1.

\frac{2 \sin \theta \tan \theta(1-\tan \theta)+2 \sin \theta \sec ^{2} \theta}{(1+\tan \theta)^{2}}=\frac{2 \sin \theta}{1+\tan \theta}

Answer»

by putting the value of angle we can verify it as well just put theta= 0°L. H. s = R. H.S



Discussion

No Comment Found