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14. Sum of digits of a two digit number is 8. If the number obtained by reversing the digitsis 18 more than the original number, then the original number is() 53(c) 26(a) 35(d) 62 |
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Answer» Let the digits in tens place be x and the digits in units place be y.Therefore, the original two digit number is 10x + y.Given that Sum of digits of a two digit number is 8.= > x + y = 8 ------- (1)Given that The new number increases by 18, when the digits are reversed.= > 10y + x = 10x + y + 18= > 10y - y = 10x - x + 18= > 9y = 9x + 18= > 9y - 9x = 18= > y - x = 2= > x - y = -2 ----- (2)-------------------------------------------------------------------------------------------------------On solving (1) & (2), we get= > x + y = 8= > x - y = -2-------------2x = 6x = 3. Substitute x = 3 in (1), we get= > x + y = 8= > 3 + y = 8= > y = 8 - 3= > y = 5. So,= > 10x + y= > 10(3) + 5= > 35. Therefore, the original number = 35.c is the right answerplease accept it as best |
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