Obtain all the zeroes of 3x4+6x3-2x2-10x-5.If two of its zeroes are -1

1.	Obtain all the zeroes of 3x4+6x3-2x2-10x-5.If two of its zeroes are -1 & 1
Answer» Quotient is x2+2x+1 Compare the equation withax2+ bx+ c= 0 We get a = 1 ,b=2 c= 1 To factorize the value we have to find two value which sum is equal to b= 2 product isac=11 = 1 1 and 1 are required values which sum is1 + 1= 2 product is1 * 1= 1 So we can write middle term2x= x+ x We get x2+ x + x + 1 =0 x (x +1) +1(x +1) = 0 ( x + 1)( x + 1)= 0 x+1 = 0 , x+1= 0 x= -1 , x= - 1 so our zeroes are - 1-1 , √(5/3) and- √(5/3)

Obtain all the zeroes of 3x4+6x3-2x2-10x-5.If two of its zeroes are -1 & 1

Answer»

Quotient is

x2+2x+1

Compare the equation withax2+ bx+ c= 0

We get

a = 1 ,b=2 c= 1

To factorize the value we have to find two value which

sum is equal to b= 2

product isa*c=1*1 = 1

1 and 1 are required values which

sum is1 + 1= 2

product is1 * 1= 1

So we can write middle term2x= x+ x

We get

x2+ x + x + 1 =0

x (x +1) +1(x +1) = 0

( x + 1)( x + 1)= 0

x+1 = 0 , x+1= 0

x= -1 , x= - 1

so our zeroes are

- 1-1 , √(5/3) and- √(5/3)