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In a two digit number, digit at the ten's place is twice the digit at units'splace. If the number obtained by interchanging the digits is added to theoriginal number, the sum is 66. Find the number. |
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Answer» Ans :-Let the tens digit be x and the units digit be y.So the number=10x+yA.q.=>x=2y(equation 1)After interchanging the digits we get10y+xAlso,=>(10x+y)+(10y+x)=66=>10x+y+10y+x=66=>11y+11x=66=>11(y+x)=66=>y+x=66/11=>y+x=6Frim equation 1 x=2ySo, y+2y=6=>3y=6=>y=6/3=>y=2And x=2(2)=4Hence the number is 42. |
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