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ans. (A) 24°

thanks

10000(1+10/100)²

= 10000*11*11/10*10

= 121*100

= 12100

i) x^5 + 9x³ - 7x² + 2x

ii) 8p⁴ - 7p² + 19p

Tn = 6n +5

=> a +(n-1)d = 6n +5

=> a +(n-1)d = 11 + 6n - 6

=> a +(n-1)d = 11+ 6(n-1)

Comparing both sides, we get

a= 11

d = 6

Sn = n/2 [ a + Tn]

= (n/2) ( 11+6n +5)

= (n/2) (6n +16)

= n(3n + 8)

= 3n^2 + 8n

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GivenSn = n^2 - 5

Then sum of (n - 1) termsSn-1 = (n - 1)^2 - 5

tn = Sn - Sn-1 = n^2 - 5 - (n-1)^2 + 5 = n^2 - 5 - n^2 - 1 + 2n + 5 = 2n - 1

I=A-PI=4410-3600I=810

T=I*100/P*RT=810*100/3600*9T=810/36*9T=90/36T=2.5years

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sin²63 + sin²27------------------------cos²17 + cos²73

sin² 63 + sin²(90 -63)---------------------------------cos²17 + cos²(90 - 17)

sin²63 + cos²63------------------------cos²17 + sin²17

1/1

1

n=1 is correct answer

1 is correct answers 😗😗

n=1 is the correct answer

According to question n ÷ n = 1 is validfor all whole number except 0 as 0 ÷ 0 is not defined

(i) 0.9 lies between 0 and 1. It is closer to 1.(ii) 0.6 lies between 0 and 1. It is closer to 1.

(p-19)(p+2)p^2+2p-19p-38p^2-17p-38this is the required equation

sahi answer he ae but ae aapko maja nahi aayega long rit ki he isne

3 is the right answer

LAMDA=3is right answer

Let Rohit age be Xhence his mother will be 5xsum is 66henceX+5x=666x=66X=11years-RohitHence mother will be 5x=5*11=55years

Let rohits age=xMothers age=5xSum of their age=66=(x+5x)Or,6x=66X=66/6=11So rohits age=x=11Mothers age=5x=5*11=55

let Rohit age be X his mother age will be 5x sum of their ages is 66hence X+5x=66 6x=66X=11yearsRohithence his mother age is 5x=5*11=55years

(3a + 4b ) (3a - 4b ) = 3a ^2 - 4b^2 = 9a^2 - 16b ^2

ER. RAVI KUMAR ROY

when a = -1 and b = 1LHS..(3*-1 + 4*1)(3*-1 - 4*1)= (1)(-7) = -7RHS..9*(-1)^2 - 16*1 = 9 - 16 = -7LHS = RHS ( VERIFIED)

same answer as above is right

A:B=4:5*7B:C=7:6*5:-A:B=28:35:-B:C=35:30:-A:B:C= 28:35:30

28:35:30 is the correct answer of the given question

A:B=4:5x7B:C=7:6x5:-A:B=28:35:-B:C=35:30:-A:B:C=28:35:35

A:B:C =28:35:30 is right answer

A:B=4:5*7B:C=7:6*5=A:B=28:35=B:C=35:30=A:B:C=28:35:30

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A:B:C =28:35:30 is the best answer 💥

answer is 28:35:30please do like it

Ans :-Let the tens digit be x and the units digit be y.So the number=10x+yA.q.=>x=2y(equation 1)After interchanging the digits we get10y+xAlso,=>(10x+y)+(10y+x)=66=>10x+y+10y+x=66=>11y+11x=66=>11(y+x)=66=>y+x=66/11=>y+x=6Frim equation 1 x=2ySo, y+2y=6=>3y=6=>y=6/3=>y=2And x=2(2)=4Hence the number is 42.

the equation becomes n/n = n => n= n² so n-n²= 0=> n(1-n) = 0 so n = 1.

root((asint-0)^2+(0-acost)^2)=root(a^2sin^2t+a^2cos^2t)=root(a^2)=a

p is not =r but it is logical equivalent

Option D is the correct answer of your question 7

Given,x - y = 5........(1)xy = 66x = 66/y........(2)

Put value of x from eq(2) in eq(1)66/y - y = 566 - y^2 = 5yy^2 + 5y - 66 = 0y^2 + 11y - 6y - 66 = 0y(y + 11) - 6(y + 11) = 0y = - 11, 6

For y = - 11x - (-11) = 5x = 5 - 11 = - 6

For y = 6x - 6 = 5x = 11

Therefore, possible values of x and y are (-6, - 11) and (11, 6)

tq

Let there is a circle having centre O touches the sides AB and AC of the triangle at point E and F respectively.Let the length of the line segment AE is x.Now inΔABC,CF = CD = 6 (tangents on the circle from point C)BE = BD = 6 (tangents on the circle from point B)AE = AF = x (tangents on the circle from point A)Now AB = AE + EB=> AB = x + 8BC = BD + DC=> BC = 8+6 = 14CA = CF + FA=> CA = 6 + xNows = (AB + BC + CA )/2=> s = (x + 8 + 14 + 6 +x)/2=> s = (2x + 28)/2=> s = x + 14Area of the ΔABC =√{s*(s-a)*(s-b)*(s-c)} =√[(14+x)*{(14+x)-14}*{(14+x)-(6+x)}*{(14+x)-(8+x)}] =√[(14+x)*x*8*6] =√[(14+x)*x*2*4*2*3]=> Area of the ΔABC = 4√[3x(14+x)] .............................1Now area ofΔOBC = (1/2)*OD*BC =(1/2)*4*14 = 56/2 = 28Area ofΔOBC = (1/2)*OF*AC =(1/2)*4*(6+x) = 2(6+x) = 12 + 2xArea ofΔOAB = (1/2)*OE*AB =(1/2)*4*(8+x) = 2(8+x) = 16 + 2xNow Area of the ΔABC = Area ofΔOBC +Area ofΔOBC +Area ofΔOAB=>4√[3x(14+x)] = 28 + 12 + 2x + 16 + 2x=>4√[3x(14+x)] = 56 + 4x=>4√[3x(14+x)] = 4(14 + x)=>√[3x(14+x)] = 14 + xOn squaring bothe side, we get3x(14 + x) = (14 + x)2=> 3x = 14 + x (14 + x = 0 => x = -14 is not possible)=> 3x - x = 14=> 2x = 14=> x = 14/2=> x = 7HenseAB = x + 8=> AB = 7+8=> AB = 15AC = 6 + x=> AC = 6 + 7=> AC = 13So value of AB is 15 cm and value of AC is 13 cm

p implies q= p⟹q≡¬[p∧¬q]p⟹q≡¬[p∧¬q]

for example : consider a statement P:If it is raining then it is cloudy. A common misperception is that this means that cloudiness causes rain, or that rain causes cloudiness. Neither is the case. [Edit: It just means that,at a given instant in time, it is not both raining and not cloudy. There is no suggestion of the passage of time or an historical record.]

Raining⟹Cloudy≡¬[Raining∧¬Cloudy]

for n=2, statement is not valid

yes it is correct answer

for n=2statement is not valid

Sorry, for n=0 statement is not valid

0 will not valid in this ststement

n=2 statement is not valid

correct answer isx = a, y = b

please like and accept as best answer

x + y=a+b, ax-by=a^2-b^2. given system of equation x+y-(a+b)=0 , ax-by-(a^2-b^2)=0, a1=1, b1=1, c1=( a+b); a2=a, b2=-b; c2=-( a^2-b^2); X| b1 c1 = y| c1 a1 =1/a1 b1, x=-a( a+b)/-(a+b); x=a; y=-b/(a+b)/ -( a+b); y=b:

X=a y=bCorrect answerPlease like and accept answer

x=a & y= b is the right answer.

Let numbers are x and (x + 5).Ass pe given condition

1/x - 1/(x + 5x) = 1/10(x + 5 - x) / x(x +5) = 1/105*10= x^2 + 5xx^2 + 10x - 5x - 50 = 0x(x +10) - 5(x + 10) = 0(x + 10)(x - 5) = 0x = - 10, 5

Numbers are :if first number = 5 then second number = 10If first number= - 10 then second number= - 5