Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
B. If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 timesthe least, then the numbers are(a) 5, 10, 15, 20 (b) 4, 10, 16,22 (c) 3,7, 11, 15 (d) none of these |
|
Answer» (a) 5,10,15,20 The sum of this number is 50.5+10+15+20=50And from this number we get,the greatest number is 4 times the least number,5*4=20 |
|
| 2. |
\frac { ( \frac { 1 } { \sqrt { 9 } } - \frac { 1 } { \sqrt { 11 } } ) } { ( \frac { 1 } { \sqrt { 9 } } + \frac { 1 } { \sqrt { 11 } } ) } \times \frac { 10 + \sqrt { 99 } } { A } = \frac { 1 } { 2 } |
| Answer» | |
| 3. |
7. The diameter of the moon is approximately one fourth of the diameter of the earth.Find the ratio of their surface areas. |
| Answer» | |
| 4. |
की कक हरo71 2x + 3y +8=0,x- y- 1=0. |
|
Answer» 2x + 3y + 8 = 02x + 3y = -8 ......(1)x - y - 1 = 0x - y = 1 ......(2) Samikaran (1) aur (2) kaeq (1) + 3 × eq (2)2x + 3y = -83x - 3y = 3 5x = -5x = -5/5x = -1 So, y = 1-x y = 1 - (-1) y = 2 thank you |
|
| 5. |
4x+py+8=02x+2y+2=0 |
| Answer» | |
| 6. |
For what value of k, the quadratic equation ky2 -4y +1 0, is a |
|
Answer» for the value of k= 4because (2y-1)²= 4y²+1-4y |
|
| 7. |
For what value of k, the quadratic equation ky2-4y 1 0, is a perfect square? |
| Answer» | |
| 8. |
7.The diameter of the moon is approximately one fourth of the diameter of the earth.Find the ratio of their surface areas. |
| Answer» | |
| 9. |
The diameter of the moon is approximately one fourth of the diameter of the earth.Find the ratio of their surface areas7. |
| Answer» | |
| 10. |
Solve the following simultaneous equations:(i) 4x +5y= 10; 5x +4y= 17. |
| Answer» | |
| 11. |
1. The diameter of the moon is approximately one fourth of the diameter of the earth.Find the ratio of their surface areas. |
|
Answer» Let diameter of earth = D diameter of moon =D/4 =) radius of earth = D/2 =) radius of moon = D/8 earth and moon are like spheres. so volume 0f earth = 4/3×π(D/2)^3 and volume of moon = 4/3 × π(D/8)^3 so ratio of their volumes = 512/8 = 64:1 curved surface area of earth = 4π(D/2)^2 curved surface area of moon = 4π(D/8)^2 so ratio of their surface area = 64/4 = 16:1 |
|
| 12. |
RY THIS3 x 4m cannot end with the digit 0 or 5 for any natural numbersShow thatn'and 'm |
|
Answer» If n and m are equal to 1, 3^n×4^m Is equal to 12if 2 the product formed is 48 and so on for any natural number thus 3^n×4^m cannot end with 0 or 5 |
|
| 13. |
\begin{array} { l } { 2 \times 2 = } \\ { 50 \times 50 = } \\ { 150 \times 320 = } \\ { 500 \times 165 = } \end{array} |
| Answer» | |
| 14. |
50 \times 99 |
|
Answer» 4950 50*99=4950 is the correct answer |
|
| 15. |
in 3 minutes.dation to show how many seconds are |
| Answer» | |
| 16. |
what is 50 times 11? |
|
Answer» 50 times 11 is 50 × 11 = 550 |
|
| 17. |
O, and O, are the centres of two congruent circles intersecting each other at pointsC and D. The line joining their centres intersects the circles in A and B such thatAB > O,02. If CD = 6 cm and AB = 12 cm, find the radius of each circle.4. |
| Answer» | |
| 18. |
Two congruent circles intersect each other at points A and 1Bsegment PAQ is drawn so that P, Q lie on the two circles, Prove that E. Ihrou |
| Answer» | |
| 19. |
Recall that two circles are congruent if they have the same radi. Prove that equalchords of congruent circles subtend equal angles at their centres |
| Answer» | |
| 20. |
For what value of k, the quadratic equation kY²- 4y + 1 = 0, is a perfect square |
|
Answer» For perfect sqaure discrimanat must be 0So,D = (-4)² - 4 × k × 1 = 016 - 4k = 0k = 4 |
|
| 21. |
kx+3y=k-312x+ky=k if it has unique solution. find value of k |
|
Answer» a and b are not equal in unique solution |
|
| 22. |
1. For what value of k, the following equations have a unique solution?4x + ky +8 02x + 2y + 50 |
|
Answer» condition for unique solutiona1/a2not equal to b1/b2here a1= 4, b1=k, a2=2, b2=24/2=k/2k= 4the value of k is 1,2,3,-4,( other than 4 ) is unique solution |
|
| 23. |
6. If x 1 and y 6 is a solution of 8x - ky +20, findthe values of k |
| Answer» | |
| 24. |
If the equations 5x + ky = 3and kx + 5y = 3represent the same line then k =(A) 1(8) 5(0) 3(D) of these |
| Answer» | |
| 25. |
there are 60 seconds in a minute. how many seconds are there in 1 hour and 6 hours |
|
Answer» 1 minuteis made up of60 seconds. Hence1 hourhas =60*60= 3600seconds. 1 min = 60 sec.1 hour = 60 min = 60 min × 60 sec= 3600 sec.6 hours = 6 × 60 min = 360 min= 360 min × 60 sec.= 21,600 sec. In 1 hour=3600 secondsIn 6 hours=3600×6=21, 600 seconds. 3600 is the right answer of the following 1 h = 3600 s6h = 21,600 s 21600 is the correct answer. please like as best 1hour= 60×60 =3600 sec6 hours=6×60×60=21600 sec 21600 sec is the correct answer of the given question 3600it is your answer 3600 and 21600 is the right answer 1min=60sec1 hour=60min=60×60=36006hours=6×60min=360min=360×60=21,600 1 minute = 60 second; 1 hr = 60 + 60 = 3600, 6 hours = 6x60=360 min, =360 min x 60 sec = 18+3+60=21600 sec in 1 hours 3,600 sec and in 6hour -21, 600 sec 1m=60sec1h= 3600sec6h×3600sec=21,600sec 1 hour= 60×60= 3600 sec6 hours= 6×60×60= 21600 sec 1min= 60 sec. 1 hour = 60 min = 60 min × 60 sec= 3600 sec. 6 hours = 6× 60 min = 360= 360 min ×60 sec = 21600 sec |
|
| 26. |
THU DARI PUUKUU 2UUPADELO- A minute has 60 seconds and an hour has 60 minutes. How many seconds are there in 4 hours? |
|
Answer» 60*60= 3600 for one hour3600*4=14, 400 Seconds in one hour=60×60 =3600Therefore, seconds in 4 hour=3600×4 =14400 |
|
| 27. |
an ant can carry 50 times its weight. if a person can do the same, how much would you be able to carry? |
|
Answer» Our weight raised to the power of fifty . |
|
| 28. |
d in a van, which cannot carry beyond 800 Rylifference between two numbers is 983563. If the greater number is 139835naller number. |
|
Answer» if greater no is 139835then the other number will be139835-983563=-843728 |
|
| 29. |
In a single throw of a die, find the probabilityof getting a number(i) greater than 2(ii) less than or equal to 2(ii) not greater than 2. |
| Answer» | |
| 30. |
If-tanÂŽë3)Prove that xa+ya" = sin2If u = tan-1Prove that y sin 2.x-y |
| Answer» | |
| 31. |
After allowing a discount of 8% on a toy. It is sold for Rs. 216.20·Findmarked Price of the tea set.the |
|
Answer» Let mp be Rs xx-8/100*x= 216.2092x/100= 216.20x= 216.20*100/ 92= 21620/92= Rs 235 |
|
| 32. |
5. A tea set was bought for528 after getting a discount of 12% on its marked price. Find themarked price of the tea set. |
|
Answer» Solution : Let the marked price of tea set be Rs =X Therefore , MArked Price - Discount on MArked Price = 528 X - 12/100 *X = 528 100 X - 12 X / 100 = 528 88X = 528*100 X = 52800 / 88 X = 600 Your answer is: 600 |
|
| 33. |
1)the probability: setTwo different dice are tossed together. Find1) of getting a doublet(ii) of getting asum 10, of the numbers on the two dice. |
|
Answer» Given that two different dice are tossed. Total number of outcomes = 6^2 = 36. (1) Let A be the event of getting a doublet. n(A) = {1,1},{2,2},{3,3},{4,4},{5,5},{6,6} = 6. Required probability P(A) = 6/36 =1/6. (ii) Let B be the event of getting a sum of 10 of the numbers of two dice. n(B) = {6,4},{4,6},{5,5} = 3. Required probability P(B) = n(B)/n(S) = 3/36 =1/12 |
|
| 34. |
16. a. Explain the method by which Aluminium metal is extracted.b. Give the name and chemical formula of the ore of Copper.C. How is Zinc extracted from calamine? Explain with equations. |
| Answer» | |
| 35. |
u=\sin ^{-1} \frac{x}{y} \text { prove that } x \frac{\partial u}{\partial x}+y \frac{\partial u}{\partial y}=0 |
| Answer» | |
| 36. |
cp=-09-17| 33 )4. Using each of the following values of a, b and c, verify a X (b + c) is equalb + a X c.Which property are you verifying?b. a= (-3) 6= (-3) |
|
Answer» the answer could be b the answer could b because question small b ) 4/5............ok like plzz ax( b+c)=b=axc:;. 2/3x((-4/5+5/8)=2/3×. (-32+25/40)=2/3×(7/40)= 80+21/120=101/120; (axc)=(2/3×-4/5)=(10+12/15)=. (22/15)×(-4/5)=110-60\75=50/75=10/15=5/3 |
|
| 37. |
A tea set was bought after getting a discount of 12% on its marked price. Find the marked price of the tea set. |
|
Answer» 88%. |
|
| 38. |
A tea set was bought forthe tea set.528 after getting a discount of 11% on its marked price. Find the marked price of |
|
Answer» thanks |
|
| 39. |
528 after getting a discount of 12% on its marked price. FA tea set was bought formarked price of the tea set.5.ind the |
| Answer» | |
| 40. |
1. Define the atomic mass unit.2. Why is it not possible to see anatom with naked eyes? |
| Answer» | |
| 41. |
(5न mas A . ८ e ; P”U‘LM A—CZ\D& ‘A : 2 |
| Answer» | |
| 42. |
[MULTIPLE CORRECT CHOICE TYPE]The expression\sqrt{\sin ^{4}(37.5)^{\circ}+4 \cos ^{2}(37.5)^{\circ}}+\sqrt{\cos ^{4}(37.5)^{\circ}+4 \sin ^{2}(37.5)^{\circ}}simplifies to |
|
Answer» you can solve lending process |
|
| 43. |
A dinner set was bought for 2,464 after getting a diprice. Find the marked price of the dinner set.inner seter getting a discount of 12% on its marked |
| Answer» | |
| 44. |
The marked price of an article is Rs 500.It is sold at successive discounts of 20%and 10 % . The selling price of the article(in Rs) is |
| Answer» | |
| 45. |
1100 -cycle) ě Yadit 5 Crn and 3cmintersect at two beirls and the diztence |
|
Answer» Let the radius of the circle centered at O and O' be 5 cm and 3 cm respectively. OA = OB = 5 cm O'A = O'B = 3 cm OO' will be the perpendicular bisector of chord AB. ∴ AC = CB It is given that, OO' = 4 cm Let OC bex. Therefore, O'C will be 4 −x. In ΔOAC, OA2= AC2+ OC2 ⇒ 52= AC2+x2 ⇒ 25 −x2= AC2... (1) In ΔO'AC, O'A2= AC2+ O'C2 ⇒ 32= AC2+ (4 −x)2 ⇒ 9 = AC2+ 16 +x2− 8x ⇒ AC2= −x2− 7 + 8x... (2) From equations (1) and (2), we obtain 25 −x2= −x2− 7 + 8x 8x= 32 x= 4 Therefore, the common chord will pass through the centre of the smaller circle i.e., O' and hence, it will be the diameter of the smaller circle. AC2= 25 −x2= 25 − 42= 25 − 16 = 9 ∴ AC = 3 m Length of the common chord AB = 2 AC = (2 × 3) m = 6 m |
|
| 46. |
37. The marked price of an article is Rs. 80.00.If it is sold at Rs. 72.00; the discount rate is |
|
Answer» MP = 80 SP = 72 Discount = MP - SP = 80 - 72 = 8 Discount % = 8 /80 × 100 = 10% |
|
| 47. |
Find the area of a parallelogram with base 32 crn and height 165cm.1. |
|
Answer» thank you |
|
| 48. |
1-60^{x}=3 \text { and } 60^{3}=5 then the value of 12^{2(1-b)} |
| Answer» | |
| 49. |
जार में कुछ वस्तुएँ गिनकर बेची जाती हैं। जैसे- संतरे, पेन्सिल, रबड़, केले आदि। इनके लिएमाप निम्नलिखित हैं-1 दर्जन 12 वस्तुएँ1 ग्रुस - 12 दर्जन| कौड़ी- 20 वस्तुएँ1 दस्ता = 24 कागज| रिम = 20 दस्ते| रिम -480 कागज-5 ग्रुस ४ दर्जन केलों को दर्जन में बदलिए।5 ग्रुस 8 दर्जन केले-5x 12 दर्जन +8 दर्जन= 60 + 8 दर्जन - 68 दर्जन उत्तर4 दर्जन केलों में कुल कितने केले होंगे?4 दर्जन केले = 4x12 केले - 48 केलेउत्तर8 कौड़ी संतरों में कितने संतरे होंगे?8 कौड़ी संतरे =8x20 संतरे - 160 संतरे उत्तर5 ग्रुस 4 दर्जन 2 कौड़ी वस्तुओं को इकाई वस्तुओं में बदलिए।- ग्रेस 4 दर्जन 2 कौड़ी वस्तुएँx 12 दर्जन +4 दर्जन +2 कौड़ी वस्तुएँदर्जन +4 दर्जन + 2x20 वस्तुएँ72X12) + (4 x 12) + (2 x 20)] वस्तुएँ |
|
Answer» please select our questions please select a question please select one question |
|
| 50. |
93.5 x l00.58 × 100014.24 × 127.59l x 6095.06 × 135 |
| Answer» | |