For what value of k, the quadratic equation kY²- 4y + 1 = 0, is a per – InterviewSolution

1.	For what value of k, the quadratic equation kY²- 4y + 1 = 0, is a perfect square
Answer» For perfect sqaure discrimanat must be 0So,D = (-4)² - 4 × k × 1 = 016 - 4k = 0k = 4

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