(iv) The lengths of sides of a rectangle are 5 cm and 3.5 cm. Find the

1.	(iv) The lengths of sides of a rectangle are 5 cm and 3.5 cm. Find the ratio of itsperimeter to area.
Answer» length=5cmbreadth=3.5cm perimeter : area2(l+b) : l×b2(5+3.5) : 5×3.52(8.5) : 17.517 : 17.517 : 175/10170 : 17534 : 35 area of rectangle are 170perimeter of rectangle 175170:17534:35 Length=5cmBreadth = 3.5cmPerimeter::Area2(L+B)::LxB2(5+3.5):5x3.52(8.5):17.517:175/10170:17534: 3534/35 the answer is 17.5 because the reactance area Length =5 cm Breadth =3.5cm Perimeter : area 2(l+b): l×b 2(5+3.5 ):5×3.52(8.5):17.5/1017:175

(iv) The lengths of sides of a rectangle are 5 cm and 3.5 cm. Find the ratio of itsperimeter to area.

Answer»

length=5cmbreadth=3.5cm

perimeter : area2(l+b) : l×b2(5+3.5) : 5×3.52(8.5) : 17.517 : 17.517 : 175/10170 : 17534 : 35

area of rectangle are 170perimeter of rectangle 175170:17534:35

Length=5cmBreadth = 3.5cmPerimeter::Area2(L+B)::LxB2(5+3.5):5x3.52(8.5):17.517:175/10170:17534: 3534/35

the answer is 17.5 because the reactance area

Length =5 cm Breadth =3.5cm Perimeter : area 2(l+b): l×b 2(5+3.5 ):5×3.52(8.5):17.5/1017:175