Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Two-thirds of three-fourths of one-seventh of a number is 8 What is 50% of that number(a) 56(b) 86(b) 60(C) 53(d) 59ts Rs 800 more than a

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suppose number is x so 2/3*3/4*1/7*x = 8 1/14*x = 8 so x = 14*8 = 112 50% of x = 0.5×112 = 56

2.

. The difference between the ages of two cousins is Toytltwice as old as the younger one, find their present ages.Half of a herd of deer are grazing in the field and three-fourths of the remaining are playingnearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.

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3.

9.A polyhedron has 30 edges and 12 vertices. How many faces does this polyhedron have?

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E +2 = F + V ( Euler's formula)

30+2 = F+12

F = 32-12

F = 20

4.

In the given figure, DE I| BC and AD: DB-5:4 findarea of ΔDFEarea of ΔCFB

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5.

Theorem 10.1: The tangent aradius through the point of contact.t perpendicular to the radius through the point of contact

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6.

| In figure if AD-6cm, DB-9cm, AE = 8cm and EC-12cm and <ADE = 48". Find. ABC| 15.

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7.

5.| In figure if AD-6cm DB-An AE-3cm and EC-12cm and ZADE-480. Find ABC1

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8.

6 km 5 cm into km

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9.

1) 6 km 5 m 4 cm into km

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10.

Explain how8. Is this correctly matched? Explagot the answer.Figure CutCross-sectionobtainedHorizontal

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yes it is correct because when we made jar then piece of tin is rectangle in size. when we fold in such a way that it comes as cylindrical . so it is correct.

yes it is match because the cylinder is horizontaly they convert into rectangle

yes this is correctly matched.when we fold in such a way that it comes as cylindrical .

yes ,This is correctly matched.Explain -The cylinder is horizontally they convert into rectangle.

11.

7. If an angle of a parallelogram is four fifths of its adjacent angle, findthe angles of the parallelogram.if one nf its angles is

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12.

3. Write the following statements in equation form. Find numerals to make true statementsEquation formSolution(i) The sum of 5 and x is 125 + x = 12(ii) x decreased by 7 is 132-713(iii) Six less than two times y is 32(iv) If 8 is taken away from the number n, the result is 4(v) 9 multiplied by ris 36(vi) a multiplied by 7 gives - 35(vii) If dis divided by - 4, the result is 3(viii) Eight decreased by 3 times a number equals 2.(ix) The product of 7 and the number is 42(2) Quotient of m divided by 5 is 6.

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sum of 5 and x=12; 5+x=12;; x=12-5=7; 2)x-7=13; x=13+7=20; 3)6 less 4 and 2=32; 32/4=8; 32/2=16;

v) 9 multiplied r be 36; 9+x=36; x=36/9=4; q+7=35; q=35/7=5; vii)q/-4=3; q=3×-4=12; ix) product of 7=42; axb=42; ax7=42; 7=42/a=6; (x)m=5×6=30

13.

and the measure of each angle 0l Ul7. If an angle of a parallelogram is four fifths of its adjacent angle, findthe angles of the parallelogramloof a narallelogram, if one of its angles is

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14.

aleFind the sum of the rational numbers –

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-5/16+7/12=-60+112/192=52/192=26/96=13/48

-5/16+7/12=-85+112/272=27/272

15.

5. How many one fourths are there in 3?

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We know that there are 4 one fourths in 1. so if we want to know the no. of one fourths in 3, just multiply 3 with 4:3×4= 12so the no. of one fourth in 3 are 12.

16.

m) Bearer chequev) Traveller cheque.Da all parts:Go-Factorization of 9r2-642.

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9x² - 64

(3x)² - 8²

( 3x - 8) ( 3x + 8)

17.

DatePageFind the solutionlequation 2ty tofothe pair ofand 2 ty alsHence find 2 if y= 22 +5

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x/10+ y/5-=0; x/8+y/6=15; 6(x/10 + y/5=0); 5(x/8+y/6=15):; x/60 + y/30=6; x/40+y/30=75; x/20=81; x=81/20=4.05;

18.

6. In triangle ABC, DE I BC and ADIFAC 4.8 cm, find AlEDB 5

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BASIC PROPORTIONALITY THEOREM(BPT) :If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points than the other two sides are divided in the same ratio.SOLUTION:In ∆ABC , DE||BCAD/DB= AE/EC[ By basic PROPORTIONALITY theorem]AD/DB= AE/(AC-AE)3/5 = AE / (4.8 - AE)3(4.8 - AE) = 5 AE14.4 - 3AE = 5AE14.4 = 5AE+3AE14.4 = 8AEAE = 14.4/8AE= 1.8Hence, AE is = 1.8 cm

19.

2. Find the area of the shaded region, if PAST14 cm and ALS and PLT are semicircles.is a square of side

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20.

0ILSs early. TheDI 18000(C) 10000kmcm6,600 in58. What sum will amount tosimple4 years at 8% per annuminterest?(A) 6,000 (B) 75,000(C) 4,000 (D) 6,200

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Use formula of simple interest

Simple Interest = P×R×N/100

21.

27. A traveller walks a certain distance; had he gone half a km anhour faster, he would have walked it in four-fifths of the time: had hegone half a km an hour slower, he would have been 23 hours longeron the road. Find the distance

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Solution:Formula:speed(s)*time(t)=distance(d)

walked 1/2km with time 4/5(s+0.5)((4/5)+t)=d --->(1)1/2km an hour slow, walked 2and half hr long(s-0.5)(t+2.5)=d ----->(2)solving (1) & (2)we get s=2t=7.5d=2*7.5=15km

22.

13. If two-fifths of a number added to 4 gives 36, find the numberfifths of what

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let the no=xA/Q2/5x+4=362/5x=36-42/5x=322x=32*5x=32*5/2x=16*5x=80

23.

How many one-fifths are there in 100?

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5 one-fifths make one unit. So, 100 is made up of (100*5) = 500 one-fifths.

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24.

Section EBAnswer any ten from the following+8000

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➡1^3+2^3+3^3+.....+20^3

As we know that summation of n^3={n (n+1)/2}^2Here n=20

➡ Sum={20 (20+1)/2}^2

➡ Sum=(10×21)^2

➡ Sum=210^2

➡ Sum=44100

25.

21. 1000, 8000, 27000, 64000, 125000,?(3) 343000(1) 128000(4) 216000(2) 145000(5) 25000(4) The series has the following pattern103,202, 309, 403, 503, 603Hence, the missing term is 216000.VII. Based on (n3+ 1) Series

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The following series is of the pattern (n*10)³ where n is the number of the term so the next term is (6*10)³=216000Therefore option 4 is correct.

26.

5. Find the least number of five digits, but more than 10000, which is a perfect square), which is a perfect square. AlsAlefind the square root of the number so obtained.

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27.

choose the correct answer from the given optiony.1. 1 m?a) 1000 cmb) 10000 cmc) 100000 cmd) 1000000 cm

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28.

Fill in the boxes withor(ii) 킁매(w) 킁며-A-8-3(iii) 139 8--"10

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i) <ii) >iii) < iv) >

full divid

29.

A path 1 m wide is built inside a square park of side 30 m along its sides. Find the areaof the path. Calculate the cost of constructing the path at the rate of 70 per m2

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side of square park (A) = 30m width of path = 1m side of inner park (a) = 30-1-1 = 28m cost of construction = 70 per m^2 Area of path = Area of square park - area of park inside the path = A^2 - a^2 = 30^2 - 28^2 = 900 - 784 = 116m^2 Cost of construction of path = 70×116 =8120

30.

2. A path 1 m wide is built inside a square park of side 30 m along its sides. Find the areaof the path. Calculate the cost of constructing the path at the rate of 70 per m2.

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31.

(iii)o | w&amp;~

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i) 3/6 + 9/18 = 3 x 3/ 6 x 3 + 9 x 1/ 18 x 1 = 9/18 + 9 /18 =18/18

iii) 2/4 *5/6=5/12i)3/6+9/18=18/18=1

32.

Two cross roads, each of width 5 m, run at right angles through the centre of a rectangularpark of length 70 m and breadth 45 m and parallel to its sides. Find the area of the roads.Also, find the cost of constructing the roads at the rate of105 per m2

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33.

roads,eachof width 5 m, run at right angles through the centre of acrosstangular park of length 70 m and breadth 45 m and parallel to its sides. Find?the area of the roads. Also find the cost of constructing the roads at the rate of105 per m2. 3

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34.

hectare. Find the length of its diagonal in metres.e area of a square field isHint. 1 hectare 10000 m213. Th2

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35.

in metres.3. The area of a square field is hectare. Find the length of its diagonal2Hint. 1 hectare 10000 m2rie urhich can so fourf

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36.

18. In a shower, 6 cm of rainfall was there. Find the volume of water that fell on 1.5 hectares of land.[Hint 1 hectare = 10000 m2].

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1hectare =10000m,then,1.5 hectare=15000m,so;cm^2 =15000×100×100cm^2=150000000cm^2rain falls = 6cmvolume of rainfall =150000000×6cm^3=900000000cm³

37.

Half cubic meter of gold-sheet is extended by hammering so as to cover an area of 1 hectare.Find the thickness of the gold-sheet1.thectane10000 m 2

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38.

(g+%) + (9 — खान देने इसे ८.

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hit like if you find it useful

39.

2 3 9 4 9 21у ху ху ху

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40.

2*((9*pi)/4 %2B sqrt(2)/3 - 9*asin(1/3)/2)

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41.

the area of Square is 10000 square cm find the area in metres

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1m =100cmNow 10000cm^2 =1m^2Thus area is 1m^2

the answer is 100 meteres ok subhash

42.

1. Find the sum of each of the following APs:(i) 2, 7, 12, 17, ................to 19 terms.

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sum of Ap =n/2[2a+(n-1)d]givenno. of terms =19first term or "a"=2common difference =5now, sum of ap= 19/2[2*2+(19-1)*5]=>19/2[4+(18)*5]=>19/2[4+90]=>19/2*94=>19*47=>893

43.

7. A line passes through (2,4). Find the locus ofmid point of the intercept between the axes.

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Now the midpoint of the x-intercept (a,0) and the y-intercept (0,b) is the point (a/2, b/2).Substituting Equation A into the y-coordinate of the point (a/2, b/2), we get

44.

j)125% of 10 litres

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12.5l is the right answer

12.5liters25%=2.5liters25%×2.5=12.5%

10 x 125/100 = 12.5 liters id correct answer.

the correct answer is 12.5.

12.5 is the correct answer

12.5 is correct answer

12.5 l is the right answer

12.5 liters is the correct answer

12.5 litres is the right answer

12.5 is the correct answer

125×10/100=12.5% is correct answer.

45.

W 10 III lung?10. A car covers a distance of 22.8 km in 2.4 litres of petrol. How1 litre of petrol?in 2.4 litres of petrol. How much distance will it cover

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46.

कैट 30+ 20050+35790- धा

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47.

7 Prove thatsin 0 —2sin’0 न20050:

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(sin-2sin^3 )/(2cos^3-cos)=tan

solving LHS

lhs=(sin-2sin^3 )/(2cos^3 -cos)

lhs=sin(1-2sin^2)/cos(2cos^2-1)

lhs=sincos2/coscos2

lhs=sin/cos

lhs=tan

lhs=rhs

hence proved

48.

A line is perpendicular to 3x+ y 3 and passesthrough a point (2, 2). Its y intercept is -

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49.

4, 6= जांबावगे मांस निर्मम को, एड 20050 +1 ला... शरद2516 - /3 = 0 मगीकतन पू्टि मिष्थ =)

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thanks

50.

Find the equation of the straight line which passes through the point(2, 3) and whose intercept on the x-axis is double that on the y-axis.]

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