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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
4 Subtract:01) 28 from - 42-66 from -34[vit) -64 from o(ii) -36 from 42(v) 318 from 0(viti) -56 from 144() -37 from -53(vi) -153 from -240 |
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| 2. |
Example 17 Discuss the continuity of sine function. |
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Answer» sine function is continuous and differentiable at all values of x. Please hit the like button if this helped you |
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| 3. |
Example Discuss the continuity of the function fdefined by f(x)-x # 0. |
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| 4. |
If the H.C.F. of 65 and 117 is expressed in the form 65m- 117, then the valueof m is: |
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Answer» 65 = 5×13 117 = 3×3×13 HCF means common factors of both the numbers HCF = 13 65m - 117 = 13 65m = 117 + 13 65m = 130 m = 130/65 m = 2 If you find this answer helpful then like it. |
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| 5. |
If the HCF of 65 and 117 is expressible in the form 65m- 117, then find the valueof m. |
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Answer» Prime factors of 65 and 11765 = 5,13117 = 3, 3, 13 HCF of 65 and 117 is 13 Then,65m - 117 = 1365m = 130m = 130/65 = 2 |
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| 6. |
If the HCF of 65 and 117 is expressible in the form 65m-117, then the value of m is(A) 4(C) 1(B) 2(D) 3 |
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Answer» Thanks |
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| 7. |
हा et oR गाँव के 380 परिवारों की जोतों का आकार दिया गया है। जोत का मध्यिका आकार S जोतों का आकार (एकड़ में) | 100 से कम | 100-200 | 200-300 | 300-4001400 तथा उससे अधिक[उत्त-241:22 एकड़]जी के कक कक. अल |
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| 8. |
, जून वाज्शब कवबिं उइनोनिकॉल ;-49+14y+y? |
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Answer» y² + 14y + 49 y² + 2 × 7 × y + 7² ( y + 7)² |
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| 9. |
Example 11. Discuss the continuityfollowing at x = 0.1 - cosrf(x) =;x=02 |
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| 10. |
The length of a picture frame is 80 cm and its diagonal is 100 cm. Find its perimeter.1㏠|
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| 11. |
1. From a rope 11 m long, two pieces of lengthsof the remaining rope?100nd 3m are cut off. What is the length |
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| 12. |
12. Two lines AB and CD intersect each other at apoint o such that LAOC: ZAOD = 5:7. Find allthe angles. |
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Answer» AOC=DOB and AOD=COB5x+7x+5x+7x =360°24x=360°x=360°/24x=155x=75°7x=105° |
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| 13. |
23. Two equal sides of an isosceles triangle are 3x - 1 and 2x + 2 units. The third side is2x units. Find x and the perimeter of the triangle. |
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Answer» equal sides are 3x-1 and 2x+23x-1=2x+2so x=3so sides are 3x-1=8,2x+2=8 and 2x=6so perimeter=8+8+6=22 unit |
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| 14. |
(12Atu 10-5. What is the value of tangential acceleration in U.C.M.? |
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Answer» I don't know the answer of this question |
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| 15. |
unee Ď=unless stated otherwise.1. A drinking glass is in the shape of a frustum of acone of height 14 cm. The diameters of its twocircular ends are 4 cm and 2 cm. Find the capacity ofthe glass. |
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Answer» thanks bro |
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| 16. |
findtheIf HCF of 65 and 117 is expressible in the form 65n 117, thenvalue of n |
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Answer» Find the Hcf of 65 and 117 65 =5*13 117 =3*3*13 --------------------------------------H.C.F. of 65 and 117 = 13 according to question =>65m -117 = 13 =>65m = 13+117 =>65m =130 =>m =130/65 =>m=2 ANS. |
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| 17. |
If HCF of 65 and 117 is expressible in the form 65n - 117, then find thevalue of n |
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Answer» Prime factors of 65 and 11765 = 5, 13117 = 3, 3, 13 HCF of 65 and 117 = 13 Now,65n - 117 = 1365n = 130n = 130/65 = 2 Therefore, value of n = 2 |
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| 18. |
CISE 6.21. In Fig. 6.28, find the values of x and y and thenshow that AB Il CD.500什130°Fig. 6.28 |
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Answer» y=130°(vertically opposite angle)x=y=130°(alternate angle) |
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| 19. |
(i) 15x - 14y 11714x 15y 115 |
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| 20. |
5. h Fig. 6.32, if AB Il CD,<APQ50° and< PRD127°, find x and y. |
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| 21. |
From the adjacent figure, find the values ofi) sec θ, cosecθ and cot θii) cosec8x sin θiii) sec θ cos θiv) tan α>< cot α13cm12cmB 5cm |
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| 22. |
2. In Fig. 6.29, if AB Il CD, CDII EF and y:z-3:7,find x.Fig. 6.29 |
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| 23. |
Two lines AB and CD intersect at O such that BC is equal and parallel to AD. Prove thatthe lines AB and CD bisect at O.2. |
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| 24. |
to oltain a perfect cube.o 241() 100nd the st(i) 256d the smallest number by which each of the following numbers mobtain a perfect cube.must be divide1 Fio 8IGi) 128(iii)135iv) 192fplasticine of sides5cm,2 cm, 5 cm. Ho |
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| 25. |
Area of Parallelograms and Triangles | 209re and a rhombus stand on the same base, prove that the square has the largerIf a squaarea.5.In the figure, the angles BAD and ADC are right angles andAXBC, ifAB- BC5 cm andDC = 8 cm, calculate the area ofABC.A 5 cm B |
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| 26. |
Th н т о0 5 6 8.:: 5068 is the smallest number aThe reason is that 0568 is actually read as 568, which is a 3-placed at extreme left place.Exercise-5Fill in the boxes using>,<or= :(a) 2815 3890(b) 8592 8592(d) 8735 5648(e) 7305 8054(g) 9682 9589(h) 7605 7605(i) 4209 Fourthousand twenty-nine (k) 5056Encircle the greatest number:(a) 8815. 1587 7805 7688 3589 (b) 4476 |
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Answer» The correct answer is (a) <(b) =(d) >(e) <(g) >(h) =( j) > The correct answer is (a) <(b) =(d) >(e) <(g) >(h) =( j) > (a) 2815 < 3890(b) 8592 = 8592(d) 8735 > 5648(e) 7305 < 8054(g) 9682 > 9589(h) 7605 = 7605 |
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| 27. |
हर आओ ez U blie 1% 4/,.i—/—//"’I/OA |+ Ifl*l("j\" |
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Answer» -3 उस्का शुण्यक है, इस्लीये x=-३ पे f(x)=0 होगा,(k-1)(9)+k(-3)+1=0 9k-9-3k+1 =0 6k=8 k=8/6 =4/3 |
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| 28. |
Question numbers 1 to 6 carry 1 mark each.(1. Find the value of k for which the following pair of linear equations has a unique solution:2x + 3y = 7; (k- 1)x +(k + 2)y = 3k. |
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| 29. |
9.If the side of a square is -(x+1) units and its diagonal is3-*5units, then the value of xयदि वर्ग की भुजा = (x+1) यूनिट हो और उसका विकर्ण* यूनिट हो, तो ४ का मान ज्ञात कीजिए।[SSC CGL Mains -2015](b) 2 unit(c) 1 unit(d) 2 unitTot |
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Answer» Given,Side of Square S = (x + 1)/2 Diagonal of square = (3-x)/root(2) We know,Diagonal of square = side*root(2) Therefore,(3-x)/root(2) = [(x + 1)/2]*root(2)(3-x) = (x + 1)2x = 2x = 1 (C) is correct option |
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| 30. |
For what value of k, the equations 4x+ ky+80and 2x +y+4 0 have a unique solution? |
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Answer» guven equations will have unique solution if4/2 = k/1 = 8/4i.e. k=2 |
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| 31. |
(For what value of k, the equations 4x + ky + 8 = 0 and 2x+y+4=0 have a unique solution |
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Answer» Equations 4x + ky + 8 = 0 and 2x + y + 4 = 0 have unique solution Then,4/2 =/= k/1 Therefore,k =/= 2 |
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11: For what value of p the pair of linear equations(+ 2)-p+ y- 32p-and 2x-3y - 7has a unique solution. |
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Answer» The Given pair of linear equation is :(p+ 2)x - (2p + 1)y = 3(2p -1) ……….(1)2x- 3y = 7 ………….(2) On comparing with General form of a pair of linear equations in two variables x & y is:a1x + b1y + c1 = 0and a2x + b2y + c2= 0 a1= (p+2) , b1= - (2p+1), c= - (3(2p -1))a2= 2 , b2= -3 , c= -7 a1/a2= (p+2) /2 , b1/b2= -(2p+1)/-3 Given: A pair of linear equations has a Unique solution, ifa1/a2 ≠ b1/b2 (p+2) /2 ≠ -(2p+1)/-3-3(p+2) ≠ 2(-2p-1)-3p -6 ≠ -4p -2-3p + 4p ≠ - 2 +6p ≠ 4Hence, the value of p ≠ 4 |
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| 33. |
9. For which values of P does the pair of equations4x+Py + 8 = 0and2x + 2y + 2 = 0have unique solution. |
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| 34. |
0/15x-14y = 11714x-15y = 115 |
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| 35. |
(u) parallel to the y-axis and is at a distance of 4 units from it towardsnegative side of x-axis. |
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| 36. |
23. In the figure, diagonals AC and BD of a trapeziumABCD with AB Il CD intersect each other at OShow that ar (AAOD)ar (ABOC)cmj(CBSE March, 2012)Sol. Since ABCD is a trapezium in which ARILCD |
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| 37. |
unless stated otherwisedrinking glass is in the shape of a frustum of aof height 14 cm. The diameters of its twoconecirculaends are 4 cm and 2em Find the capacity ofthe glass |
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| 38. |
20.In Fig. 10.16, the angle BADand ADCare right anglesand AX is parallel to BC. If AB BC5 cm, andDC 8 cm. Calculate the area of ABCX.(SC)Fig. 10.16 |
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| 39. |
made a picture of an aeroplane with coloured paper as shown in Fig 12.15. Fina, Findthe total area of the paper used.5cm6emIV1.5cm6.5cmlem2emFig. 12.15triangle and a olt |
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| 40. |
(0)- cos x sln" xCây n do |
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| 41. |
Define tangential linear acceleration and write its formula. |
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Answer» Tangential acceleration is a measure of how the tangential velocity of a point at a certain radius changes with time. Tangential acceleration is just like linear acceleration, but it's particular to the tangential direction, which is relevant to circular motion. |
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| 42. |
and the value of:74411587V801405(iv) 172x2338 (v)45 x V20(ii)(iii)1625V1728 |
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Answer» (i)=4/9(ii)=21/25(iii)=23/24(iv)=156(v)=3/2 1.4/92.21/253.23/244.1565.3/2👍👍 |
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| 43. |
(1) V4U- V20valy vuuJ U4. Arrange surds in descending order |
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Answer» I)9√4,6√3,3√5 hope this will work |
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| 44. |
4. 1000000 is obtained, when a number issubtracted from the sum of 893645 and635489, find that number. JNV 2014]12. The val(1) 0.01 |
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Answer» Let number is x(893645+635489)-x=1000001529134-x=1000000x=1529134-1000000x=529314 |
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| 45. |
3. A die is thrown once. What is the probability of getting(i)(iii)a prime number?a number other than 2 and 5?(ii)a number greater than 2? |
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Answer» Total outcomes = 6probability of getting a prime number = 3/6 = 1/2Probability of getting a number greater than 2= 4/6 = 2/3probability of getting a no. other than 2 and 5 = 2/6 = 1/3 |
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| 46. |
The solution set of 'Ax-3 +-/2x + 3 = 6 is :(i) 37,9(iii) 3,9d)(ii) 111, 3(iv) none of these |
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Answer» Squaring both sides,(√(4x-3)+√(2x+3))²=36 Using identity (a+b)²=a²+b²+2ab 4x-3+2x+3+(2*√(4x-3)*√(2x+3))=366x+(2*√(8x²+12x-6x-9))=366x+(2*√(8x²+6x-9))=36Therefore, x=3,9(By putting value x=3,9 in LHS) wrong |
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| 47. |
If A = (sin x, 0); B = (0, cos x), then find the length of AB. |
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Answer» Distance AB is √ (sinx - 0)² + (0 - cosx)² √ sin²x + cos²x √ 1 1 |
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| 48. |
4.gram is 45º. Find the measure of the obtuse angle.ABCD is a trapezium such that ABCD, ZA:ZD = 2:1, ZB:ZC = 7:5. Find the angles of the trapezium.decon |
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Answer» ABCD is a trapezium....givenAB||CD...givenLet angle A=2x,B=7x,C=5x and D=x...from given and sayTherefore,AB||CD with transversal BCTherefore angle ABC+angle DCB=180°...interior anglesi.e. angle C+angle B=180°therefore 5x+7x=180°12x=180°x=15therefore angle A=2x=2×15°=30,B=7x=7×15=105°,C=5x=5×15=75° and D=x=15° HOPE IT HELPED U IF IT HELPED PLZ MARK AS BEST ANSWER |
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| 49. |
determine the value of k for which the given pair of linear equation has unique solution 2x -3y=1;kx+5y=7 |
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Answer» for unique solution a^1/ a^2 is no equal to b^1/b^2therefore the value of k is 7 2x-3y=1; 5(2x-3y=1)=10x-15y=5, 3(kx+5y=7)=3kx+15y=21;\\10x-3kx=16; 10-3k=16;16-10=3k; 6=3k; k=6/3=2 14 is the right answer. The value of k is not equal to 10/3 2x-3y=1; kx+5y=7; a1/a2=v1/b2#c1/c2; a1=2; b1=3; a2=k, b2=-5, 2/k=3/-5; 2x-5/3=k; -10/3=K |
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| 50. |
Perimeter of a square of side x units is sameas the circumference of a circle of radius yunits. Obtain a linear equation in x and y, onthe basis of given information. |
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Answer» perimeter of square 4xcircumference of a circle = 2πygiven both are equal so4x = 2πy2x = πy2x - πy = 0 Thnk u |
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