If \tan \theta=\frac{a}{b}, \text { then } \frac{\cos \theta+\sin \theta}{\cos \theta-\sin \theta}=?\begin{array}{ll}{\text { (A) } \frac{\mathrm{a}+\mathrm{b}}{\mathrm{a}-\mathrm{b}}} & {\text { (B) } \frac{\mathrm{a}-\mathrm{b}}{\mathrm{a}+\mathrm{b}}} \\ {\text { (C) } \frac{\mathrm{b}+\mathrm{a}}{\mathrm{b}-\mathrm{a}}} & {\text { (D) } \frac{\mathrm{b}-\mathrm{a}}{\mathrm{b}+\mathrm{a}}}\end{array}

If \tan \theta=\frac{a}{b}, \text { then } \frac{\cos \theta+\sin \the

1.	If \tan \theta=\frac{a}{b}, \text { then } \frac{\cos \theta+\sin \theta}{\cos \theta-\sin \theta}=?\begin{array}{ll}{\text { (A) } \frac{\mathrm{a}+\mathrm{b}}{\mathrm{a}-\mathrm{b}}} & {\text { (B) } \frac{\mathrm{a}-\mathrm{b}}{\mathrm{a}+\mathrm{b}}} \\ {\text { (C) } \frac{\mathrm{b}+\mathrm{a}}{\mathrm{b}-\mathrm{a}}} & {\text { (D) } \frac{\mathrm{b}-\mathrm{a}}{\mathrm{b}+\mathrm{a}}}\end{array}
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