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1. For what value of k, the following equations have a unique solution?4x + ky +8 02x + 2y + 50

Answer»

condition for unique solutiona1/a2not equal to b1/b2here a1= 4, b1=k, a2=2, b2=24/2=k/2k= 4the value of k is 1,2,3,-4,( other than 4 ) is unique solution



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