1.

1. Find the sum of each of the following APs:(i) 2, 7, 12, 17, ................to 19 terms.

Answer»

sum of Ap =n/2[2a+(n-1)d]givenno. of terms =19first term or "a"=2common difference =5now, sum of ap= 19/2[2*2+(19-1)*5]=>19/2[4+(18)*5]=>19/2[4+90]=>19/2*94=>19*47=>893



Discussion

No Comment Found