This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(in) The lengths of sides of a rectangle are 5 cm and 3.5 cm. Find the ratio of itsperimeter to area. |
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| 2. |
Michael borrowed 16000 from a finance company at 10% per annum, compoundedhalf-yearly. What amount of money will discharge his debt after 1 years?2 |
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| 3. |
(iv) The lengths of sides of a rectangle are 5 cm and 3.5 cm. Find the ratio of itsperimeter to area. |
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Answer» length=5cmbreadth=3.5cm perimeter : area2(l+b) : l×b2(5+3.5) : 5×3.52(8.5) : 17.517 : 17.517 : 175/10170 : 17534 : 35 area of rectangle are 170perimeter of rectangle 175170:17534:35 Length=5cmBreadth = 3.5cmPerimeter::Area2(L+B)::LxB2(5+3.5):5x3.52(8.5):17.517:175/10170:17534: 3534/35 the answer is 17.5 because the reactance area Length =5 cm Breadth =3.5cm Perimeter : area 2(l+b): l×b 2(5+3.5 ):5×3.52(8.5):17.5/1017:175 |
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| 4. |
CieaI lHe debt?Find the compound interest on ( 10000 in 2 years at 4% per annum, the interestbeing compounded half-yearly.17.18 Ifthe simnle interest nn |
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Answer» a |
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| 5. |
SECTION B. The anyles of a quadrilateral are in the tatio 1:2:3:4.Find the sntallest and the largest angle. |
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| 6. |
16. By what number shouldbe multiplied to get 427 |
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Answer» thanks |
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| 7. |
D) g T2xâ0 X |
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| 8. |
है... साकृति 10:36 मे, केन्द्र 0 चाले एक वृत्त£BOC=30° T4 £ AQB = g0 यदिमर तीन बिन्दु ७.७ और इस प्रकार हैं किहै, तो ८8100 ज्ञात कीजिए।चाप 80 के अतिरिक्त वृत्त पर 9 एक बिन्दु |
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| 9. |
0=6+F+%) (T2 (1M |
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Answer» answer is -1 |
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| 10. |
24(18 + x)-241 18the quadratic formula, we geting48 t4-48 Âą 602Since a is the speed of the sta1:-54. Therefore, x = 6 gives th241. Find the roots of the followicompleting the square:(i)2-7x+3=0(iii) 4x2 + 4V3x + 3 = 02. Find the roots of the quadratiformula |
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| 11. |
1. Find the ratio of:a. 10 m to 25 cmd. 3.2m to 56 m |
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| 12. |
Bela borrowed 25,000 from a finance company to start her boutique at 20%unt of money will clear her debtper annum compounded half-yearly. What amount of money will ciesafter 1years? |
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| 13. |
is56cm,findtheThe ratio of two sides of a parallelogram is 4:3. If its perimeterlengths of its sides. |
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Answer» T Thank's bro 😊☺ |
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| 14. |
0) The difference between two numbers is 26 and one number is three times the other.0Find them.OSntoey anyles evceeds the smaller by 18 degrees. Find |
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Answer» let no.s be x and y x-y=26 x=3y 3y-y=262y=26y=13 x=3yx=3×13x=39 |
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| 15. |
60 kg 240 g divided by 12 |
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Answer» Explanation : 1 g = 0.001 kg 60 kg 240 g = 60.240 kg (60.240)/12 = 5.02 kg = 5 kg 20 g Solution : 5 kg 20 g If you find this answer helpful then like it |
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| 16. |
1) 3 > l s l e 3 ŕ¤ŕĽ * |
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| 17. |
İRY THESE. Find angle x in each figure40° |
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Answer» Concept : When opposite side are equal then opposite angles are equal.So, x = 40° |
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| 18. |
Find the supplement ry angle of 105 |
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Answer» The supplement of angle 105° = 180° - 105° = 75°. |
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| 19. |
LFhĂŠangles ofa quadrilateral are in the ratio 1 :2:34. Find the smallest and the largest angle |
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Answer» Let the angles of quadrilateral are x, 2x, 3x, 4x Sum of all angles of quadrilateral = 360 Then,x + 2x + 3x + 4x = 36010x = 360x = 36 Angles of quadrilateral are36, 72, 108, 144 Therefore smallest angle = 36largest angle = 144 |
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| 20. |
if A matrix of oder 2×3 and B is a oder 3×5 then what is the oder of matrix (AB)' or (AB)¹? |
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Answer» As order of A is 2×3 and order of B is 3×5 Order of (AB) is 2×5, Order ( AB)' = 5×2 |
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| 21. |
The altitude of triangle are 12, 15, 20 unit. Find the measure of the largest angle. |
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| 22. |
If the angles of a triangle are in the ratio 2:3:7 then the largest angle is |
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| 23. |
The difference between two numbers is 26 and one number is three times the oderFind thenmThe larger of two supplementary angles exceeds the smaller by 18 degrees Finhem |
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Answer» let the smaller angle be xand the larger be yy=x+18y-x=18y+x=1802y=198y=9999+x=180x=81 let two numbers be x and yx-y=26x=3y3y-y=262y=26y=13x=3*13x=39x=39,y=13 |
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| 24. |
. The angles of a quadrilateral are in the 56ratio 1:2:3:4. The largest angle is: |
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Answer» press the picture and then see the answer for more clarity |
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| 25. |
\left. \begin{array} { l } { _ { 5 } 410 \text { by } 8 \% } \\ { g 240 \text { by } 12 \frac { 1 } { 12 } \% } \end{array} \right. |
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| 26. |
Eolle o n.% L__54__{_3_5_4__;“_{42.%__&»_6.%"‘&;_‘\’b"‘S |
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| 27. |
3 L =42 |
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Answer» 3L = 42 L = 42/3 L = 14 |
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| 28. |
“४” Ry G 7.t ee |
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| 29. |
A2 4 s -7 0]3, खालील एकसामयिक समीकरणे क्रेमरच्या पदुधतीने\ Ry -4y =10 ;4x + 3y =5 |
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Answer» Part1 पर्यायी पद्धतीच्या मदतीने आम्ही याचे निराकरण केले |
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| 30. |
लिन जला हा नह 201 7 &> Ry - 8% ARश्र . X 0.35 + 0.15 x 0.15 +2 % 0.35 X 0.15 |
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| 31. |
Recall, is defined as the ratio of the circumference (say c) of a circle to its diameter(say d). That is, π--. This seems to contradict the fact that π is irrational. How willyou resolve this contradiction? |
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Answer» There is no contradiction. When we measure a length with scale orany other instrument, we only obtain an approximate rational value.We never obtain an exact value. For this reason, we may not realisethat eithercordis irrational. Therefore, thefractionc/d is irrational. Hence, π is irrational. Woops Thanks 😋😊 |
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| 32. |
SECTION7 The angles of a quadtrilateral are in the ratio 12:34 Find the smallestthe largest anglery |
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Answer» Let the angles be x,2x,3x and 4x. x+2x+3x+4x=36010x=360x=36 Smallest angle=x=36Largest angle=4x=4×36=144 |
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| 33. |
एक दुकानदार के पास 45 घड़ी खरीदने के लिए पूरी रकम है जबकि एक घड़ी के!मूल्य 427 रु है। यदि वह 122र अधिक मूल्य वाला घड़ी खरीदना चाहे तो उततीही रकम में वह कितनों धड़ियाँ खरीदेगा दर |
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Answer» thanks |
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| 34. |
8. 28.314 - 31:427 +113.928 = ? + 29.114( बैंक पी०ओ० परीक्षा, 2010| 00101 |
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Answer» 28.314 - 31.427 + 113.928 = ? + 29.114 Let number to find be x142.242 - 31.427 = x + 29.114x = 142.242 - 60.541x = 81.701 Therefore, missing number is 81.701 |
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| 35. |
7/6 of a leap yearweek(a) 427(c) 61(b) 35(d) 13 |
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Answer» 1 leap year = 366 days 7/6 of leap year = 7/6*366 = 61*7 days = 61 weeks. |
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| 36. |
₹4000 पर 5 %की वार्षिक दर से 2 वर्षों में चक्रवर्ती ब्याज क्या होगा (a)410(c)420(b) 421(d) 427 |
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| 37. |
(3) Observethe following figure. If thesome current be induced in the coil B? Explain.current in the coil A is changed, will |
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Answer» It is because when the current in your coil A is successfully changed, then the magnetic field linked with it also changes. Hence, the overall magnetic field around the coil B also alters. This kind of change in the magnetic field the lines around coil B actually induces the electric current in this field. It is known as electromagnetic induction. |
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| 38. |
e lirst ree lens.How many 3-digit numbers are divisible by 7 ? |
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Answer» first = 105last = 994so , Tn = a+(n-1)dHere , 994 =105+(n-1)7or , 7(n-1)=994-105or , 7(n-1)=889or , n-1=127or , n=128 . 3 digit no are 100 to 999a= 104d=7ln=994let n be the term a+(n-1)d=on104+(n-1)×7=9947n-7=994-104=8897n= 889+7=896n= 896/7=128total no of term = 128 Numbers begin from 105 ....... 994 here a= 105l= 994n=?d= 7so994 = 105+(n-1) 7= 105+7n-7994= 98+7n994-98 = 7n896/7 = nn= 128 So , 128 three digit numbers are divisible by 7 Least 3 digit number divisible by 7 is 105The biggest 3 digit number divisible by 7 is 994 Sn= a+(n-1)d=>994= 105+(n-1)7=>7(n-1)= 889 {994-105=889}=>n-1= 127=> n=128... The first number =105,last number=994,last term= a+(n-1)d,994=105+(n-1)7,889=(n-1)7,127=n-1,n=126 |
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| 39. |
10. PQRS is a parallelogram. T is the midpointof PQ (Fig. 11.18). ST bisects ZS. Provethata) QR = QT b) RT bisects ZRc) ZSTR = 90°Fig. 11.18 |
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Answer» We have,PQRS as the given parallelogram, then PQ∥RS and PS∥QR.Since PQ∥RS and TS is a transversal, then∠PTS = ∠TSR (Alternate interior angles) . ....(1)Now, TS bisects ∠S, then∠PST = ∠TSR ........(2)From (1) and (2), we get∠PTS = ∠PSTIn ∆PTS,∠PTS = ∠PST (Proved above) ⇒PS = PT [Sides opposite to equal angles are equal] .........(3) But PS = QR (opposite sides of parallelogram are equal) ........(4) PT = TQ (As T is the mid point of PQ) ..........(5) From (3),(4) and (5), we getQR = TQIn ∆TQR,QR = TQ (Proved above)⇒∠QTR = ∠QRT [angles opposite to equal sides are equal] ......... (6)Since PQ∥RS and TR is a transversal, then∠TRS = ∠QTR (Alternate interior angles) .........(7) From (6) and (7), we get∠QRT = ∠TRS⇒TR bisects ∠R. Now, ∠R + ∠S = 180° [Adjacent angles of ∥gm are supplementary] ⇒12∠R + 12∠S =90°⇒∠TRS + ∠TSR = 90° .......(8)I In ∆TSR,∠TRS + ∠TSR + ∠RTS = 180° [Angle sum property]⇒90° + ∠RTS = 180°⇒∠RTS = 90° We have,PQRS as the given parallelogram, then PQ∥RS and PS∥QR.Since PQ∥RS and TS is a transversal, then∠PTS = ∠TSR (Alternate interior angles) .....(1) Now, TS bisects ∠S, then ∠PST = ∠TSR ........(2) From (1) and (2), we get∠PTS = ∠PSTIn ∆PTS,∠PTS = ∠PST (Proved above) ⇒PS = PT [Sides opposite to equal angles are equal] .........(3) But PS = QR (opposite sides of parallelogram are equal) ........(4) PT = TQ (As T is the mid point of PQ) ..........(5) From (3),(4) and (5), we getQR = TQIn ∆TQR,QR = TQ (Proved above) ⇒∠QTR = ∠QRT [angles opposite to equal sides are equal] .........(6) Since PQ∥RS and TR is a transversal, then ∠TRS = ∠QTR (Alternate interior angles) .........(7) From (6) and (7), we get∠QRT = ∠TRS⇒TR bisects ∠R. Now, ∠R + ∠S = 180° [Adjacent angles of ∥gm are supplementary] ⇒12∠R + 12∠S =90°⇒∠TRS + ∠TSR = 90° .......(8)I In ∆TSR,∠TRS + ∠TSR + ∠RTS = 180° [Angle sum property] ⇒90° + ∠RTS = 180° ⇒∠RTS = 90° |
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| 40. |
17. In the given figure, T is a point on side QR of APQR and S is a point suchthat RT = ST. Prove that PQ + PR > Qs.Triangles : Inequalities in a Triangle427 |
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| 41. |
In the figure given below, PQRS is a quadrilateral inwhich PQ 11 RS and PS= QR. If <P= 1100, thenfind <Q.ST70°B. 85°D. 140C. 1000E of these |
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| 42. |
के o 5T ,{%,wkw ip. | SRl Ry n - -- bR, = M % |
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Answer» a=3d=5an=a+(n-1)d78=3+(n-1)580=5nn=16 |
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| 43. |
ry |
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| 44. |
. If a function of is continuous on a closedInterval [a, b] and feas and fl by aree ofopposite signs (real.feb ll<o), themtherce exists at least a ree point2 tla, bls. t. f cal to. |
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| 45. |
Find the equation of the straight line passing through the point (3, -4) and cutting ofintercepts equal but of opposite signs, from the two axes. |
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| 46. |
explain an ecosystems. echosysteam di nioverBell contained are closed, susaity.l, men by The interaction or |
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Answer» Ecosystem is a system in which all living things include (plants,animals & organisms) which depends each other. ecosystem is a system in which all living things include plants animals org which depend on each other |
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| 47. |
-1/14 %2B 1/21 %2B 3/7 |
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Answer» 3/7+1/21-1/149+1-2/218/21 17/42 is the answer. lcm is 42. so answer is 18+2-3=》17/42 |
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| 48. |
In DPOR ,S and T are points in the sides PQ and PRPQ-9 cm and PR 4.5 cm, then find PT.,respectively such that ST QR. If PS-4 cm |
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| 49. |
PORS is an isosceles trapeziuml(PQ) = 7 cm. seg PML seg SR,l(SM) = 3 cm,Distance between two parallelsides is 4 cm, find the area of PQRS |
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| 50. |
2Also, find the co-ordinates of the point of divisionind the sum of n terms of the series: (11 |
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