1.

determine the value of k for which the given pair of linear equation has unique solution 2x -3y=1;kx+5y=7

Answer»

for unique solution a^1/ a^2 is no equal to b^1/b^2therefore the value of k is 7

2x-3y=1; 5(2x-3y=1)=10x-15y=5, 3(kx+5y=7)=3kx+15y=21;\\10x-3kx=16; 10-3k=16;16-10=3k; 6=3k; k=6/3=2

14 is the right answer.

The value of k is not equal to 10/3

2x-3y=1; kx+5y=7; a1/a2=v1/b2#c1/c2; a1=2; b1=3; a2=k, b2=-5, 2/k=3/-5; 2x-5/3=k; -10/3=K



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