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tho aiven quontttie eqidistant ssieginning and the end is enalehtIlanenitent |
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Answer» Let B,E be the constant beginning and end respectively and let b,e,d be variables for any of the two numbers and their equidistance from the beginning and end. Then: b=B+d e=E−d So the arithmetic mean is b+e2=B+d+E−d2=B+E2 Which is constant. |
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