5. An elevator descends into a mine shaft at the rate of 6 metres per

1.	5. An elevator descends into a mine shaft at the rate of 6 metres per minute. If the descent 20 m above the ground level, how long will it take to reach - 340 m?
Answer» Considering the elevator to be at constant speed and the destination to be 350 m below ground level, The elevator has to travel 10m till the ground, then 350 m more. So, the total distance to travel is 360 m If the elevator's speed is 6 metres/minute,Then Time= Distance/Speed = 360/6 =60 minutes =1 hour Thus the elevator would take 1 hour to reach its destination. thanks a ton

5. An elevator descends into a mine shaft at the rate of 6 metres per minute. If the descent 20 m above the ground level, how long will it take to reach - 340 m?

Answer»

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,Then

Time= Distance/Speed = 360/6 =60 minutes =1 hour

Thus the elevator would take 1 hour to reach its destination.

thanks a ton