Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

1. Find the sum of each of the following APs:(i) 2, 7, 12, 17, . to 19 terms(i) 9,7,5, 3, .. to 14 terms

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2.

239. Find value: 2

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(-27)^2/3

= (-3)²

= 9

3.

5. Find the sum:5399

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(5/9)+(3/9)=(5+3)/9=8/9

Answer:8/9

(5/9)+(3/9)=8/9the right answer is 8/9

Given summation is (5/9)+(3/9)=8/9.

4.

39. Find the equivalent fraction ofhaving denominator 30

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5.

)"-G)"9. Find the value of x for which333

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6.

. A car can cover a distance of 357 km on 42 litres of petrol. How far can it travel on 12 litres ofpetrol?

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Distance covered by the car with 42 L of petrol = 357 km

Distance covered by the car with 1 L of petrol = 357/42 km [less petrol, less distance]

Now, distance covered by the car with 12 L of petrol = 357/42×12 = 102 km [more petrol, more distance]

7.

9. Find:3and 2 to

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8.

0) sin A, cos A(i) sĂ­n C, cos C12 es

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9.

The cost of 1 litre is 42" What is the cost of 10 litres of milk?

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Cost of 1 litre petrol = 42 4/7 = 298/7cost of 10 1/2 litre petrol = ?10 1/2 = 21/2

298/7×21/2=6258/14so, the 101/2 litre petrol = 447 answer

Answer:. Rs 447

Step-by-step explanation:

The cost of 1 litre petrol= 10 1/2 =

21/2 x 298/7

Then we will reduce it 149x3 /1 = Rs 447

Hope it helps

milk 1 litre 298/7;, 21/2 litre milk; 287/7 × 21/2=6258/14=447 answer

The cost of 1 liter = 298/7 rupees Now the cost 21/2 liter = 298/7 x 21/2 = 597 597 is the correct answer

Sorry my answer is wrong The answer is 447

447 is correct anseer

cost of 1lt.milk=₹42 4/7cost of 21/2lt.milk=21/2×₹(294+4/7)=₹21/2×(298/7)=₹3×149=₹447

division is the answer

10.

A car can cover a distance of 357 km on 42 litres of petrol. How far can it travel on 12 litresof petrol?5.

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11.

3. A bucket is in the form of a frustum of a cone. Its depth is 15 cm and thediameters of the top and the bottom are 56 cm and.42 cm respectively[CBSE 20050Find how many litres of water can the bucket hold. Take T

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12.

39. A line passesintercept isesthrough(2,2)andisperpendicularto the line 3k450.51.522(C) 1

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13.

what numbes must be addedله مه 4 هود لمعهبا مدل ها لوا|8.

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7/2 X 4/5 = 28/10now 28/10+ X = 18so X = 18-28/10= 152/10

14.

The psroduct of too dationalnUmbes5

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let the number be X.

according to question,

(-16/5)*X = 8X= 8*(-5/16)X = -5/2

Ans: Hence, the other rational number is -5/2.

15.

Find the numbes te ms in eachhe eliwing Aps1 2

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Here,a=18t1=18,t2=15

d=t2-t1d=15-18d=-3

here,last term or nth term is -47

we know that,

tn=a+(n-1)d............................(formula).

-47=18+(n-1)-3-47=18-3n+3-47=21-3n3n=21+473n=68n=68/3n=22.67

n=>23

16.

If tane+ sece-2,value of the tan θ180es; find the

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Put tanA + secA = 2 with the trig identity 1 + tan²A = sec²A and we have the system of equations tanA + secA = 2 1 + tan²A = sec²A Solve by substitution: Solve the first for secA secA = 2 - tanA Substitute into the second equation 1 + tan²A = (2 - tanA)² 1 + tan²A = 4 - 4tanA + tan²A The tan²A's cancel and we get 1 = 4 - 4tanA 4tanA = 3 tan A = 3/4

17.

. Two Cubes have their volumes in the ratio 1: 27. Find the ratio of their surface areas.

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Let their edges be a and b.Then,a³/b³ = 1/27⇒ (a/b)³ = (1/3)³⇒ a/b = 1/3 --------------------(1)Therefore, Ratio of the surface area,⇒6a²/6b²⇒ a²/b²⇒ (a/b)²⇒(1/3)² [From (1)]⇒1/9⇒i.e. 1 : 9Ratio of the surface area= 1 : 9

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18.

Two cubes have their volumes in the ratio 1 27. Find the ratio of their surface areas.

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19.

Two cubes have their volumes in the ratio 1: 27.Find the ratio of their surface areas.

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20.

1.Two Cubes have their volumes in the ratio 1:27. Find the ratio of their surface areas.t than find the value ofk

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Let side of cube one = s1Let side of cube two = s2

V1/V2 = 1/27s1^3/s2^3 = 1/27

Then,s1/s2 = 1/3

Ratio of surface area of two cubesSA1/SA2 = 6*s1^2/6*s2^2 = (1/3)^2 = 1/9

Therefore ratio of surface area of two cubes is 1:9

21.

PLACE VALUEA. Tick (✓) the correct option.1. The smallest 6-digit number isa. 111111. b. 100001..100000.d. 1000000

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c. 100000 is correct please mark best

The smallest 6-digit number is 100000 answer (c)

the smallest 6-digit no. isoption c. 100000is correct

the smallest 6-digit no. is 100000-option=c

22.

5. A car can cover a distance of 357 km on 42 litres of petrol. How far can it travel on 12 litresof petrol?

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23.

27.If the ratio of the sum of the first n terms of two A.Ps is (7n+1): (4n +27), then find the ratio of theirhterms

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Given ratio of sum of n terms of two AP’s = (7n+1):(4n+27)We can consider the 9th term as the m th term.Let’s consider the ratio these two AP’s m th terms as am: a’m→(2)Recall the nth term of AP formula, an= a + (n – 1)dHence equation (2) becomes,am: a’m= a + (m – 1)d : a’ + (m – 1)d’On multiplying by 2, we getam: a’m= [2a + 2(m – 1)d] : [2a’ + 2(m – 1)d’]= [2a + {(2m – 1) – 1}d] : [2a’ + {(2m – 1) – 1}d’]= S2m – 1: S’2m – 1= [7(2m – 1) + 1] : [4(2m – 1) +27] [from (1)]= [14m – 7 +1] : [8m – 4 + 27]= [14m – 6] : [8m + 23]Thus the ratio of mth terms of two AP’s is [14m – 6] : [8m + 23].now substitute the value of m as 9so the answer becomes120/95

24.

14. Sum of digits of a two digit number is 8. If the number obtained by reversing the digitsis 18 more than the original number, then the original number is() 53(c) 26(a) 35(d) 62

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Let the digits in tens place be x and the digits in units place be y.Therefore, the original two digit number is 10x + y.Given that Sum of digits of a two digit number is 8.= > x + y = 8 ------- (1)Given that The new number increases by 18, when the digits are reversed.= > 10y + x = 10x + y + 18= > 10y - y = 10x - x + 18= > 9y = 9x + 18= > 9y - 9x = 18= > y - x = 2= > x - y = -2 ----- (2)-------------------------------------------------------------------------------------------------------On solving (1) & (2), we get= > x + y = 8= > x - y = -2-------------2x = 6x = 3.

Substitute x = 3 in (1), we get= > x + y = 8= > 3 + y = 8= > y = 8 - 3= > y = 5.

So,= > 10x + y= > 10(3) + 5= > 35.

Therefore, the original number = 35.c is the right answerplease accept it as best

25.

6.i 2 of a number is less than the original number by 10, the orithan the original number by 10, the original numbes(b) 60(a) 30(c) 36(d) 45

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26.

who is biggesLine es0universe

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Universe and line both are infinite

27.

1000 ml = ___ litres.

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1000 millilitres= 1 litre

1000 millilitres= 1 litre

28.

6product of two numbers is -15If one of the numbers is 39find the other numb9

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First converting both to improper fraction from mixed fraction we get the numbers as 140/9 and 28/9 respectively;Let the required no be y

then yx28/9=140/9=> y=(140x9)/(28x9)=> y=140/28=5Hence the answer is 5

29.

smallest 6 digit number

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The smallest positive 6 digit number is100,000.

thanks

30.

2. What percent is 150 ml of 3.5 litres?

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1000 ml in 1 litre1ml= 1/1000 so 350 ml= 1/1000*3500.35 litre 0.35/3.5*10010 percentage

31.

3. Write the predecessor of the smallest 6-digit number.

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The before number of any number is called its predecessor. If n be any number, then (n - 1) be its predecessor.

We know that, the smallest 6-digit number is100000Hence, its predecessor be

(100000 - 1)=99999

The predecessor of the smallest 6-digit numer (100000) is the largest 5-digit number (99999).

99999 is the answer of your question

32.

97. What per cent is 150 ml of 3.5 litres?

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First we have to convert both value in same dimensions. so 3.5*1000= 3500 mlnow 150*100/3500=15000/3500=4.2857%so the answer is 150ml water is 4% of 3.5 litre.

33.

By subtracting 1 from the smallest 6 digit number, which number would youget? How many digits would it be?( 10

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34.

Numb

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It isirrationalnumber because if we look upon on the definition ofrationalnumbers then :Rationalnumbers : The numbers which are in the form of p/q where p and q both are integers . In the above statement√5isnotan integer , so it isnot rationalnumber .

35.

isiirrational numb

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36.

recurring decim1.Write the fo237Irrational numb

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Please post complete question

37.

le he bigges numba6 9d) 25 4

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a) 9> 6b) 8>0c) 5>4

38.

pathule park has an arca of 305 m Find the dumensions dlA rectangular lawn 70 m by 50 m has two roads, each 5 m wide, runmingthrough itso its length and the other parallel to its breadth. Find the cost ofconstructing the roads at 120 per m

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39.

2018 फरवरी15गुरूवार

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-10

-10

ý

40.

\left. \begin array l \text (i) 93 \\ \text (i) 93 \\ \text (iii) 90 \end array \right.

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90 comes in between 89 and 91option 3

41.

rrange in columns and add13. 79 litres 85 ml, 35 litres 978 ml

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42.

C个L>h i25 cm

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The area of the shaded region is = Area of rectangle - area of ∆ = (25*14) -(1/2*25*14)= 350-175 = 175cm².

43.

A rectangular park 60 m long and 40 m wide hastwo concrete crossroads running in the middle ofthe park and rest of the park has been used as alawn. The area of the lawn is 2109 sq.m. what is thewidth of the road?

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44.

d.A rectangular park 60the middle of the park and rest of the park has been used as a lawn. If the areathe lawn is 2109 sq. m, then what is the width of the roadm long and 40 m wide has two concrete crossroads running

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thank

45.

andalsotheareluof3 A rectangular lawn 70 m by 50 m has two cross roads each 6 m wide running in the middle5.50the remaining sheetper squatto the length and other parallel to the breadth. Find the cost of levelling them at

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46.

he ar ea or the lawnThe length and breadth of a rectangular park are in the ratio 5:2. A 2.5-m-wide pathrunning all around the outside of the park has an area of 305 m2. Find the dimensions ofthe park.

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47.

Find the capacity in litres of a conical vessel with radius 7 cm, slant height 25 cm (ii) height 12 cm, slant height 13 cm

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48.

A rectangular field is 50 m by 40 m. I has two roads through its centre, runits sides. The width of the longer and the shorter roads are 2 m and 2.5-m-respectivelyFind the area of the roads and the area of the remaining portion of the fieledparallel to

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49.

A class room is 7m long, 6.5m wide and 4m high. It has one door 3m X 1.4m and three windows measuring 2m x 1m.The interior walls are to be painted. Find the cost of painting atthe rate of Rs 3.50 per m2

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Area of four walls of class= 2(l*h + b*h)= 2(7*4 + 6.5*4) = 2(28 +26)= 2(54) = 108 m^2

Area of window = 2*1 = 2 m^2

Area of door = 3*1.4 = 4.2 m^2

Area to be painted = 108 - 4*2 - 4.2= 108 - 12.2 = 95.8 m^2

Cost of painting= 95.8*3.50 = Rs 335.3

50.

28. A class room is 7m long, 6.5m wide and 4m high. It has one door 3m X 14m and threwindows measuring 2m x 1m. The interior walls are to be painted. Find the cost of painting atthe rate of Rs 3.50 per m2

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