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let numbers be 8x and 3x.

according to question,

8x+3x=14311x=143x=13

so numbers are 8×13=1043×13=39 ans

1st no. is 104 and second no. 39

let the numbers are 8x and 3x A. T. S. 8x+3x=143 11x=143 x=143/11 x=13therefore the numbers=8x13=104 3x13=39

8x ,3x is correct answer

3x,4x is correct amswer

39 is the right answer

let the x is included in the rationumber=8x and 3xthen,8x+3x=143 11x=143 x=13number=8x=8×13=104and other number=3x=3×13=39

let numbers be 8x and 3x.according to question.8x+3x=14311x=143x=13

so numbers are 8×13=1043×13=39answer

let's take number be x:

8x+3x-14311x-143x-143/11x-13

therefore,: 8into 13-104 3into13-39

so two numbers are 104 and 39 as 104+39-143

X+Y=143Y=(143-X) .....(1)

X/Y=8/3 X/(143-X)=8/3 ; putting value of (1)X=104✔Y=(143-104)=139✔

5

is correctly answer plz like my

104 and 33 is answer for this question

let the no be 8x and 3xnow 8x+3x=143or,11x=143or, x=13so, no will be 8x=1043x=39

Let the ratio factor be X. first number = 8Xsecond number = 3X

A/Q

8X + 3X = 14311X = 143X = 143 / 11 = 13

first number =8X= 8 x 13 = 104second number =3X= 3x13= 39

104 39 is answer for this question

104 and 39 is the best answer

39 is right answer ......

8x+3x=14311x=143 x=13

Let the two numbers be 8x and 3x respectively

according to question ,

8x+3x = 143=> 11x = 143=> x= 143/11 => 13

x = 13 then ,=> 8x = 8(13) => 104=> 3x = 3(13) => 39

the two number are 94 and 39

104. 39 is answer for this question

104 and 39 is the right answer

104 and 39 is answer for this question

one no. is 104 and second no. is 39

104 and 39 is answer for this question

The first number be= 8/11*143=104&the second number be=3/11*143= 39

39 is the correct answer

and other is 94 which is 1st no.

one no.is 104 and second is 39

104 and 33 is the right answer

the no.s are 104 and 39

let the first no. be = 8xsecond no. = 3xthe give no.= 146therefore,8x + 3x = 14611x= 146x=146/11answer=13

therefore, first no. = 3x =3*13 =39second no.=8x=8*13=104

the nos are 104 and 39

39 is right answer

plz like my answers I like yours

let xand y be the two no.8/3=x/y8y=3xx+y=1433/8y+y=143y=104x+104=143x=39

8x+3x=143x=143/11=13

numbers are 8x=8×13=104✔🇮🇳3x=3×13=39✔🇮🇳

Let the two numbers be 8x and 3x respectively

according to question ,

8x+3x = 143=> 11x = 143=> x= 143/11 => 13

x = 13 then ,=> 8x = 8(13) => 104=> 3x = 3(13) => 39

hope this helps

the ratio =8:3the sum of the numbers=1438x+3x=14311x=143x=13

104 and 39 is the correct answer

let the no. are 8× and 3+× 8×+ 3×=143. ×=13 so numbers are 8×13=104 and 3×13 =39

104 & 39 is the right answer

Let the 1st no. be x

8x + 3x = 143

11x = 143

x = 143/11

x = 13

Hence ,

8x = 8×13 = 104

3x = 3×13 = 39

39 is the right answer

the numbers are 104 and 39

8x+3x=143, 11x=143, x=143/11=13 , so number are 8×13=104, 3×13=39. because let number is 8x and 3x

GK only no mathmatics

8x+3x=143, 11x=143, x=143÷11=13 , because let let number is 8x and 3x ,so number are 8×13=104 , 3×13=39 ; this is the right answer

39 is theright answer

the correct answer 104 and 39

39 is the correct answer of following question

Let the ratio ne 8x and exTheir sum is 143Therefore,8x+3x=14311x=143x=143/11x=138x=8×13=943x=3×13=39Hence the two numbers are 94 and 39

104 and 39 is the right answer

109 and 39 is the right answer

8 ratio = 1043 ratio is = 3939+104= 143

Let the two numbers be 8x and 3x respectively

according to question ,

8x+3x = 143=> 11x = 143=> x= 143/11 => 13

x = 13 then ,=> 8x = 8(13) => 104=> 3x = 3(13) => 39

39 is the correct answer

8x+3x=11x ,11x = 143 ,13

8/3+x=143x=143×3/8x=53

8x+3x=14311x =143x =143/11x =13hence, the number is 13

104 and 39

correct answer for this question

39 is the correct answer

8x + 3x = 14311x = 143 x = 143 / 11x = 138x = 8 × 13 = 943x = 3 × 13 = 39please mark me as best

11x=143so, x=13now the numbers are 104 and 39

39 is the right answers

the required numbers are 104 and 39

LET THE NUMBERS BE 8x AND 3x.THEREFORE, 8x + 3x=14311x=143x=143/11x=13THEREFORE THE NUMBERS ARE 8x=8×13=104 and 3x=3×13=39.CHECK104+39=143THEREFORE CHECKED

let the numbers be 8x and 3x therefore,8x+3x=143so,11x=143x=143/11x=13therefore the numbers are8x=8×13=143and,3x=3×13=39CHECK BY104+39=143hence checked

than first namber 104 and second number 39

let number be 8X and 3X

8*+3*=1433*13=39

1st no.is 13 and 2nd answer is 39

let the numbers be 8x and 3x

8x+3x=14311x=143x=13

so the numbers are8x+3x=1043×13=39 ans

one no.is 143 and other is 39

The numbers are are 104 and 39

39 is the correct answer to this question

Let the numbers be 8x and 3xtherefore,8x + 3x = 14311x = 143x = 143/11x= 13therefore the numbers are 8x =104, 3x = 39.

let the ratios be xa/qthe sum of the ratios = 143so8x+3x=14311x=143x=143/11x=118x= 11×8 =883x= 11×3 = 33so the first no. = 88 and the second no.=33

104 and 39 are the two numbers

Two number ratio 8x and 3xThe sum of number=1438x+3x=14311x=143x=143/11x=13 ans

Distance covered in 1 litre of petrol=55.3 km

Distance covered in 10 litre of petrol=55.3×10 km=553 km

Given:Let the number be x and yx+y=74..(1)x=10+y..(2)substitute (2) in (1)(10+y)+y=7410+2y=742y=74-102y=64y=32

substitute in (1)32+x=74

x=74-32=42

Thus the two numbers are 42& 32

x + 1 / x - 1 + x - 2 / x + 2 = 4 - 2x + 3 / x - 2

Taking lcm we get

(x + 2)(x + 1) + (x - 1)(x - 2) / (x -1) ( x + 2) = 4(x - 2) - (2 x + 3) / x - 2

x^2 + 3x + 2 + x^2 - x - 2x + 2 / x^2 + x - 2 = 2x - 11 / x - 2 = 2x - 11 / x - 2

2x^2 + 4 / x^2 + x - 2 = 2x - 11 / x - 2

2x^3 - 4x^2 + 4x - 8 = 2x^3 + 2x ^2 - 4x - 11x^2 - 11x + 22

5x^2 + 19x - 30 = 0

5x^2 + 25x - 6x - 30 = 0

5x( x + 5) - 6( x + 5) = 0

(x + 5)( 5 x - 6) = 0

x + 5 = 0, 5 x + 6 = 0

x = - 5 , x = 6 / 5

Option B is correct.

h=2π/rh=2*22/7*7h=22 cm

that salary increasing 10%simple this original salary is 154 rupees

two x kha se aya

is correct answer ...

13/17<4/17. is the correct answer

1.insert the symbol <,>or = in each circle a answered b >d < e <g <h <

2. arrange in descending order b 3/5>2/5>1/5c 9/11>6/11>5/11d 22/13>12/13>10/13e 23/23>13/23>11/23

3. arrange in ascending order b 1/4<3/4<7/4c 6/6<11/6<16/6d 8/8<9/8<11/8e 1/9<6/9<7/9

volume of cube is side^3hence when side is 24cmhencevolume =(24)^3=13824cm^3

9x = 8x9x - 8x = 0x=0

5x + 4 - 6x - 3x - 35x - 6x - 3x + 4 - 35x - 9x + 1- 4x + 1

Given,radius, r = 20 cmslant height, l = 15 cmNow,curved surface area of cone= πrl= π x 20*15= π x 300= 300π

2x4- 3x3- 3x2+ 6x - 2

easy

you know how to divide polynomials right?? ofcourse you know, you're X

you mentioned two of its roots were√2 and -√2

hence the factors are (x -√2) and (x+√2) since x=√2 and x= -√2

if you multiply both you'll get x2- 2

when you divide2x4- 3x3- 3x2+ 6x - 2 byx2- 2 since it is divisible by2x4- 3x3- 3x2+ 6x - 2please like the solution 👍 ✔️

the quotient will turn out to be 2x2- 3x + 1

Now lets factorise this equation,

=>2x2- 3x + 1=0

=>2x^2 -2x -1x + 1 =0

=>2x(x - 1) -1(x - 1)=0

=>(2x - 1)(x - 1)=0

therefore 2x - 1=0 or x-1=0

which implies x=1/2 or x=1

here you have it the remaining two roots

Hope you get it

total area=Πr²h +2Πr

total area= πr²h+2πr

total area =πr²h +2πr

The curved surface area of a cone=C=πrl=πr√(h²+r²)where h, l and r are the height, slant height and radius of the cone.Volume of the cone=V=πr²h/3∴3πVh³-C²h²+9V²=3π{(πr²h)/3}h³-{πr√(h²+r²)}²h²+9(πr²h/3)²=π²r²h⁴-π²r²(h²+r²)h²+9π²r⁴h²/9=π²r²h⁴-π²r²h⁴-π²r⁴h²+π²r⁴h²=0 (Proved)

please like the solution 👍 ✔️

1). complement of 45 = 90 - 45 = 452). a= bq + r

Things which are equal to the same thing are equal tooneanother.If equals are added to equals, the wholes are equal.If equals are subtracted from equals, the remainders are equal.

complement of 45°=90°-45°=45°

according to euclids 3rd axiom,If equals be subtracted from equals, the remainders are equal.it is given that a=b and a-c=25.at the same time if b is subtracted from same c so a,b equals are subtracted from c .hence the remainders will be same.therefore b-c=25.First Axiom: Things which are equal to the same thing are also equal to one another.

it is blur

Quotient is

x2+2x+1

Compare the equation withax2+ bx+ c= 0

We get

a = 1 ,b=2 c= 1

To factorize the value we have to find two value which

sum is equal to b= 2

product isa*c=1*1 = 1

1 and 1 are required values which

sum is1 + 1= 2

product is1 * 1= 1

So we can write middle term2x= x+ x

We get

x2+ x + x + 1 =0

x (x +1) +1(x +1) = 0

( x + 1)( x + 1)= 0

x+1 = 0 , x+1= 0

x= -1 , x= - 1

so our zeroes are

- 1-1 , √(5/3) and- √(5/3)

p(x)=3x4+6x3-2x2-10x-5

as we have given that two of its zeroes are root5/3 and -root5/3. so their factors are;

(x-root5/3) and (x+root5/3). the product of the factors ;

(x-root5/3) (x+root5/3)=x2-5/3

=3x2-5/3=1/3(3x2-5)

where k=1/3

now g(x)=3x2-5

dividing p(x) by g(x) we get

q(x)=x2+2x+1

by division algorithm;

p(x)=g(x)*q(x)+r(x)

=(3x2-5)(x2+2x+1)

=(3x2-5)(x2+x+x+1)

=(3x2-5)(x(x+1)+1(x+1)

=(3x2-5)(x+1)(x+1)

the other two zeroes are -1 and-1

i not understand this formula

any more formula to get answer

Let number be x x-(14/100)*x=516x - 14/100 *x =516,50x -7x /50 =516,43x/50 =516,x = 516 *50/43x=600

Given polynomial= 2x^3 + 2x

For x = - 1 value of polynomial= 2(-1)^3 + 2(-1)= 2*-1 - 2= - 2 - 2= - 4

The mirror image is option 3

kyu hai option 3 deatil m btyo

Thanks for the answer

36+15=51=3×179+39=48=3×1628+83=111=3×37so missing number is 37.

The other zeroes are 2 and -1/2....

-1 is one zeroesso x= -1x+1=0 is a factor2x^3-x^2-5x-22x^3+2x^2-3x^2-3x-2x-22x^2(x+1)-3x(x+1)-2(x+1)(x+1)(2x^2-3x-2)= polynomial2x^2-3x-2=02x^2-4x+x-2=02x(x-2)+1(x-2)=0(x-2)(2x+1)=0either x-2=0, x=22x+1=0, x= -1/22, -1/2& -1 are the zeroes

-1 is zeroesso x+1 is a factor of 2x^3-x^2-5x-2x+1)2x^3-x^2-5x-2(2x^2-3x-2 2x^3+2x^2 -. --------------------------- -3x^2-5x-2 -3x^2-3x +. + ------------------- -2x-2 -2x-2 +. + ------------+(x+1)(2x^2-3x-2)= 2x^3-x^2-5x-22x^2-3x-2=02x^2-4x+x-2=02x(x-2)+1(x-2)=0(x-2)(2x+1)=0x-2=0, x=22x+1=0, 2x= -1, x= -1/22, -1,2 & -1 are the zeroes

The coefficient of x² is (d)4

x²y-3xy/y=x²y/y -3xy/y=x²-3x=x(x-3)