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Area of lawn = 70* 85 as length= 70m and breadth = 85mas it is a rectangle area will be 5950 m^2After path is around rectangleso new Length 70+(2*10)= 90 mand new width= 85+(2*10)= 105marea of rectangle with path = 90*105= 9450m^2= (length*breadth)So area of path = 9450-5950= 3500 m ^2

compare all 3 terms with constant kso 2A=3B=4C=kso A=k/2, B=k/3, C=k/4so A:B:C=k/2:k/3:k/4=6:4:3

Area of lawn = 70* 85 as it is a rectangle 5950 m^2After path is around rectangleso new Length 70+(2*10)= 90 mand new width= 85+(2*10)= 105marea of rectangle with path = 90*105= 9450m^2So area of path = 9450-5950= 3500 m ^2

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207+840=1047.584+20 = 604.147+170=317.1921+110=2031.78+207=285.

207+840=1047584+20=604147+170=3171921+110=203178+207=285

207+840=1047584+20=604147+170=3171921+110=203178+207=285

So 5 number will be0.210.220.230.250.26

To find 5 numbers between 1/2 and 1/3

Denominator of both fraction should be same

1/2 = 1*15/2*30 = 30/601/3 = 1*20/3*20 = 20/60

Now five rational numbers between 20/60 and 30/60 are21/60, 22/60, 23/60, 24/60, 25/60

0.54406804435 is the answer

5a+4b+3c+3a-3b-2c-2a+5b-8c=6a+6b-7c answer

5a+4b+3c+3a-3b-2c-2a+5b-8c=6a+6b-7c answer

6a+6b-7c is the correct answer of the given question

answer to this question is (6a+6b-7c)

=6a+6b-7cis the best answer

5a+4b+3c+3a-3b-2c-2a+5b-8c=6a+6b-7c

angle 6 + angle 7 = 180° angle 6 = 180° - 118° = 62° if m||n then angle 3 = angle 6 ( Alternate angle)As angle 6 is not equal to angle 3 here so m is not parallel to n

Let common difference be d and first term be a So, given

a(21) - a(7) = 84

a + 20d - ( a + 6d ) = 84

20d - 6d = 84

14d = 84

d = 6

For AP nth terman = a1 + (n-1)d

Then, a21 = a1 + 20da7 = a1 + 6d

Given, a11 - a7 = 84(a1 + 20d) - (a1 + 6d) = 8414d = 84d = 84/14 = 6

Common difference = 6

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thirty lakh fourth three thousand two hundred

thirty lakh forty thousand two hundred is the correct answer of the given question

Thirty lakh fourth three thousand two hundred is the answer of the following question

Thirty lakh fourty three thousands two hundred ,,,is answer this question

thirty lakhs fourty three thousand and two hundred

Thirty lakh forty thousand two hundred is the correct answer of the given question

answer

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In triangle OAC tan 45=AC/OA=1

AC=OA=80

IN TRIANGLE ODB

tan 30=BD/OB=1/√ 3

OB=BD√ 3-AC√ 3(since ac=bd as bird remains constant height)

AB=OB-OA=AC√ 3-AC=AC(√ 3-1)=80(√ 3-1)

NOW FOR 2 SEC

80(√ 3-1)/2=40(√ 3-1)

=29.2M/SEC

3n+7=253n=25-73n=18n=18/3=6

Given,Mean = 14.25Median = 15.5Mode = 16

As mode is 16 so age of twins is 16

Let, age of other two children are x and yIn ascending order ages are x, y, 16, 16

Then,Median = ( y + 16)/215.5 = (y + 16)/231 = y + 16y = 31 - 16 = 15

Mean = (x + y + 16 + 16)/414.25*4 = x + 15 + 32x = 57 - 47x = 10

Therefore ages of four children are 10, 15, 16, 16

Let the two parts be x and y.x+y = 84⇒ y = (84-x)

You need to maximise the product of "one part" and "the square of other"Let one part = (84-x)square ofother part = (x)² = x²product, p = x²×(84-x) = 84x² - x³

dp/dx = 0d/dx(84x² - x³) = 084*2x - 3x² = 03x(56 - x) = 0x = 0, 56

For maximum,d^2 p/dx^2 < 0d^2 (84x² - x³)/dx = d/dx(168x - 3x²)= 168 - 6x

at x = 0168 - 6x = 168 - 0 = 168 > 0

at x = 56168 - 6x = 168 - 6*56 = - 168 <0

So x=56,y = 84 - x = 84 - 56 = 28

So the two parts are (28,56)

Explanation : (7/15)/(7/9 + 5/10) ÷ 1/2 = (7/15)/((70+45)/90) ÷ 1/2 = (7/15)/(115/90) ÷ 1/2 = (7×6)/115 × 2 = 84/115

Answer : 84/115

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1st is correct answer

1st is the correct answer of this question

1st is correct answer

1st is the correct answer

1st is the correct answer

3645 = 3*3*3*3*3*3*5

=(3*3)*(3*3)*(3*3)*55 is alone here

to make 3645 perfect square we multiply with 5

3645*5 = (3*3)*(3*3)*(3*3)*(5*5)

=(3*3*3*5)^2=(135)^2

Let x = the number Then, x + x2 = 42. So, x2 + x - 42 = 0 (x + 7)(x - 6) = 0 x = -7 or x = 6

We have to find the surface area of the cubical box.

Surface area of the cube = 6a² where a = 30 cm

⇒ 6*30*30

⇒ 5400 sq cm

As the cubical box has to be painted both from the outside and inside.

So, the total surface area = Inner surface area + outer surface area

⇒ 5400 + 5400

= 10800 sq cm

As we know that 1 sq m = 10000 sq cm

Surface area in sq m = 10800/10000

Surface area in sq m = 1.08 sq m

Cost of painting the cubical box = Rs. 5.50 per sq m

Total cost of painting = 5.5*1.08

Total cost = Rs. 5.94

So, the total cost of painting the cubical box from outside and inside is 5.94

Given,Side of Square = 11 cm

Perimeter of Square Ps= 4*side= 4*11 = 44 cm

Let radius of circle be r

Then,Circumference of circle C = 2*pi*r

As per given conditionC = Ps2*pi*r = 442*22/7*r = 44r = 7 cmm

Area of circle = pi*r*r= 22/7 * 7 *7= 154 cm^2

Volume of cube = (side)³Volume of cube = (11 cm)³ = 1331 cm³

It will be after the rationalization√5/2√5*√5√5/102.236/100.2236AnswerPlease like the solution 👍 ✔️

Literal numbersare the letters which are used to represent anumber. Theliteral numbersare also known as literals.Literal numbersobey all the rules of addition, subtraction, multiplication and division ofnumbers. Thus, a + b means b is added to a

A family has 3 ChildrenThus total members in the family = 5

Thus

Probability that family has exactly one girlP = 1/5

Probability that it has At least one girlP = 3/5

Probability that it has utmost girlP = 0