Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ह-.......... 5. उस गोले का आयतन ज्ञात कौजिए जिसका सम्पूर्ण पृष्ठ 452 4 वर्ग सेमी है। : |
| Answer» | |
| 2. |
Pationalise the ofenominator6+452 |
| Answer» | |
| 3. |
5. Prove that452 is an irrational number. |
| Answer» | |
| 4. |
5.Prove that 452 is an irrational number |
| Answer» | |
| 5. |
16) In the given figure, APQRSA3.5 cm3.5 cm452045°RY5 cm5 cm |
|
Answer» triangle pqr congruent to triangle xyz ∆PQR congruent to ∆XYZ Congruent to triangle XZY |
|
| 6. |
8. There are 65 – pieces of wood whichneed to be painted with blue colour. Theamount of paint within a bucket is enoughfor 5- pieces of wood. How many bucketsof paint are required in all? |
|
Answer» Total pieces of wood = 131/2 23/4 pieces of wood can be painted by one bucket of paint Therefore,To paint 131/2 pieces amount of paint required= 131/2 ÷ 23/4= 131/2 * 4/23= 11.39 buckets |
|
| 7. |
A 60-litre tank was full of oil. Sam used 40% of it and poured therest into a 40-litre tank.(1) What per cent of the 40-litre tank was filled with oil? |
|
Answer» Capacity of 1stTank =60 litres.Amount of oil used by Sam=40% of 60 litres. =(40/100)*60 litres. =24 litres. Amount of oil left = (60 - 24) litres = 36 litres. Amount of oil that was left, was poured in 2ndtank with capacity 40 litres.Now,Percentage ofoil in 2nd tank=(36/40)*100 %= 90 %. |
|
| 8. |
More with Multiplication and DivisionA tank is full of 300 L of water. How much water willbe filled in 25 tanks? If 15 buckets can be filled withone tank of water, how many buckets in all can befilled with the water in 25 tanks? |
| Answer» | |
| 9. |
10. Findthree rational numbers betuKational humbes between 3 and 45 5 |
|
Answer» 13upon20, 14upon20, 15upon20 Since we have to find 5 rational numbers between 3/5 and 4/5, so we will mutiply the numerator and denominator of the given numbers by 5+1, i.e. equal to 6.We get, 3/5=(3×6)/(5×6)=18/30 4/5=(4×6)/(5×6)=(24/30) Now, we have to find 5 rational numbers between 18/30 and 24/30, which will come as (19/30),(20/30),(21/30),(22/30),(23/30)(19/30),(20/30),(21/30),(22/30),(23/30) Thus, five rational numbers between 3/5 and 4/5 are=(19/30),(2/3),(7/10),(11/15)and(23/30) |
|
| 10. |
A man donates 10 aluminumcm and has its upper and lowest ends of radius 36 cm and 21 cm respectively, Find the cost ofpreparing 10 buckets if the cost of aluminum sheet is Rss 42 per 100 cm2. Write your comments onthe act of the man.buckets to an orphanage. A bucket made of aluminum is of height 20 |
|
Answer» Find the surface area of 1 bucket: Surface Area = π(R - r)√[(R - r)² + h²] Surface Area = π(36 - 21)√[(36 - 21)² + 20²] Surface Area = 375π cm² Find the surface area of 10 buckets: 1 bucket = 375π cm² 10 buckets = 375π x 10 = 3750π cm² Find the cost: 100 cm² = Rs 42 3750π cm² = 42/100 x 3750π = Rs 4950 |
|
| 11. |
A man donates 10 aluminum buckets to an orphanage. A bucket made of aluminum isof height 20 cm and has its upper and lowest ends of radius 36 cm and 21 cmrespectively. Find the cost of preparing 10 buckets if the cost of aluminum sheet is42 per 100 cm2. Write your comments on the act of the man. |
|
Answer» Answer: Rs 4950 Step-by-step explanation: Find the surface area of 1 bucket: Surface Area = π(R - r)√[(R - r)² + h²] Surface Area = π(36 - 21)√[(36 - 21)² + 20²] Surface Area = 375π cm² Find the surface area of 10 buckets: 1 bucket = 375π cm² 10 buckets = 375π x 10 = 3750π cm² Find the cost: 100 cm² = Rs 42 3750π cm² = 42/100 x 3750π = Rs 4950 Answer: The cost is Rs 4950 hit like if you find it useful |
|
| 12. |
The compound interest, calculated yearly, on a certain surm of money for thesecond year is? 1,320and for the third year is 1,452 Calculate the rate of interestand the original sum of money |
| Answer» | |
| 13. |
The compound interest, calculated yearly, on a certain sum of money for thesecond year is 1,320 and for the third years? 1 452 Calculate the rate of interestand the original sum of money. |
| Answer» | |
| 14. |
uu I 10 morelc 7 hours to cover a certain distance at the sped of 4s km/hr I the spetlhiewere added tuo uicin.t7. A car takeshowmuch time will it take to cover the same distance? |
|
Answer» Let the distance be X from question , x = 7*48 = 336km now if the speed is decreased by 20km/h , the new speed is 48-20 = 28km/h so the time will be T*28 = 7*48 => T = 48/4 = 12hrs. |
|
| 15. |
A hemispherical tank full of water is emptied by a pipe at the rate of 25/7 litre per sec .How much time will it take to empty half the tank if it 3 in diameter ? |
|
Answer» Diameter = 3mradius = 3/2 = 1.5 m volume=2/3πr^3volume=2/3*3.14*1.5^3=7065litre emptying rate = 25/7 l per secondlet the time taken to empty half volume = t 25/7*t=1/2*volumet=989seconds. Is the answer is correct |
|
| 16. |
))If x = t2-1 ,find the value of x2 |
|
Answer» wrong ans |
|
| 17. |
r 1. Find the common difference of the AP V3,T2. |
|
Answer» common difference(d)= A2-A1 d=a2-a1 = √12-√3= √9 =3 |
|
| 18. |
et6=90] x p-⏠âTR |
|
Answer» 3.14 * 10^6= 314*10^-2*10^6= 314*10^[6-2]= 314*10^4= 3140000 ans |
|
| 19. |
चुन त्दु ते दR TR कद X™ ¢ ~ 0 |
|
Answer» 12,24,36,48 is your answer my friend |
|
| 20. |
4. In figure. S and T are points on the sides PQ and PR respectively of ΔPQR such thatPT = 2 cm. TR = 4 cm and STI QR. Find the ratio of areas of ΔPST and ΔPQR.R. |
| Answer» | |
| 21. |
अल ही...TR B_——-evwl——bq‘y_fim_fi__l__b——————-’q""' 2 e | |
| Answer» | |
| 22. |
A sum when reckoned at 7 1/2% per annum amounts to? 3920 in 3 years. Find the sum |
|
Answer» Simple interest (s.i.) =( p×r×t)/100 Where p = principalr = rate of interest per annumt= time in years In this case,Amount (A)=3920, r= 7.5% t = 3Amount (A) = p + s.i. => 3920 = p+ prt/100=> p = 3200 |
|
| 23. |
calculated at 72% per annum anwhenmounts to3920 in 3 years. Find the sum. |
|
Answer» 3920=P+P*3*7.5/1003920=P(1+0.225)so P=3920/1.225=3200 |
|
| 24. |
15. A sum when reckoned at 72 % per annum amounts to3920 in 3 years. Find the sum. |
|
Answer» simple |
|
| 25. |
न 6. सिद्ध कीजिए-- अं * 6-८051 0 न2 आए 7 9-1it TN |
|
Answer» sint*sint*sint*sint - cost*cost*cost*cost a*a - b*b = (a+b)(a-b) using this we can write like following way (sint*sint+cost*cost)(sint*sint-cost*cost) now sint*sint + cost*cost = 1 and cost*cost = 1 - sint*sint = (1)*(sint*sint - (1 - sint*sint)) = sint*sint - 1 + sint*sint = 2sint*sint - 1 If you find this answer helpful then like it. |
|
| 26. |
(3)If in an A. P, d = 10, findtr |
|
Answer» In an A.P, tn=a+(n-1)dt6=a+(6-1)d =a+5d t2=a+d So,t6-t2=(a+5d)-(a+d) = 4d =4(10) =40 |
|
| 27. |
9] =dg—x¢ ‘g = 4% (TN |
| Answer» | |
| 28. |
दि e 'a‘m- हों समीकरण ज्ञात कीजिए जिसके'(क). यदि समीकरण »* -+- 20 के मुल ०, 9 हों तो वह स bl 2T Qo+ )TN +FDEL o शा |
| Answer» | |
| 29. |
9. A committee is to consist of 4 men and 3 women. How many different committeesare possible if 7 men and 5 women are eligible ?Tn how many wavs |
|
Answer» total men=7total women=5 men required=4women required=3 total combinations = ⁷C₄*⁵C₃ =(7*6*5/3*2)(5*4/2)=35*10=350 |
|
| 30. |
12. किसी कूट भाषा में eat good food को ke la pa लिखा जाता है,good quality को pa jo लिखा जाता है तथा eat less को ke raलिखा जाता है। इसमें food के लिए कोड क्या है ? |
| Answer» | |
| 31. |
In acceptance sampling, when there is a finite probability that the lot may be acceptedeven if the quality is not really good, is called -a) Consumer's riskc) Operator's riskb) Producer's riskd)Owner's risk |
|
Answer» (Ans:a) consumer's risk is the correct option. |
|
| 32. |
Iff (x)="tr + c,findf, (0) |
|
Answer» Differentiating with respect to xf'(x)=m f'(0)=m |
|
| 33. |
Find the value of x4144-5 (41-3x3.(i)囹49街3xTr+ 73-7542x+1 ÷16=64(ii)(iii) |
| Answer» | |
| 34. |
4TrFind the remainder when 3x- 4x3- 3x 1 is |
|
Answer» if it is divisible then put X=1 in equation hence3(1)^4-4(1)^3-3(1)-1=3-4-3-1=-1-4=-5hence -5 is the remainder |
|
| 35. |
6 BEST is a parallelogram. Find the values ofx, y and z.TrQ.1 |
| Answer» | |
| 36. |
.A sum when reckoned 7 % per annum amounts tr23920 in 3 years. Find the sum. |
| Answer» | |
| 37. |
SNReaction |
|
Answer» The SN2 reaction is a type of reaction mechanism that is common in organic chemistry. In this mechanism, one bond is broken and one bond is formed synchronously, i.e., in one step. SN2 is a kind of nucleophilic substitution reaction mechanism. TheSN2 reactionis a type ofreaction mechanismthat is common inorganic chemistry. In this mechanism, one bond is broken and one bond is formed synchronously, i.e., in one step. SN2 is a kind ofnucleophilic substitutionreaction mechanism. Sincetworeacting species are involved in the slow (rate-determining) step, this leads to the termsubstitutionnucleophilic (bi-molecular) orSN2, |
|
| 38. |
17 9-bathpx.tsx.thナSheas--that-Pas.. |
| Answer» | |
| 39. |
tho aiven quontttie eqidistant ssieginning and the end is enalehtIlanenitent |
|
Answer» Let B,E be the constant beginning and end respectively and let b,e,d be variables for any of the two numbers and their equidistance from the beginning and end. Then: b=B+d e=E−d So the arithmetic mean is b+e2=B+d+E−d2=B+E2 Which is constant. |
|
| 40. |
In fig., a sector OAP of a circle is shown with centre Ocontaining 20. AB is perpendicular to the radius OAand meets OP produced at B. Prove that the perimeterof shaded region is r-l tan θ + sec θ + 100-11[All India 2016]o0A |
| Answer» | |
| 41. |
4(ann) 14 |
|
Answer» 24 will be the answer How? |
|
| 42. |
uahe tn |
| Answer» | |
| 43. |
0)T TNрдк*) > > % Y |
| Answer» | |
| 44. |
If Sn= 5n2+ 2n, find Tr? |
|
Answer» S1=5(1)^2+2(1)=5+2=7and S2=5(2)^2+2(2)=5(4)+4=20+4=24henceSn=n/2(2a+(n-1)dwhen n=17=1/2(2a)=ahence a=7henceS2=2/2(2*7+d)=2424=14+dd=10hence Tn=a+(n-1)dhenceT =7+(n-1)*10 |
|
| 45. |
if Sn=2n2+n then find t2 |
|
Answer» thanks |
|
| 46. |
in an AP if Sn=4n-n2 then d is |
|
Answer» Sn=4n-n²a₁=S₁=4-1=3S₂=a₁+a₂4*2-(2)²=3+a₂4=3+a₂a₂=1 d=a₂-a₁d=1-3=-2 thanks |
|
| 47. |
If in an AP an 5-6n then find Sn |
| Answer» | |
| 48. |
b < \/A\TN\QJ |2 |
| Answer» | |
| 49. |
.. 1-cosxlim ——x—0 X |
|
Answer» lim x->0 (1-cosx)/(x*x) If we put x = 0 we will get 0/0 form so using L'hospital rule lim x->0 sinx/2x If we put x = 0 we will get 0/0 form so using L'hospital rule lim x->0 cosx/2 = cos0 / 2 = 1/2 If you find this answer helpful then like it. |
|
| 50. |
In a△ABC, <ABC 100°, <BACfind ZC and length DC.35° and BD丄AC meets side AC in D. If BD = 2 |
| Answer» | |