find the original fractionD. 5 such that their difference is 15

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suppose fraction is x/yy=2x+1now both are increased by 5so (x+5)/(2x+6)=3/55x+25=6x+18so x=7so fraction is 7/15

21.

6.During a sale, a shop offered a discount of 10% on themarked prices of all the items. What would a customerhave to pay for a pair of jeans marked at 1450 andtwo shirts marked at? 850 each?

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22.

During a sale, a shop offered a discount of 10%on the marked prices of all the items. What would acustomer have to pay for a pair of jeans marked at1450 and two shirts marked at 850 each?

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23.

During a sale, a shop offered a discount of 10% on themarked prices of all the items. What would a customerhave to pay for a pair of jeans marked at 1450two shirts marked at 850 each?and0 000 eac

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24.

transaction.6.During a sale, a shop offered a discount of 10% on themarked prices of all the items. What would a customerhave to pay for a pair of jeans marked at? 1450 andtwo shirts marked at 850 each?

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discount=10%cost of all items= 90%of marked pricecost of jeans=(1450* (90/100))=1305cost of 2 shirts= (850*2*(90/100))=1530total cost after discount= 1305+1530= 2835

25.

During a sale, a shop offered a discount of 10%on the marked prices of all the items. What would acustomer have to pay for a pair of jeans marked atRs 1450 and two shirts marked at Rs 850 each?6.

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26.

During a sale, a shop offered a discount of 10% on themarked prices of all the items. What would a customerhave to pay for a pair of jeans marked at t 1450 andtwo shirts marked at ? 850 each?6.

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27.

, weren are divisiDle uy(vi) Find the sum of natural numbers between 1 and 100, which are not divisible by s.

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thanks

dhanyabad

28.

preagesManavis wice as old as his brother Vikram. If the difference oftheir ages be 11 year, find their

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Let the Vikram age be x.

Then the age of manav will be 2x.

Given that difference in their ages be 11 years.

2x - x = 11

x = 11.

The age of manav will be 2 * 11 = 22 years.and vikram is 11 yrs

29.

Ashop gives 20% discount. What would the sale price of each of these be?(a) A dress marked at 120(c) A bag marked at250I.(b) A pair of shoes marked at750

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discount is of 20%a) so SP=120×0.8=96b) so SP=750×0.8=600c) so SP=250×0.8=200

afraid marked at ££120

30.

Q8. During a sale a shop offered a discount of 10% on the markedprices of all the itenis. What would a customer have to pay for a jeansmarked at Rs1450 and two shirts marked at Rs850 each.

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Selling price of jeans = (100-10)/100 * 1450= 9/10 * 1450= 9*145= Rs. 1305

Selling price of 1 shirt = (90/100) * 850= 9*85= Rs. 765. Selling price of 2 shirts = 765*2= Rs. 1530. Total selling price = 1305 + 1530 = Rs. 2835

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Can you please solve it with class 8th method?

31.

uyFind the HeS and 6o

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PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL.

32.

[ह xq की ) किम ¥i X Uyकवच 1है 3 श्ध्थ

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hit like if you find it useful

33.

\frac { \operatorname { sec } 2 } { \operatorname { cosec } 61 ^ { \circ } }

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34.

\frac \operatorname sin 61 ^ \circ \operatorname sin 29 ^ \circ

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35.

3, 60% students in a class of 40 students passedin mathematics with distinctions. How manystudents could not get distinction marks?

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There are 40 students.60% students passed in mathematics with distinctions, so these are 60×40/100=24 students.so remaining are 40-24=16.so 16 students could not get distinction marks.

36.

(111) о.60% students in a class of 40 students passedin mathematics with distinctions. How manystudents could not get distinction marks?

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There are 40 students.60% students passed in mathematics with distinctions, so these are 60×40/100=24 students.so remaining are 40-24=16.so 16 students could not get distinction marks.

37.

FiIn Fig. 10.39, A, B, C and D are four points on acircie. AC and BD intersect at a point E suchthat 2 BEC = 130° and ECD-20。. FindZ BAC.

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38.

If \tan \theta=\frac{a}{b}, \text { then } \frac{\cos \theta+\sin \theta}{\cos \theta-\sin \theta}=?\begin{array}{ll}{\text { (A) } \frac{\mathrm{a}+\mathrm{b}}{\mathrm{a}-\mathrm{b}}} & {\text { (B) } \frac{\mathrm{a}-\mathrm{b}}{\mathrm{a}+\mathrm{b}}} \\ {\text { (C) } \frac{\mathrm{b}+\mathrm{a}}{\mathrm{b}-\mathrm{a}}} & {\text { (D) } \frac{\mathrm{b}-\mathrm{a}}{\mathrm{b}+\mathrm{a}}}\end{array}

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39.

Cubical boxes of volume 15625 cm each are put in a cubical store of side 2.5m|How many such boxes can be put in the store?

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I not know the answer for that q+a

volume = a³=2.5³=15.625

no. of boxes= 15625/15.625=1000 boxes hope this will help you like my answer

40.

9. Stretch Your Thinking Use the graph atPet Store Animalsthe right. If the pet store had 10 more birds,the number of dogs would be double thenumber of birds. What numbers should beon the scale? Explain how you solved.Type of Pet

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Is the point P(x, y) equidistant from the point A(3,6) B(-3,4) prove that 3x + y - 5

if 19x² =100²-90² then find the value of x

scale is x:Number of pets = 1unit. y: type of pet. y: type of pet . y:

41.

5Example 2 : ABCD is a trapezium with AB II DCE and Fare points on non-parallel sides AD and BCrespectively such that EF is parallel to ABAE BF(see Fig. 6.14). Show that En FC

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join a f and b then EC and every then you will easily solve this question

AE/ED=BF/FC parallel but (lines which are parallel to some line are parallel to each other)

42.

Avangle AlC ia draws to circumsoribe e circiefnndius 4 am such that the segments BD andDC no which BC is divided by the point ofmact D are of lengths 8 om and 6 ennepetivaly (see Fig 4.14). Find the sides AE

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First join the vertices of the triangle to centre of the circlethen there became 3 triangles with perpendicular (OAB,OBC,OAC)find area of ∆ABC by heron formulathen area of three∆by 1/2b*h compare them to find value of x ,then x is 7put value and find sides

43.

|| 15. यदि 53 है, तो 1का मान ज्ञात कीजिए -a+2ba+2b

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4/3 is the ryt answer.

44.

(text*((b*y)*(7*x - 9)))*(14*x^2 - 53*x %2B 45)

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45.

how was collected from 1786students of each students contributed Rs 625

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46.

-11 - 42 %2B 53 %2B 29

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47.

11. The age of a girl in months is equal to the age ofher grandmother in years. If the differencebetween their ages is 66 years, find their ages.

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let a = the age of the girllet g = age of grandmother

:"the age of a girl in months is equal to the age of her grandmother in years"12a = g:if the differences between their ages is 66 years "g - a = 66replace g with 12a12a - a = 6611a = 66a = 66/11a = 6 yrs is the girls ageg=72 years

48.

Zarina and Shabana, two students of class IX of a school, together contributed 100towards the Prime Minister's Relief Fund to help the earthquake victims. Write alinear equation which satisfy this data and draw the graph of the same. What value isdepicted in the question ?

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49.

Yamini and Fatima, two scudents of Class IX of a school, together contributed Rs 100towards the Prime Minister's Relief Fund to help the earthquake victims. Write a mearequation which satisfies this data. CYou may take their contrybutions as Rs x andRs y.) Draw the graph of the same.

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50.

0.1The studentThe students of a class contributed some amount of moneymoney to an orphanage.student contributed as much amountcontributed as much amount as the number of students in the class.total contribution from the class is Rs 2,209, how many students were there inclass?2 473 530 57tedly

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47 is the correct answer