Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

7. If f(x) = log tan ), , then the value of f'(x) is -

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2.

9 x - 16 x + 457 - 100 = 400

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9x-16x+457-100=400-7x+457-400-100=0-7x=+43x=6.142

3.

\sqrt{100} * \sqrt{16} * \sqrt{225} * \sqrt{1}

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4.

10. Find the value of x.la) * % of 100 =16

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X is equal to 16 so simple

x/100*100=16then x =16

ansx is equal to the number 16 it is very easy

x = 16 is the best answer

xis equal to 16 so simple

5.

x-10Then find the angles.A) The angles of triangle are 40, -209) and

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6.

. ProveVe that:(i) sin 100 sin 30° sin 50%in7o-16

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7.

In a triangle the sum of any two sides exceeds the third side by 6 cm. Find its area (in sq. m)(A) 12 v3(C) 153(D) 18 /3

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Let a, b, and c are sides of trianglea/c questiona+b-c=6b+c-a=6c+a-b=6add all equations a+b+c=18hence perimeter (s)=18s-(a+b-c)=18-6a+b+c-a-b+c=122c=12c=6cmin the same way b=a=6cmhence triangle is an equilatral so ,area of equilatral triangle=√3/4 (6)^2=9√3 cm^2

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8.

Find the value of 'x' in16 : 80 :: x : 100

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16 : 80 is in 1 : 5 ratio.Therefore x : 100 should also be in 1:5 ratio. As a resultX * 5 = 100X = 20

16/80=x/100x=(100×16)/80=100/5=20

9.

Q2. 15 added to thrice a wholenumber gives 93. Find the number. /ਇੱਕ ਪੂਰਨ ਸੰਖਿਆ ਦੇ ਤਿੰਨ ਗੁਣਾ ਵਿੱਚ 15 ਜੋੜਨ ਤੇ93 यूप्यउ चै । मविना या वठे । / एकपूर्ण संख्या के तीन गुना में 15 जोड़ने पर 93 प्राप्तप्राप्त होता है ।वह संख्या पता करें । *

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this questions answers is 29

3×A+15= 933×A= 93-15A =78÷3A= 26 answer

solve=93-15=78then,78÷3=26therefore,the answer is 26.

let x be the required number According to the question 15+3=933x=93-15=78x=78÷3=26Hence the required number is 26

10.

Q2. 15 added to thrice a wholenumber gives 93. Find the number /ਇੱਕ ਪੂਰਨ ਸੰਖਿਆ ਦੇ ਤਿੰਨ ਗੁਣਾ ਵਿੱਚ 15 ਜੋੜਨ ਤੇ93 यूप्यउ चै । हठ मविना या वठे । / एकपूर्ण संख्या के तीन गुना में 15 जोड़ने पर 93 प्राप्तप्राप्त होता है । वह संख्या पता करें । *

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let number be x and thrice of that number be 3xaccording to question, x + 3x = 934x = 93 x = 93/4 x = 23.25the number is 23.25

3x+15=933x=93-153x=78x=26whole number is 26

answer is 2693-15=7878÷3=26

26 hoga answer 3x+15=93 3x=93-153x=78x=26

solve=93-15=78then, 78÷3=26therefore the answer is 26.

15+3x=933x=93-153x=78x=78/3x=26

वह संख्या हे 26क्योंकि 26 के तीन गुना 78 और प्लस 15 बराबर 93

let the whole number be x15+3x=933x=93–15x=78/3x=26so,the number is 26

3x+15=93×=78/3×=26

3x+15=933x=93-153x=78x=78/3x=26

3x+15=933x=93-153x78 x=26 Ans=26

let the whole number be Xthen according to question3X+15=933X+15-15=93-15 ( by subtracting b/s by 15)3X=78X=78/3X=26

mana namber =XX×3+15=933X+15=933X=93-153x=78X=78/3X=26answer

whole number 93-15=78is right answer

x*3+15=93x*3=93-15x*3=78x=78/3x=26

26 hogi because 26*3=78+15=93

3x + 15 = 93 3x= 93 - 15. x = 78 ÷ 3 = 26

mere bahi 15ka Teen guna gayeda ho ga 78

let no. be x thrice of no. is 3xtherefore X+3x =93and x=15 therefore 3x=93-15therefore X=78/3=26

yaar bahi bo tere anser ka jabab hai ki bo 78

Esme hum ek bah sankhya lenge Jo purn ho to 26×3+15

15+3num = 93num = <93-15>/3num=26

iska answer 26 hoga kyun ki.93me se 15 ghata lo or fir jb 78 ayega to 3 se divide kr lo answer aa jayega

let the whole number be x =3x+15=93on shift 15on other side3x=93-153x=78 x=78÷3 x=26

3x+15=933x=93-153x=78x=26

A x 3 +15=93A x 3=93-15=78A=78/3A=26

26

the number that satisfies above equation is 26

3x+15=933x=93-15x=78/3x=26

26*3. =78and 78+15= 93 right answer is 26

15+3x=93 3x=93-153x=78x=78/3x=26

3x + 15 =933x = 93-153x =78x =78÷3x = 26

78 aur 15 93 hota hai

26. .

let whole number be x and its thrice is 3x according to ur question, 3x + 15 = 933x = 93 - 153x = 78x = 78/3x = 26the number will be 26

11.

Section (AortionHCF of 85 and 153 is expressible in the form of 85m-153, then find the valuef m

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12.

. Five added to twice a number gives 13. Find the number.

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two Threads of number is greater thank on trade of the number by 3 find the number

13.

1. Six added thrice of a number gives 33. Find the number

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Let the required number be x,Given in the question that 6 added to thrice the required number gives 33,Converting the theory in equation,=> 3x + 6 = 33

=> 3x = 33 - 6

=> 3x = 27x=27/3x=9

14.

Nine added to thrice a whole number gives 54. Find the number

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Let the number be n

According to given condition3n + 9 = 543n = 54 - 93n = 45n = 5

Number is 5

15.

(a) 0.29 (b) 2.08 (U)Write each of the following as decimals.4.() 209,10 (6) 137+ 16%()100

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16.

In each question given below whichone number can be placed at the signof interrogation?251072091020

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2 × 2 = 419 × 19 = 36117 × 17 = 289361 - 289 - 4 = 68

First set7 × 7 = 4916 × 16 = 25610 × 10 = 100256 - 100 - 49 = 107

17.

In the question given below which one numof interrogation?9327)(7916633742

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This is a pattern where the uppermost left element is the sum of all other elements of the set. 93=27+63+3.78= 38+37+4. 67= 16+42+X=> X = 67-58=> X = 9.

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18.

nine added to thrice a whole number gives 54 find the number

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19.

Find the volume of cylinder which is made by rolling a rectangular sheet of size 44 cm×33cm along its breadth

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Length=circumference of base44=2πr22=(22/7)rr=7 cm

Breadth=HeightHeight=33 cm

Volume of cylinder=πr²h=(22/7)(7²)(33)=5082 cm³

correct ans is 3811.5 cm3

20.

Face value of a digit is the value of the digit itself.

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this statement is correct. Face valueis the actualvalueof the digit. In the number 456, the "5" has aface valueof 5.Value.Value= The placevalueof the digit times itsface value.Example: thevalueof the digits 6, 8 and 4 in the number 684.

this statement is true.

684 is the answer of the following

684 is the answer of the following

this statement is true.in 725 the phase value of 7 is 7 and 2 is 2.but in 725 place value of 7 is 700 and place value of 2 is 20.

21.

The area of a rectangular plot is 880 m2 and its length is 44 m. Finda. its perimeterb. the cost of fencing it at the rate of? 5 per m.

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Area = Length×breadth880=44 ×b b=20m a) Perimeter=2(l+b)=2(44+20)=2(64) =128 mb) Cost = 128×5 = 640 rs

22.

The frequency of an oscillator is 4 Hz. What will be the time period of oscillations for that oscillator

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23.

ven below which one number can be placed at the sign of interrog162510720910 204293175217

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24.

130. The Indian states that were annexed by invoking theDoctrine of Lapse included:

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Jhansi, Nagpur and Satara

25.

12) Nine subtracted from a number givesFind the number.

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26.

5.The area of a square is 121 m. Its perimeterisb. 22 m

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Area of square = side²

side ² = 121

side = √121

side = 11

So, Perimeter = 4 × side = 44

27.

The sum of the squares of two consecutive naturalnumbers is 313. Then the product of the two numbersis(1) 110(3) 144(2) 132(4) 156

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28.

50+150+250

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50+150+25050+400450 answer

29.

Ihe points A and B representnumbers on a number line asbelow:shown25000 A 39000В 61000The distance between the pointsA and B is-(1) 22000 units(2) 29000 units(3) 84000 units(4) 22 units

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nice

30.

Write the following numbers in its decimal form(i) -5/7(ii) 9/11(iii) √5 (iv) 121/13

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I)-5/7=0.714ii)9/11=0.818iii)√5=2.236iv)121/13=9.308

steps plzzz

1) -5/7 = 0.7142852) 9/11 =0.81

31.

Find the face value of 7 in 942756(a) 7(c) 7000(b) 700(d) 70000

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Face value of a digit in any number is the digit itself. Therefore, Face value of 7 = 7.

32.

x+20%=84000

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x+20%=84000x =84000-20%X= 84000 - 20/100x = 840098

840098 is the correct answer

840098 is answer

......

x+20%=84000x=84000-20/100x=(84000-0.2x=83999.8

33.

1. If banana is apple, apple is grapes, grapes is mango, mango isnuts, nuts is guava, which of the following is a yellow fruit?

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mango is a yellow fruit but mango is nuts, so nuts is a yellow fruit

34.

cosecl =—, dl tanf 217 cos Wl

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35.

In3 theny 156

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ATQ

x+y = 180..... ( linear pair)

so, if x = 30

=> y = 180-30 = 150°

in that value of x and y available

what can I solve in it

36.

Amount (Rs.)21768

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217+68+260=545. is right answer

545 is the correct answer of the given question

545 was right answer

37.

Section,217..end 시 \ = 3, then tind the value of A

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38.

35 added to a number gives 217. Find the number.

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Let the number be x

35 + x = 217

x = 217 - 35

x = 182

39.

r line:(d) -250)+ (+ 150)-is(f) (217)4100)2

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-13+(+18)=-13+18=5-250+150=-100-217-100=-317

40.

6. In the given figure, PQ andAB are respectively the arcsof two concentric circles of o30radii 7 cm and 3.5 cm andcentre O. If ZPOQ 30, thenfind the area of the shadedregion [ Use π 22m.Delhi 20121 (3)

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41.

156, 13121 22(iv)

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42.

1. In the given figure, if PQ isa tangent and OQ is radiusthen what is the value of30°ZPOQ?

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Radius OQ is perpendicular to the tangent PQ . Therefore, POQ is a right angled triangle. Sum of all interior angles of a triangle is 180°

x+30+90= 180

=> x= 60°

43.

1. In the given figure, if PQ isa tangent and OQ is radiusthen what is the value ofZPOQ?30

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44.

臼In the giventangentnid, the measure of zPOQa 1200dso0

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It will be 100°as OP and OQ are radius and both will be equal so will make equal angles OP is perpendicular to AB angle OPQ= (90-50)= 40°now in triangle OPQangle P + angle O + angle Q = 180°40+40+angle O = 180°= 10O° Answerplease like the solution 👍 ✔️

45.

11) An insurance policy pays 90% of the first20000 of a certain patient's medicalexpenses, 80% of the next 40000 and 40%of the 40000 after that. If the patient's totalbill is 92000, then how much will thepolicy pay?a 90000b 84000c 70000d 62800

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Total bill of patient = 92000

Then insurance company will pay = (90/100)*20000 + (80/100)*40000 + (40/100)*32000= 90*200 + 80*400 + 40*320= 18000 + 32000 + 12800= 62800

Therefore insurance company will pay Rs 62800

(d) is correct option

46.

Find the area of the sector of a circle whose radius is r and length of the arc is l.

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47.

Find the area of the sector of a circle whose radius is r and length of the arc is l

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48.

APB is a tangent to a circle with centre O, at point P. If ZOPB 50°, then themeasure of ZPOQ is:Fig. 2(A) 120°(B) 100 (C) 140(D)150°

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49.

the given figure, if ZPOQ = 60° and radius = 20 cin, then find the areas of the minutegment and the major segment.11 - 3.14.3 = 1.73)02600 R1) rand length of one of 18

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50.

find the area of a sector of a circle whose radius is 14cm and the length of the arc of the sector is 28cm

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