Find all the zeroes of 2x1 -3x -3x +6x -2, if two of its zeroes are 2

1.	Find all the zeroes of 2x1 -3x -3x +6x -2, if two of its zeroes are 2 and -.
Answer» 2x4- 3x3- 3x2+ 6x - 2 easy you know how to divide polynomials right?? ofcourse you know, you're X you mentioned two of its roots were√2 and -√2 hence the factors are (x -√2) and (x+√2) since x=√2 and x= -√2 if you multiply both you'll get x2- 2 when you divide2x4- 3x3- 3x2+ 6x - 2 byx2- 2 since it is divisible by2x4- 3x3- 3x2+ 6x - 2please like the solution 👍 ✔️ the quotient will turn out to be 2x2- 3x + 1 Now lets factorise this equation, =>2x2- 3x + 1=0 =>2x^2 -2x -1x + 1 =0 =>2x(x - 1) -1(x - 1)=0 =>(2x - 1)(x - 1)=0 therefore 2x - 1=0 or x-1=0 which implies x=1/2 or x=1 here you have it the remaining two roots Hope you get it

Find all the zeroes of 2x1 -3x -3x +6x -2, if two of its zeroes are 2 and -.

Answer»

2x4- 3x3- 3x2+ 6x - 2

easy

you know how to divide polynomials right?? ofcourse you know, you're X

you mentioned two of its roots were√2 and -√2

hence the factors are (x -√2) and (x+√2) since x=√2 and x= -√2

if you multiply both you'll get x2- 2

when you divide2x4- 3x3- 3x2+ 6x - 2 byx2- 2 since it is divisible by2x4- 3x3- 3x2+ 6x - 2please like the solution 👍 ✔️

the quotient will turn out to be 2x2- 3x + 1

Now lets factorise this equation,

=>2x2- 3x + 1=0

=>2x^2 -2x -1x + 1 =0

=>2x(x - 1) -1(x - 1)=0

=>(2x - 1)(x - 1)=0

therefore 2x - 1=0 or x-1=0

which implies x=1/2 or x=1

here you have it the remaining two roots

Hope you get it