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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
what number should we multiply (2-3) so that the product may be equal2. Byt the nroduct may be equal to |
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| 2. |
O) Ifthe sum of the zeroes of the quadratic polynomial(x) kx+ 2x + 3k is equalto their product, find the value of k. |
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| 3. |
19. The cost and revenue functions of a product are given by C(x) = 20x + 4000 andRG) = 60x + 2000 respectively, where x is the number of items produced and sold. Howmany items must be sold to realise some profit? |
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Answer» s We have, profit = Revenue – Cost = (60x + 2000) – (20x + 4000) = 40x – 2000 To earn some profit, 40x – 2000 > 0 ⇒ x > 50 Hence, the manufacturer must sell more than 50 items to realise some |
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| 4. |
3. The students at the center found many linear functions. Find an equationfor each line.a. The line passes through the points (0. 8) and (4. 1.3)b. The line has slope -3 and passes through the point (1. 4).c. The line passes through points (1, 1) and (3,9). |
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Answer» (1)points are (0,8) and (4,13)y-13=((13-8)/(4-0))(x-4)y-13=(5/4)(x-4)4y-52=5x-205x-4y=-32 (2)m=-3 and point (1,4)(y-4)=-3*(x-1)y-4=-3x+33x+y=7 (3) points are (1,1) and (3,9)y-9=((9-1)/(3-1))(x-3)y-9=(8/2)(x-3)y-9=4x-124x-y=3 |
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| 5. |
an angle of 45' at the initial point of a given ray and jusitfy the constraction |
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| 6. |
Construct an angleof 90 at the initial point of a given ray nd justity the |
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| 7. |
. Construct an angle of 90° at the initial point of a given ray and justify the construction. |
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| 8. |
How many factors of 108 is / areprime number? |
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| 9. |
8. Find (a) of |
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| 10. |
Construct an angle of 90 at the initial point of a given ray and justify the construction. |
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| 11. |
at number must be added to each term ofthe ratio 4:5, so that it may become equal to5: 6? |
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| 12. |
Costruct an angle of 450 at the initial point of a given ray and justify the construction |
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| 13. |
Factorise x^{3}+13 x^{2}+32 x+20 |
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| 14. |
If n(A) = n(B) = 3, Then how many bijective functions from A to B can be formed? |
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Answer» hence 3!=6 |
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| 15. |
If n(A) = n(B) = 3, Then how many bijective functions from A to B can be formed. |
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Answer» hence 3!=6 |
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| 16. |
A decimal fraction is multiplied by itself. Ifthe product is 51.84, find the fraction |
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| 17. |
An exterior angle of a triangle is 130° and one of the interior opposite angles is 45e. Findthe other two angles of the triangle.(4) |
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Answer» angle adjacent to exterior angle [130°]=180°-130°=50°one angle is 45°sum of angles of a triangle is 180°if a b c are anglesa=45°b=50°c=?a+b+c=180°45°+50°+c=180°95°+c=180°c=180°-95°=85° |
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| 18. |
X. Prove that, “If a side of a triangle is produced, then the exterior angle so formed is equal to thesum of the two interior opposite angles." |
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| 19. |
Prove that the total number of selections thatcan be made out of the letters of the phrase"daddy did a deadly deed" is 1919.How many different factors can 1155 have? |
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Answer» there are 9 D,3 E,3 A,2 Y,1 L and 1 I. there are 10 ways of selecting D,4 ways of selecting both A and E,3 ways of selecting Y and 2 ways of selecting L and I. only one case is there in which we can select none of the given alphabets. =10 * 4* 4* 3* 2* 2 -1 =1920-1 =1919 that's all |
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| 20. |
5. Prove that : If a side of a triangle is produced, then theexterior angles so formed is equal to the sum of the twointerior opposite angles. |
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| 21. |
1. If ( | m and t is a transversal such that the two interior opposite angles are 2xanis the value of x?3x2x |
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Answer» 2x +3x = 180° ( linear pair)5x = 180°x = 180°/5x = 36° |
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| 22. |
aj2k11. The angle of projection at which the horizontal range and maximum height ofprojectile are equal isBCECE-2003](d)60l luihing a narabolic path. Wh(a)45 (b)0-tan (0.25)(e)略 antaor (8-760) |
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| 23. |
(b) Discuss different steps in theconstruction of range chart3 |
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Answer» 1 2 3 4 5 |
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| 24. |
gilTay and justify the construction.Construct an angle of 45 at the initial point of a given ray and justify the construction |
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| 25. |
EXERCISE 11.1I Construct an angle of 90' at the initial point of a given ray and justify the constructionand iustify the construction |
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| 26. |
\text { calculate HCF }\3 ^ { 3 } \times 5 \text { and } 3 ^ { 2 } \times 5 ^ { 2 } |
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| 27. |
Calculate:1/2 of 5 m in cm |
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Answer» Ans :- 1/2 of 5 m =1/2 × 5 = 5/2 = 2.5 m 1 m = 100 cm 2.5 m = 100 × 2.5 = 250 cm |
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| 28. |
longwill73. If 5 men can do a certain construction work in 14 days, then howmen taketo complete the same construction work? |
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Answer» 5 men can do in 14 daysTotal amount of work=5×14=70 man-daysSo 7 men will take 70/7 =10 days to complete the same construction work |
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| 29. |
Define bijective function. |
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Answer» Ans :- In mathematics, a bijective function or bijection is a function f : A → B that is both an injection and a surjection. This means: for every element b in the codomain B there is exactly one element a in the domain A such that f(a)=b. |
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| 30. |
Define Analytic function with an example. |
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Answer» In mathematics, an analytic function is a function that is locally given by a convergent power series. There exist both real analytic functions and complex analytic functions, categories that are similar in some ways, but different in others. |
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| 31. |
bulitut à given ray and justify the construction.Construct an angle of 450 at the initial point of a given ray and justify the construction.struct the angles of the folu |
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| 32. |
f3. The exterior angle of a triangle is 120° and oneof the interior angles is 309. The measure ofthe other interior opposite angle is |
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Answer» By using interior angles theorem 120- 30 = 90 degrees. You can solve all questions |
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| 33. |
. Show that for any two odd positive integers a and b, tdivisible by 4. |
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| 34. |
If the two interior opposite angles of a triangle are in ratio 4:5 and the exterior angle is 108. Find the measure of two interior angles. |
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Answer» 4x+5x=108x=12Angles are 48° and 60° |
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| 35. |
find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively?in detail |
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| 36. |
ths of the diagonals of a rhombus are 16 cm and 12 cn respectively. DFind the length of each of its sides. |
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| 37. |
4. The sum of two integers is –30. If one of the integers is 15, determine the other. |
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Answer» Let the other integer be x, Sum of that integers = -30 15 + x = -30 => x = -30 -15 => x = -45 Hence, other integer is -45 |
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| 38. |
2.Findthefollowingratiosinsimplestfor( 35: 105216:64 |
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Answer» 35:105 = 1/3216:64 = 108/32 = 54/16 = 27/8 |
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| 39. |
OF TU-TUTTUA5. If there are a negative integers and 4 positive integers what will be the sign of their product. |
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| 40. |
Graph the function Y = 5 + 3x. What is the slope of the function? |
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Answer» comparin the equation with y = mx +c , the coefficient of x will give the slope of the line. so, slope is 3. |
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| 41. |
8. Find the remainder when p(x)=x-62° +147-3 is divided by g(x) = 1 - 2r anverify the result by long division. |
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Answer» don't know.............................. another part is more |
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| 42. |
Find the sum and the difference of the identity function and themodulefunction |
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| 43. |
7. Find the HCF of 65 & 117 and express it in the form of 65m + 117n. |
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| 44. |
9.Ravi earns twice as much in Januaryas in each of the other months. Whatpart of his annual earnings he earns inthat month? |
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Answer» suppose in each month he earns xso in Januuary he earns 22xso total yearly 33xso he earns=22/33=2/3 in that month. |
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| 45. |
7. Find the HCF of 65 & 117 and express it in the form of 65m+ 117n. |
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Answer» Like if you find it useful |
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| 46. |
7.Find the HCF of 65 & 117 and express it in the form of 65m+ 117n. |
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Answer» Euclid's Division Lemma :-a = bq +r 117 > 65 117 = 65 × 1 + 52 ----> [ 2 ] 65 = 52 x 1 + 13 -----> [1] 52 = 13 x 4 + 0 HCF = 13 13 = 65m + 117n From [ 1] ,13 = 65 - 52 x 1 From [2] ,52 = 117 - 65 x 1 ----> [3] Hence , 13 = 65 - [ 117 - 65 x 1 ] ------> from [3] = 65 x 2 - 117 = 65 x 2 + 117 x [-1 ] m = 2n = -1 |
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| 47. |
0"+10y + 24) รท(v+4) |
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| 48. |
Verlily the tollowing60: 105 : : 64 : 147 |
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| 49. |
Integers4. Subtract:(i) 28 from -42(iv) -66 from -34(vii) -64 from 0(i) -36 from 42(v) 318 from 0(viii) -56 from 144(iii) -37 from -53(vi) -153 from -240 |
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| 50. |
Whose surface area is 154 cm.100 cmnd tht Teter of the moon is approximately one fourth ofdiamd the ratio of their surface arcas |
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