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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
51. एक बंदर किसी चिकने खंभे पर 1 मिनट में 9 मीटरऊपर चढ़ता है और दूसरे मिनट में 2 मीटर नीचेफिसल जाता है। बताएँ कि उस खंभे 60 मीटरकी ऊँचाई तक चढ़ने में उसे कितना समय लगेगा?(1) 16 मिनट (2) 16 मिनट(3) 16 मिनट (4) 16 मिनट |
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Answer» 16-4/9 16 -4/9 2 option |
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| 2. |
नी - ey NSRS23... रू0 5600 पर TP वार्षिक दर से ४ माह का साधारण ब्याज ज्ञातकीजिए |(को रू0 280 (= रू0 300हम) रू0 320 (=) T0 340 &) NOT. |
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Answer» साधारण ब्याज= मूलधन x दर x समय/१००यहां समय = ९/१२ साल=०.७५= 5000*20/3*0.75/100= 250 ruppes |
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| 3. |
6. If the dlameter ofa semici de protractor is 14find its perimeter. |
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Answer» d=14cmso perimeter=pie*d=22/7 * 14=44 cm |
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| 4. |
12. Find the perimeter of two books placed above each other each measuring 12 cm in length and10 cm in breadth |
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Answer» perimeter=2(l+b)=2(12+10)=2×22=44cm |
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| 5. |
| (C)340 रुपए (D)33 सपए3. A एक काम 10 दिन में करता है और Bवही काम 15 दिन में करता है। दोनोंमिलकर वही काम कितने दिन में करेंगे।(A) 5 दिन (B) 6 दिन |
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Answer» 5 दिन मे करते है 5 din me krega dono milkar 5 din me karega 5 din me karega 5 dine. karega |
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| 6. |
5. An elevator descends into a mine shaft at the rate of 6 metres per minute. If the descent 20 m above the ground level, how long will it take to reach - 340 m? |
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Answer» Considering the elevator to be at constant speed and the destination to be 350 m below ground level, The elevator has to travel 10m till the ground, then 350 m more. So, the total distance to travel is 360 m If the elevator's speed is 6 metres/minute,Then Time= Distance/Speed = 360/6 =60 minutes =1 hour Thus the elevator would take 1 hour to reach its destination. thanks a ton |
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| 7. |
400+50+300-200+6 |
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| 8. |
xample 8 : Show that 1.272727⌠= 1.27 can be expressed in the form, where pand q are integers and q * 0. |
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| 9. |
7 3 ml+52 ml3 |
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Answer» 7 3 ml+5 2ml=125ml |
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| 10. |
1. Add the following quntities(a) 31 86 ml and 7 200 ml |
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Answer» 1L = 1000mL3L 86 mL = 3. 086 L7L 200mL = 7.2 Ladditon gives (3.086 + 7.2) L = 10.286 L |
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| 11. |
-16mple 8 Convert the complexumber0into polar forum1+iv3 |
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Answer» here is your answer |
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| 12. |
4.Ifa-2, b=-2, find the value of:(i) a+ ab+b |
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Answer» 2square +-2square 4+48 |
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| 13. |
For the G.P. ifa=5, r=-2 find t_5 |
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| 14. |
11. IfA: C = 2:3 and B: C = 5:6, find A:B. |
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Answer» A/C=2/3,B/C=5/6. A/C*C/B=2/3*6/5=4/5. this is the correct answer |
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| 15. |
(i)Ifa _ _ 2, then find the value of a2+ a +1 |
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Answer» wrong answer a=-2 a2+a+1 =( -2)2+(-2)+1 = 4+(-1) =3 |
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| 16. |
-1 216. IfA=and B =h ' find X such that AX = B |
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| 17. |
[There are two books each of three volumes and two books each oftwo volumes. In how many ways can the ten books be arraged on atable so that the volumes of the same book are not separated.] |
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| 18. |
Heena lent 40960 to praveen at the rate of 6¼% per annum compound interest. find the amount payable by praveen to Heena after 3years |
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Answer» please like my answer if you find it useful |
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| 19. |
7. what sum of money will amount to? 21296 in 3 years at 10% per annum, compound.edannually? |
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| 20. |
Conversion of Units of CapacityConversion of Litres into Millilitresxample Convert the following into millilitres:(a) 8 l(b) 7 l65 ml |
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Answer» The answer for question no a is 8000ml 13 liters 25 milliliter |
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| 21. |
Which is larger (1.01)10000,000xample |
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| 22. |
-16xample 8 Convert the complex numberinto polar form1+iv3 |
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Answer» -16/(1+i√3)= -16(1-i√3)/(1+i√3)(1-i√3)= -16*(1-i√3)/(1+3)= (-16+i16√3)/4= -4+4√3i= 4(-1+√3i) in polar form r = 4*√1²+(√3)² = 4√(1+3) = 4*2 = 8 and ∅ tan-¹(√3/-1) = tan-¹(-√3) = -π/3 so, Z = 8cos(-π/3) + 8sin(-π/3) |
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| 23. |
16. tan-" ()+ tan-" () is equal to(a) I(c) 0,25. If cosequal toA |
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Answer» Answer:d)tan -1(1/2) |
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| 24. |
5. The roots of an equation x2 + 2x + 1 = 0 are.a. Equalb. Not equalc. Zercd. One |
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Answer» D=b^2 -4ac =(-2)^2-4(1) =4-4=0equal roots |
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| 25. |
2Ifa <0; b> 0 then a. b is equal to(d) none of the |
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| 26. |
6 340300in lowest term) |
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| 27. |
Do ThisCan you draw the angle of 60AllowedNot allowed90CompassA straight edgeProtractor |
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| 28. |
ond, in its lowest term:4.80 paise, 1.20 |
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Answer» 1.20 rupees means 120 paise so 80/1.20=80/120=2/3 2/3 is the correct answer of this question 80 paise is the lowest term 2upon3 entity passage the lowest term 80:1.20*100=80:120=40:60+4:6=2:3 |
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| 29. |
117. On a shelf there are 4 books on Economics, 3 books onManagement and 4 books on Statistics. In how manydifferent ways can the books be arranged so that thebooks on Economics are kept together?3)5040 |
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Answer» 3)50400 because I don't no😂😂😂😂😂 Books on Economics are to be kept together. Hence, we are to arrange 3 books on management, 4 books on Statistics and one book on Economics. These can be arranged in 8! ways. Again, 4 books on Economics can be arranged together in 4! ways. Therefore, Total number of arrangements =8!×4!= 967680 |
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| 30. |
In how many ways 21 English books and 19Hindi books can be arranged in a row suchthat no two Hindi books are together. |
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Answer» Let E - Position of English bookLet H - Position of Hindi book.In order to keep Hindi books that are never together, we must place all these books as:H E H E H E H .... H E HSince there are 21 books on English, we can choose 22 places to place 19 Hindi books.22C19=22C3= (22 x 21 x 20)/(3 x 2 x 1) = 1540 ways. |
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| 31. |
The weight of 56 books is 7 kg(a) What is the weight of 90 such books?(h) How many such books weigh 7.5 Kg? |
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Answer» 56 books=7kg1book=7/56=1/8kg(a) 90 books=1/8*90=11.25Kg7kg=56 books1 kg=56/7=8 books7.5kg=8*7.5=60 books thanks |
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| 32. |
ū Evaluate" U32412 – 516 |
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Answer» sqrt(37 + 12) - sqrt(16) = sqrt(49) - 4 = 7 - 4 = 3 |
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| 33. |
{4} 15 दिन57. एक दूध के डिब्बे में 35 लीटर दूध आ सकता है।| इसका भाग दूध से भरा हुआ है। 5 लीटर दूधबेचने के पश्चात इस डिब्बे में कितना और दूधडाला जा सकता है कि यह पूर्णतया भर जाए?(1) 25 लीट(2) 24 लीटर(3) 20 लीटर() लीटर |
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| 34. |
the amount of Rs. 1 5625 for 9 months at 16% per annum compoundFinded quartet(B) Rs 17675(C) Rs 1657517576 |
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| 35. |
4. The length of tangent from an extend point p' to a circle with centre 'o'is alwaysless than 'op' is this statement true ? Give reasons?a5 TĹĄ |
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| 36. |
“सर व 0०५ ० 22 i¢ Y =ine. e Mo o2- |
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| 37. |
4. The length of tangent from an extend point 'p' to a circle with centre 'o' is alwaysless than 'op' is this statement true ? Give reasons?DTR |
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| 38. |
e 1S: Find CI paid when a sum of t 10,000 is invested for I year andCxamms at 8% per annum compounded annually.mo |
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| 39. |
asin θ _ b cos θ-a2-b2e+bcos® a2 + b2If tanθa, prove thata sin |
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| 40. |
x^2+15x-2700 |
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| 41. |
What is the common difference of an APof which t 5n +1?(A) 7(C) 3(B) 5(D) 1 |
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Answer» Like if you find it useful |
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| 42. |
The sum of n terms of two A.Ps are in the ratio of (7n-5)(5n-17) . Then thethe two series are equal.term of |
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Answer» Let us assume that the two APs are: a1 + (n-1)d1 And a2 + (n-1)d2 Now the sum of these respective APs are n/2(2*a1 + (n-1)d1) n/2(2*a2 + (n-1)d2) Taking the ratio we get (2*a1 + (n-1)d1) : (2*a2 + (n-1)d2) = (7n-5) : (5n+17) Comparing the coefficients of n on the RHS with those in both the terms on the LHS, we get d1= 7 and d2= 5 Substituting these values in the equation and comparing the constants we get, a1= 1 and a2= 11 Therefore the series are 1,8,15,22,29,36,43,50,57,64,71…. And 11,16,21,26,31,36,41,46,51,56,61,66,71,76… So the series of numbers common in both APs is 36,71,106,141,176,211,…. Or (35n+1) where n is a natural number. 35 because it's the LCM of 7 and 5, the common differences of the APs. So the number of equal terms are infinite. |
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| 43. |
Q3. In the given figure if ABI |DE then x-a) 110°b) 1150c)120d) none of theseis |
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Answer» x=75°(alternate angle) |
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| 44. |
Q3. In the given figure if AB| |DE then x-a) 110b) 1150c)120d)none of theseSous |
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Answer» In triangle ABC, angle A+ Angle B +angle C=18075+50+angle C=180angle C=180-125angle C= 55Due to vertically opposite angles, angle C=55 in ΔCDE angle D+ angle E +angle C=180x+45+55=180x=180-100x=80 Hence, the answer is none of these |
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| 45. |
\begin{array}{l}{3+\frac{1}{\sqrt{4}-\sqrt{5}}+\frac{1}{\sqrt{5}-\sqrt{6}}+\frac{1}{\sqrt{6}+\sqrt{7}}+\frac{1}{\sqrt{7}+\sqrt{8}}} \\ {+\frac{1}{\sqrt{8}-\sqrt{9}}=?}\end{array} |
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| 46. |
\begin{array}{l}{\text { Simplify. }} \\ {\text { (a) } \frac{3}{7}+\frac{5}{7}-\frac{4}{7}} \\ {\text { (a) } 5-\frac{1}{6}+2 \frac{1}{3}} \\ {\text { (a) } 10-\frac{3}{4}-\frac{5}{8}}\end{array} |
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Answer» a) 3+5-4/7 = 4/7 b) 30-1+14/6 = 43/6 |
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| 47. |
a2 b2(i) 3x+2y = 5 ; 2x_3y = 7(ii) 2x-3y = 8 ; 4-6p=9 |
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| 48. |
eguatin.dn.ut Ď ranĺ-u/h ) |
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| 49. |
| नह पाई + [हि 503VIO PRS0 ———_ : .| +pus—psos o8 Xe 20l l |
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| 50. |
QuIS 68०3+ 100800 7= ==t pus0®0DT= 1" 08 T |
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Answer» Like my answer if you find it useful |
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