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In a triangle the sum of any two sides exceeds the third side by 6 cm. Find its area (in sq. m)(A) 12 v3(C) 153(D) 18 /3 |
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Answer» Let a, b, and c are sides of trianglea/c questiona+b-c=6b+c-a=6c+a-b=6add all equations a+b+c=18hence perimeter (s)=18s-(a+b-c)=18-6a+b+c-a-b+c=122c=12c=6cmin the same way b=a=6cmhence triangle is an equilatral so ,area of equilatral triangle=√3/4 (6)^2=9√3 cm^2 Like my answer if you find it useful! Thanks |
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