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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the volume of a cubical box of side 11 cm. |
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Answer» Volume of a cubical box of side 11 cm=(11 cm)³=1331 cm³ |
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| 2. |
O The digits of a two-digit number differ by 3. If the digits are interchanged and thereigumber is added to the original number, we get 143. What can be the originalber? |
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| 3. |
1. The length of each side of a cubical boxis 2.4 m. Its volume is |
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| 4. |
6.)Find the length of each side of a cubical box, the volume of which is 61 em2 |
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| 5. |
e mealassequenFind all zeroes of the polynomial (2x- 9x3 5x2+3x 1) if two of its zeroes are(2+V3) and (2-3).lowin |
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| 6. |
14. A square lawn is surrounded by a path 2.5m wide. If the area of the path is 165 m' find the area of the lass |
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| 7. |
Example 14: The digits of a two-digit number differ by 3. If the digits are interchanged,and the resulting number is added to the original number, we get 143. What can be theoriginal number? |
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| 8. |
फर्क दरiy ™ ) I s%W"‘% 7S T LG |
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Answer» Let speed of A be Km/h and speed of B be km/h And we know that distance =80km 80=(a-b) ×8 and 80=(a+b)×(4/3) a-b=10 and a+b=60 a= 35. , b=25 |
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| 9. |
पु हे 01८८ 1178 6 7S (5.54जी 1 ६0२८ ९0/५क. ण 00 obt ‘W!fd—i¢ |
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Answer» Percentage marks scored by Rupesh = (495/750) × 100 = 66% |
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| 10. |
=(190-101)err t4. Find the perimeter of the shaded region, ifABCD is a square of side 21 cm and APBand CPD are semi-circles,use π |
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Answer» Like if you find it useful |
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| 11. |
15. Find the 11th term from the end in the AP 56, 63, 70,. ,329 |
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| 12. |
of a cubical box ism216ns side |
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| 13. |
15. The angles of q.ad Haierai are iu the ratiosFitnd ail the angles of the quairi.atera.3. |
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| 14. |
Folve the following word problems.A two digit number and the number with digits interchanged da143. In the given number the digit in unit's place is 3 more thandigit in the ten's place. Find the original number.Let the digit in unit's place is x |
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Answer» x = 4 is a correct answer |
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| 15. |
l ail giuey or this triangle are equal them of three consecutive odd numbers is 201. Find the numbers. |
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Answer» Let the intgers be 2x + 1, 2x + 3, and 2x + 5, so 6x + 9 = 201, so 6x = 192, so x = 32, and the numbers are: 65, 67, and 69. |
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| 16. |
the problems given below:In a two-digit number, the one's digit is 3 timesthe ten's digit. If 10 is added to the 2 times of thenumber, its digits interchange their places in thenew number. Find the number. |
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| 17. |
Find the distance between two points (2,4) & (7,8). |
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Answer» distance between (2,4) and (7,8)√(2-7)² + (4-8)²√(25 + 16)√41 |
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| 18. |
find the distance between two points (2,4)&(7,8) |
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| 19. |
distance between two points with coordinates (2,3) and (-4,4) |
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| 20. |
lass than hirę°š |
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| 21. |
s Add the sum of 5x-2y+and xyto the product of fax + yland (2x 3y).Ad the product of 5x-)and (y+ 8) to the product of f-3xy+2)and (y -2 |
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| 22. |
2 From a cubical piece of wood of side 21 cm, a hemisphere is carvedon such a way that the diameter of the hemisphere is equal to the sidete cubical piece. Find the surface area and volume of the remainCBSE2 |
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| 23. |
11. From a square cardboard of side 21 cm, a circle of maximum area is cut out. Findthe area of the cardboard left.[Hint. Diameter of circle of maximum area = 21 cm.] |
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Answer» Side of cardboard = 21 cm :. radius of circle for its area to be max would be 21/2cm Area of square= 21*21 = 441cm^2. Area of circle = (22/7)*(21/2)*(21/2)= 346.185 cm^2 :. the difference = 94.815 hit like if you find it useful Wrong answer94. 5 cm² |
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| 24. |
SusseLASSOrwakt BREAK |
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Answer» HCF (Highest Common Factor) = HCF of numerators / LCM of denominators = 1/60 |
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| 25. |
rom a square cardboard of side 21 cm, a circle of maximumthe area of the cardboard left.areaiscutout.FindDiameter of circle of maximum area = 21 cm.] |
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Answer» radius of the circle in the square= side/2 = 21/2=10.5cm area left after cutting the circle will be = area of square - area of circle=21^2 - π 10.5^2=94.64 cm^2 |
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| 26. |
SHOW Willout espanums un wayI a? bc27. (1)ca = 0[CBSE 99] |
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| 27. |
11. From a square cardboard of side 21 cm, a circle of maximum area is cut out. Findthe area of the cardboard left. |
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Answer» Diameter of circle =Side of square Diameter of circle = 21 cmRadius of circle = 21 /2 cm Area of circle = pi *r^2 = 22 * 21 * 21 /7 * 2* 2= 22 * 21 * 3 / 4= 462 * 3 /4= 1386/4= 346.5 cm^2 Area of cardboard left = Area of square - Area of circle Area of cardboard left = 21*21 - 346.5= 441 - 346.5= 94.5 cm^2 hit like if you find it useful |
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| 28. |
. Which of the following has a langer are sand by how much?A rectangle of length 24 cm and breadth 17 cm or a square of side 21 cm. |
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Answer» Area of rectangle = 24×17 = 408 Area of square = 21×21 = 441So the area of the square is more than the rectangle. Also, difference in area = 441-408= 33 cm sq. |
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| 29. |
ABC IS ail l303C0IOIf the circumference and the area of a circle are numerically equal, Find the diameterof the circle.nd distance het ween two points. |
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Answer» Circumference=Area2πr=πr²2=r diameter=2r=2*2=4 square units |
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| 30. |
Divide 56 into four parts which are in AP such that the ratio of product of extremes to the product of means is 5: 6. |
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Answer» wow |
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| 31. |
Divide 56 into four parts which are in AP such that the ratio of product of extremes to the product of means is 5:6. |
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Answer» thanks |
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| 32. |
AOB is a diameter of a circle whose centre is O. At C on the circumference a tangenecsparallel to AC meets this tangent at E. Prove that EB touches the circde. |
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Answer» thnxx |
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| 33. |
5. In Fig. 8.134, ABC is EBa triangle rightangled at C. A linesegment through themid-point M of ABand parallel to BCintersects AC at DShow that CMFig. 8.134.AB2 |
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| 34. |
Curved surface area of a cone is 308 cente meter square and its slant height is 14cm find 1 . radius of the base and2. total surface area of the cone? |
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Answer» A conical tent is 10m high and the radius of its base is 24m find 1. slant height of the tent 2. cost of the canvas required to make the tent,if the cost of 1 metre square canvas is rs 70?? |
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| 35. |
2. निम्नलिखित बहुपदों में से प्रत्येक बहुपद के लिए p(0), pp(1) और (2) ज्ञात कीजिए:(i) p{}) = y-y+1(ii) p(1) =2 + 1 + 21-1(ii) p(४)=(iv) p(CZ) = (x-1) (x + 1)|जिज्ञा कि दिखाए गए मान निम्नलिखित स्थितियों में संगत बहुपद के शुन्यक हैं: |
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| 36. |
of wood of side 21 cm, a hemisphere is carvede sidein sucha way that the diameter of the hemisphere is equal tothe cubical piece. Find the surface area and volume of the remainingpiece.28. From a cubical pieceCBSE 2014 |
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| 37. |
the two digits exceeds the given number by 36. Find the numberA two-digit number is such that the product of the digits is 14. When 45 is added to thenumber, then the digits interchange their places. Find the numbericlass than its denominator. If the numerator is decreased |
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| 38. |
Example 1.11The sum of the digits of a given two digit number is 5. If the digitsenare reversed, the new number is reduced by 27. Find the given number. |
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Answer» Suppose number is 10x + y so x + y = 5 Now digits are reversed so new number is 10y + x 10y + x = 10x + y - 27 9y - 9x = -27 x - y = 3 x + y + x - y = 5 + 3 2x = 8 x = 4 y = 1 Original number 10*4 + 1 = 41 If you find this answer helpful then like it. |
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| 39. |
丨.xo),ooool'로-lyna }.un.woaytu. Da ") r acㅓδ>~a><o//rpyl.ドwij |
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Answer» Case 1Given : P = Rs. 16000, R = 5 %, T = 3/2 yearsSimple Interest = (P*R*T)/100= (16000*5*3)/(2*100)Simple Interest = Rs. 1200Case 2Compound InterestGiven : P = Rs. 16000, R = 5 % per annum and compounded half yearly so, rate of interest = 2.5 %T = 3/2 years = 1 year and one half year = 3 half yearsA = P (1 +r/100)ⁿ= 16000 (1 + 2.5/100)³= 16000× 102.5/100× 102.5/100× 102.5/100A = Rs. 17230.25So, compound interest = 17230.25 - 16000 = Rs. 1230.25 Difference between compound interest and simple interest = 1230.25 - 1200 = Rs 30.25 thanku |
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| 40. |
. The sum of three numbers in GP is 56, If 1,7, 21 be subtracted from themrespectively, we obtain the numbers in AP. Find the numbers. |
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| 41. |
1Hesolve un |
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| 42. |
Divide 56 into four parts which are in AP such that the ratio of product of extremes to the productof means is 5:6.27. |
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Answer» 4 no =a-3d,a-d,a+d,a+3dsum , 4a=56a=14(a-3d)(a+3d)/(a-d)(a+d)=5:66(a²-9d²)=5(a²-d²)a²=54d² - 5d²14² =49d²d²=14² /7²d=±14/7=±2for d=2, a-3d=14-6=8a-d=14-2=12a+d=14+2=16a+3d=14+6=20Numbers are 8,12,16,20 Like my answer if you find it useful! |
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| 43. |
OA coue of maxinum size is carved out from a cube of edge 14 cm. Find the surface area of theremaining solid afer the cone is carved out |
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Answer» The cone will have a diameter of 14 cm and height of 14 cm. (Radius = 7cm) Slant height of cone = √(14² + 7²) = 15.652 cm Surface area = 22/7 x 7 x 15.652 + 22/7 x 7² = 498.35 cm²Surface area of solid remaining solid = Total surface area of the cube - area of circle where the cone was carved out + curved surface area of cone (hole remaining in the cube)= 14x14x6 - 22/7x7² + 22/7x7x15.652= 1366.344 cm² |
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| 44. |
m a cubical piece of wood of side 21 cm, a hemisphere is carved outin such a way that the diameter of the hemisphere is equal to the side ofthe cubical piece. Find the surface area and volume of the remainingpiece.[CBSE 2014 |
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| 45. |
meter of the base of a cone is 10.5 cm and its slant height is 10cm. Find its curvsurface area. |
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| 46. |
the sum of the digits of a two digit number is 15 the number obtained by interchanging the digits exceeds the given number by 1 the number is |
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Answer» Let the number be 10x+ywith digits x,ytherefore x+y=15........(i)again, 10y+x-10x-y=9or, 9y-9x=9or, x-y=-1..........(ii)solving equation (i) and (ii) we getx+y=15........(i)x-y=-1..........(ii)------------------------2x=14x=7andy=8therefore the number is 10x+y=10x7+8=78 78 is the desired number |
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| 47. |
15. Inthe adjoining figure, EB L AC, BG 1 AE and CF L AE. Prove that(i) BC BEBD AB |
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| 48. |
33. In Fig. given below, a crescent is formedby two circles which touch at A. C is thecentre of the larger circle. The width ofthe crescent at BD is 9 cm and at EF, it is5 cm. Find the area of the shaded region |
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| 49. |
1.049; hundredths |
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Answer» there is no number at hundredths place so it is 0. |
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| 50. |
b) Factorise: (p-q)-6(P-4)-1a)Find the quotient and remainder for the following by using synthetic div(x3+2x2-x-4) (x+2)(OR |
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