9. Find10. Findthe angle whose supplement is four times its complement

1.	9. Find10. Findthe angle whose supplement is four times its complement.the angle whose complement is one third of its supplement.
Answer» 1) sum of supplementary angles is = 180° so , let the angle be x => supplementary angle is. 180-x also , its complementary angle is 90-x now , according to the question..180-x = 4(90-x) => 4x-x = 360-180 => 3x = 180° so, x = 180/3 = 60° 2) sum of complementary angle is 90°so, let the bigger angle be xnow its complimentary angle is 90-x , and also its supplementary angle is 180-x now according to the question 180-x = 3(90-x) => 3x-x = 270-180 => 2x = 90 => x = 45°

9. Find10. Findthe angle whose supplement is four times its complement.the angle whose complement is one third of its supplement.

Answer»

1) sum of supplementary angles is = 180° so , let the angle be x => supplementary angle is. 180-x

also , its complementary angle is 90-x now , according to the question..180-x = 4(90-x) => 4x-x = 360-180 => 3x = 180° so, x = 180/3 = 60°

2) sum of complementary angle is 90°so, let the bigger angle be xnow its complimentary angle is 90-x ,

and also its supplementary angle is 180-x

now according to the question 180-x = 3(90-x) => 3x-x = 270-180 => 2x = 90 => x = 45°