This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
-sqrt(x - 1) %2B sqrt(x %2B 1)=sqrt(4*x - 1) |
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Answer» b root (x+1) -root(x-1)=root(4x-1) squaring both sides, we get x+1+x-1-2root(x^2-1)=4x-1 2x-2root(x^2-1)=4x-1 -2x+1=2root(x^2-1) squaring again both sides 4x^2+1-4x=4(x^2-1) 4x^2+1-4x=4x^2-4 5=4x x= 5/4it is having only one solution show option B is the right answer thank you so much |
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| 2. |
]| हि च्ण * एल लननन लव कर परेल (लिका। t ot wolich Ha Gides (ethen Hhan . W:>i 1 fi% Y o ond Bem e Conatruck Gnothen hncuxa/ln whegkGidae कैच भेज Covre 'ए Sidkes of Ha giver - W"’O“ . |
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| 3. |
find the values of(ICSE)5 x 0 110 5x and y. |
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Answer» thanq😊😊 |
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| 4. |
-sqrt(3*x %2B 1) %2B sqrt(5*x %2B 7)=sqrt(x %2B 3) |
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| 5. |
Salve ha quadaatic cquatian |
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| 6. |
ind the Rauk of Ha Matsex |
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Answer» Rank will be 4 for this Eliminate elements in the 1st column under the 1st element 2)Swap the 2nd and the 4th rows Eliminate elements in the 3rd column under the 3rd element 4)Calculate the number of linearly independent rows |
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| 7. |
If $\sin \alpha-\cos \alpha=0$ then find the value of $\left(\sin ^{4} \alpha+\cos ^{4} \alpha\right)$ |
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Answer» sin - cos = 0sin = costan = 1 so = 45°sosin⁴ + cos⁴ = (1/√2)⁴ + (1/√2)⁴= 1/4 + 1/4 = 2/4 = 1/2 |
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| 8. |
4Ans. (A)1)The value of cos l sin-ě! is :The value of cos sinis:17 |
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| 9. |
Find the value of 3 \sin 15^{\circ}-4 \sin ^{3} 15^{\circ} - |
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Answer» sin 15 = sin(45 - 30)= sin45 cos30 - cos45 sin30= ½√2(½√3) - ½√2(½)= ¼(√6 - √2)maka3 sin15 - 4 sin³15 = 3(¼(√6 - √2)) - 4(¼(√6 - √2))³= ¾(√3√2 - √2) - (1/16)(√3√2 - √2)³= (√3 - 1)¾√2 - (3√3 - 5)¼√2 …3(√3 - 1)√2 - (3√3 - 5)√2= ------------------------------------……………….4 = ½√2 Please solve |
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| 10. |
The value of6 (sin 6 θ + cos 6 θ)-9 (4 0) + 4sin θ + cosis(a)3(c) 1(b) 0(d) 3 |
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| 11. |
İf tan θ= 4/3 then find the value of (sin θ + cos θ)/ (sin θ-cosθ) |
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| 12. |
||2यदि A=, इस प्रकार है कि A =I, तो0 |(A) 1 +0+ 3Y = [](B) 1 - 2 + 37 = 0(C) 1 -- -- 3 = 0(D) 1 + c* - 37 = 0 |
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| 13. |
Find x.1102040 460 42110 |
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Answer» 204 + 110 =314; 360-314=46 |
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| 14. |
if x^3 + 1/x^3 =110, then x+1/x |
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Answer» x^3+1/x^3=110 (x+1/x)^3=x^3+1/x^3+3(x+1/x) (x+1/x)^3=110+3 (x+1/x) Let(x+1/x)=a eq … 1 So, a^3=110+3a a^3-3a-110=0 P (a)=a^3-3a-110 PUT a=5 P (5)=(5)^3-3 (5)-110=125-15-110 125-125=0 P (5)=0 1st factor =(a-5) Write (a-5) three times and put the value according to polynomial a^2(a-5)+5a(a-5)+22(a-5) (a-5)(a^2+5a+22) If (a-5)=0 or (a^2+5a+22)=0 (a-5)=>x+1/x-5=0 from eq1 x+1/x=5 ans |
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| 15. |
Methodmit |
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Answer» 33/4 is a correct answer 33/4 is right answer Eight integer one upon two 33/2 is a correct answer mixed fraction is 8 33/4 right ans like this 33/4 is the correct answer 33/4 is correct answer. =11/2+11/4=5.5+2.75=8.25it is the correct answer aaaaaaaaaaasssaaaasss |
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| 16. |
x ^ { 3 } + \frac { 1 } { x ^ { 3 } } = 110 , \text { then } x + \frac { 1 } { x } = |
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| 17. |
M) dohod कि कर ८ ललित है e& lzu\“ NG तू ne d AO 9, n -l (2 0) (० ) |
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Answer» For the 6th term, put n=6 in the given sequence an=(n-1)(2-n)(3+n)=(6-1)(2-6)(3+6)=5*(-4)*9=-180 |
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| 18. |
हि —VS0 नि L :§ By st DU pbin] ‘Lol B (2 Dinjie 20 DiGhBER ng s |
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| 19. |
可可可币27T 큐 라,ET ,MIT,π〒 |
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| 20. |
(-37)*0-(-8) |
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Answer» 8 is the Answer (-37)×0-(-8)=0-(-8)=0+8=8 is your answer plz like thanks |
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| 21. |
20.\Delta A B C \ddot{H}, 2 R^{2} \sin A \sin B \sin Cका मान ज्ञात कीजिए। |
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Answer» धन्यवाद |
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| 22. |
f จี h f (Prove that) :I. (sin θ + cosec θ)2 #, sin2 θ + cosec2 θ + 2. |
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| 23. |
61. H sin A-cosA-0, then the valive fthen the valuesin 4 A+ cos A is(2) 14 |
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Answer» sinA - cosA = 0 ⇒ sinA = cosA ⇒ sinA/cosA = 1 ⇒ tanA = 1 ⇒ tanA = tan45° ⇒ A = 45° ∴ sin⁴A + cos⁴A = sin⁴45° + cos⁴45° = (1/√2)⁴ + (1/√2)⁴ = 1/4 + 1/4 = 2/4 = 1/2 |
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| 24. |
'थदि घ्वयद्उ द. यदि A+ B = 30—37-‘0 cos A m %!{7 8 |
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Answer» A+B= 90A= 90-BcosA= cos(90-b) = sinb |
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| 25. |
Q-1 Find the angle whose complement is equal to the angle itself. |
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| 26. |
अं. है (socfis tan B YD बाण |
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| 27. |
the sum of the digits of a two digit number is 7. If the digits are reverse the new number is increased by 3 equals to 4 times the original number |
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| 28. |
x 594 =;110 |
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Answer» 100×594/110 = 10×54 = 540 If you find this answer helpful then like it. super tq |
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| 29. |
102. 25,30 yd 60 aFind the LCM of 25,30 & 60(a) 600(c) 150(b) 240(d) 300 |
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Answer» 25 = 5×5 30 = 2×3×5 60 = 2×2×3×5 LCM = 2×2×3×5×5 = 300 |
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| 30. |
Write an integer for eachsituation.3 units to the left of Othe opposite of 815 ft above sea levela gain of 6 yd5° below zeroa deposit of $2014 steps backwardfour seconds after liftoffa loss of ten poundsone floor down19 m below sea levelthe opposite of -11 |
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Answer» -3-8156-5-20-144-10-1 |
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| 31. |
sin 0cos θ |3537tan θ |
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| 32. |
11. One of the angles forming a tinear pan12. Can two acute angles form a linear pair?rr than find its complement. |
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Answer» No, Because acuteangle measures less then 90 degrees and more then 0 degrees. so if we take the biggest acute angle and it with itself it will be less then 180 degrees. Eg:-89 + 89 = 178 |
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| 33. |
Q-2 Find the measure of an angle whose supplement is equal to the angle itsef. |
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| 34. |
A boat goes 30 kmeam and 44 km downstream int can goExample 19:ps10 hours. In 13 hours, i40 km upstream and 55 kmdown-stream. Determine the speedof the stream and that of the boat instill water |
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| 35. |
Find the angle whose complement is one-third of its supplement. |
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| 36. |
84. Prove that:SinH sin -+ sinNa |
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| 37. |
Prove that area of 4 walls is 2(l+b)×h |
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| 38. |
The digits of a three-digit number are in AP and their sum is 15. The numberobtained by reversing the digits is 594 less than the original number. Findthe number.12. |
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| 39. |
2. The sum of the digits of a 2-digit number is 7. If the digits are reversed, the new number increased by 3less than 4 times the original number. Find the original number |
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| 40. |
8The digits of a two-digit number are in the ratio 2:3 and the number obtained by interchanging the digitsis greater than the original number by 27. What is the original number?! |
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| 41. |
4. The difference of the digits of a 2 digit number is 3. If the digits areinterchanged and the new number is added to the original number, theresult is 77. Find the original number. |
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Answer» let the digits be x and y. x - y = 3; x = y + 3(10x + y) + (10y + x) = 7711x + 11y = 77x + y = 7y + 3 + y = 72y = 4y = 2x = 2 + 3 = 5original no. is 52 52 is is original number 52 is original number 52 the correct answer of the given question 52 is original number |
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| 42. |
3.Study of Accounting procedure of Partnerships Organisation. |
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Answer» When two or more individuals engage in enterprise as co-owners, the organization is known as apartnership. This form of organization is popular among personal service enterprises, as well as in the legal andpublic accountingprofessions. The important features of and accounting procedures for partnerships are discussed and illustrated below. |
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| 43. |
Q25. IfIf (372+5 83. Find yd-1.3 |
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Answer» blank |
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| 44. |
If the(m. 3)Jlies on the insegment oning the points A3.6and BQ2, 83, find the value afm |
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Answer» Please hit the like button if this helped you |
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| 45. |
17. If a+ b + c15 and a2+ b+c2-83, find value of a+b2+3- 3abc. |
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| 46. |
8. The supplement of an angle is one-third of itself. Determine the angle and its supplement. |
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Answer» thanks |
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| 47. |
7. The supplement of an angle is one-third of itself. Determine the angle and itssupplement. |
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Answer» supplement angles addition is 180so x=1/3(180-x)3x=180-xso 4x=180so x=45so.angles are 45 and 135 |
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| 48. |
10. If the supplement of an angle is two-third of itself. Determine the angle and itssupplement |
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Answer» Think you so much x + 2/3x =180 5/3x= 180 x=180×3/5x= 108 . so the other angle is 2×108/3 = 72 |
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| 49. |
QRS in which QR -7 cm, PR- PS 55 cm, RS 4.5 cm, and QS-95 em. |
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| 50. |
9. Find10. Findthe angle whose supplement is four times its complement.the angle whose complement is one third of its supplement. |
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Answer» 1) sum of supplementary angles is = 180° so , let the angle be x => supplementary angle is. 180-x also , its complementary angle is 90-x now , according to the question..180-x = 4(90-x) => 4x-x = 360-180 => 3x = 180° so, x = 180/3 = 60° 2) sum of complementary angle is 90°so, let the bigger angle be xnow its complimentary angle is 90-x , and also its supplementary angle is 180-x now according to the question 180-x = 3(90-x) => 3x-x = 270-180 => 2x = 90 => x = 45° |
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