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-16xample 8 Convert the complex numberinto polar form1+iv3 |
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Answer» -16/(1+i√3)= -16(1-i√3)/(1+i√3)(1-i√3)= -16*(1-i√3)/(1+3)= (-16+i16√3)/4= -4+4√3i= 4(-1+√3i) in polar form r = 4*√1²+(√3)² = 4√(1+3) = 4*2 = 8 and ∅ tan-¹(√3/-1) = tan-¹(-√3) = -π/3 so, Z = 8cos(-π/3) + 8sin(-π/3) |
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