6. In triangle ABC, DE I BC and ADIFAC 4.8 cm, find AlEDB 5 – InterviewSolution

1.	6. In triangle ABC, DE I BC and ADIFAC 4.8 cm, find AlEDB 5
Answer» BASIC PROPORTIONALITY THEOREM(BPT) :If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points than the other two sides are divided in the same ratio.SOLUTION:In ∆ABC , DE\|\|BCAD/DB= AE/EC[ By basic PROPORTIONALITY theorem]AD/DB= AE/(AC-AE)3/5 = AE / (4.8 - AE)3(4.8 - AE) = 5 AE14.4 - 3AE = 5AE14.4 = 5AE+3AE14.4 = 8AEAE = 14.4/8AE= 1.8Hence, AE is = 1.8 cm

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