81279 + Interview Questions in Mathematics QA in Mathematics

1.	cost of the Cow.7. Mr Kannan had deposited 2,500 in a bank at 12% per annum. After3 years, he withdraws this amount. Out of this money, he wants to buya dressing table costing R 4,000. How much more money does he need?2
Answer» Amount after 3.5 yearsimple interest= PTR/100Amount = SI + principal amountSI= 25003.512/100= 1050Amount = 2500+10503550he needs 4000-3550= 450 rupees

Discussion

2.	1 + \frac { x ^ { 3 } } { 729 }
Answer» 1 + x³/7291 + (x/9)³(1+ x/9) ( 1 + x²/81 - x/9)

Discussion

3.	pter covers 600 km. in 1 hour. How much distance will it cover in 4 hougyour answer in meters.
Answer»

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4.	Find the value of m 3^(2m)*81=729
Answer» 3²ⁿ x 3⁴= 9³3²ⁿ⁺⁴= 3⁶2m+4= 6 base is same so power will be equal too2m=2m =1

Discussion

5.	\frac { \sin 30 ^ { \circ } + \tan 45 ^ { \circ } - \csc 60 ^ { \circ } } { \sec 30 ^ { \circ } + \cos 60 ^ { \circ } + \cot 45 ^ { \circ } }
Answer»

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6.	18 \times [ - \frac { 2 } { 3 } ] ^ { n - 1 } = \frac { 512 } { 729 }
Answer»

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7.	x=2+\sqrt{3}2 \text { (b) } 2 \sqrt{3} \text { (c) } 4 \text { (d) } 2-\sqrt{3}
Answer»

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8.	\begin{array} { l } { \text { Which of the following form an AP? } } \\ { \text { (A) } 1,1,2,2,3 , \dots } \\ { \text { (B) } 0.3,0.33,0.333 , \dots } \\ { \text { (C) } \sqrt { 2 } , 2,2 \sqrt { 2 } , 4 , \ldots } \\ { \text { (D) } 9,9 + \sqrt { 3 } , 9 + 2 \sqrt { 3 } , 9 + 3 \sqrt { 3 } , \ldots } \end{array}
Answer» 1. D) is an APwith common difference√3

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9.	\left. \begin array l l \text (a) \sqrt 3 & \text (b) \frac 1 \sqrt 3 & \text (c) \frac 2 \sqrt 3 \end array \right. \quad \text (d) 1
Answer» tan60=sin60/cos60=(√(3)/2)/(1/2)=√(3)

Discussion

10.	\left. \begin{array} { l } { \text { If } \sqrt { 2 + \sqrt { x } } = 3 , \text { then } x = } \\ { \text { (A) } 1 } & { \text { (B) } \sqrt { 7 } } \\ { \text { (C) } 7 } & { \text { (D) } 49 } \end{array} \right.
Answer»

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11.	EXERCISE 11A1. Find the amount and the compound interest on2500 for 2 years at 10% per annumcompounded annuallyuseo5 for 3 vears at 12% per annun
Answer»

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12.	-n/227n/ 223. If(3" x2)3729then, prove that m-2
Answer» 9^(n+1)(3^-n/2)^-2 - 27^n/(3^m 2)^3 = 1/729 27^n(9 - 1)/27^m8 = 1/729 27^n8/27^m*8 = 1/27^2 1/27^[m - n] = 1/27^2 Since base is same then powers are equal Therefore,m - n = 2

12.

-n/227n/ 223. If(3" x2)3729then, prove that m-2

Answer»

9^(n+1)*(3^-n/2)^-2 - 27^n/(3^m * 2)^3 = 1/729

27^n(9 - 1)/27^m*8 = 1/729

27^n*8/27^m*8 = 1/27^2

1/27^[m - n] = 1/27^2

Since base is same then powers are equal

Therefore,m - n = 2

Discussion

13.	I. In sequence an-2n2-1 the second term is,A) IB) 7C) 17D) 3
Answer» a(n) = 2n² - 1 a(2) = 2 × 2² - 1 = 8 - 1 = 7 (B) is correct yah option B is correct

13.

I. In sequence an-2n2-1 the second term is,A) IB) 7C) 17D) 3

Answer»

a(n) = 2n² - 1

a(2) = 2 × 2² - 1 = 8 - 1 = 7

(B) is correct

yah option B is correct

Discussion

14.	- \frac { \sin 30 ^ { \circ } + \tan 45 ^ { \circ } - \csc 60 ^ { \circ } } { \sec 30 ^ { \circ } + \cos 60 ^ { \circ } + \cot 45 ^ { \circ } }
Answer» sin30=1/2Tan45=1cosec60=2/√3sec30=2/√3 cos60=2 cot 45=1put in expressionhence1/2+1-2/2/√3+2+11/2-1/2/√3+3-1/2/2+3√3/√3-√3/2(2+3√3)

Discussion

15.	\frac{\sin 30^{\circ}+\tan 45^{\circ}-\csc 60^{\circ}}{\sec 30^{\circ}+\cos 60^{\circ}+\cot 45^{\circ}}
Answer» sin30=1/2 tan45=1 cosec60=2/√3sec30=2/√3 cos60=1/2 cot45=11/2+1-2/√3/2/√3+1/2+13/2-2/√3/2/√3+3/23√3-4/√3/3√3+4/√33√3-4/3√3+4

Discussion

16.	5(sqrt(3)(text(sqrt(2)(a(dn))))) %2B 3sqrt(2) - 3sqrt(3)
Answer» first 3√2+5√3=12.9028now, √2-3√3=-3.7819now, according to the question, on adding both12.9028+(-3.7819)12.9028-3.7819=9.1208 (3√2+5√3) + (√2-3√3)=3√2-√2+5√3-3√3=2√2+2√3

16.

5(sqrt(3)(text(sqrt(2)(a(dn))))) %2B 3sqrt(2) - 3sqrt(3)

Answer»

first 3√2+5√3=12.9028now, √2-3√3=-3.7819now, according to the question, on adding both12.9028+(-3.7819)12.9028-3.7819=9.1208

(3√2+5√3) + (√2-3√3)=3√2-√2+5√3-3√3=2√2+2√3

Discussion

17.	\left. \begin array l \text in \theta ) \text and n = ( \operatorname cos \theta %2B \operatorname sin \theta ) \\ \sqrt \frac m n %2B \sqrt \frac n m = \frac 2 \sqrt 1 - \operatorname tan ^ 2 \theta \end array \right.
Answer» Like if you find it useful

Discussion

18.	Y, Ariftook a loan of 80000 from abank, Iftherateofínterest is 10% per annumyears if the interest isfind the difference in amounts he would be paying after 10) compounded annually.ii) compounded half yearly
Answer»

Discussion

19.	In sequence anA) I= 2n2-1 the second term is,B) 7I.C) 17D) 3
Answer» a(n) = 2n² - 1 a(2) = 2 × 2² - 1 = 8 - 1 = 7 (B) is correct

19.

In sequence anA) I= 2n2-1 the second term is,B) 7I.C) 17D) 3

Answer»

a(n) = 2n² - 1

a(2) = 2 × 2² - 1 = 8 - 1 = 7

(B) is correct

Discussion

20.	o lorge Mo = xsmall No ydifferentbetweentuonois 26.:large No isthreetimesmall mox=3420 a 390B1= 26+y
Answer» x-y=26 x+y=180' by elmn method x=103 , y =77 is correct answar

20.

o lorge Mo = xsmall No ydifferentbetweentuonois 26.:large No isthreetimesmall mox=3420 a 390B1= 26+y

Answer»

x-y=26

x+y=180'

by elmn method x=103 , y =77 is correct answar

Discussion

21.	अति लघु उत्तरीय प्रश्न \|\| हर समीकरण 227 + ke + 1 =0 90 मूल हो तो 4 ज्ञात क
Answer» For this put X=-1/22(-1/2)^2+k(-1/2)+1=02*1/4-k/2+1=01/2-k/2+1=01-k+2=0k=3

Discussion

22.	6)Arif took a loan of80,000 from a bank. If the rate of interest is 10%per annunfind the difference in amounts he would be paying after 1yersifthe interesti0) compounded annually(i) compounded half yearly.
Answer»

Discussion

23.	5sin(30circ) %2B 3tan(45**circ)
Answer» 5sin30+3tan4551/2+315/2+311/2

Discussion

24.	((5sqrt(2) %2B 5sqrt(3))(x - 2sqrt(6)))/(-5sqrt(2) %2B 5sqrt(3))=1
Answer» (x - 2root(6))(5root(3) + 5root(2))/(5root(3) - 5root((2)) = 1 (x - 2root(6))= (root(3) - root(2))/ (root(3) + root(2)) (x - 2root(6)) = (root(3)-root(2))^2 / (3 - 2) x - 2root(6) = 3 + 2 - 2root(6) x = 5

24.

((5sqrt(2) %2B 5sqrt(3))(x - 2sqrt(6)))/(-5sqrt(2) %2B 5sqrt(3))=1

Answer»

(x - 2root(6))(5root(3) + 5root(2))/(5root(3) - 5root((2)) = 1

(x - 2root(6))= (root(3) - root(2))/ (root(3) + root(2))

(x - 2root(6)) = (root(3)-root(2))^2 / (3 - 2)

x - 2root(6) = 3 + 2 - 2root(6)

x = 5

Discussion

25.	N=-sqrt(-2*sqrt(2) %2B 3) %2B (sqrt(-2 %2B sqrt(5)) %2B sqrt(2 %2B sqrt(5)))/sqrt(1 %2B sqrt(5))
Answer» 1 is the correct answer.

Discussion

26.	(i) Show that number of the form 7". n âŹ N cannot have unit digit 0. [CBSE 2010]
Answer» can you please help me on whatsapp

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27.	(sqrt(-2 %2B sqrt(5)) %2B sqrt(2 %2B sqrt(5)))/sqrt(1 %2B sqrt(5))
Answer»

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28.	The sum of a number and it's positive square root is 6/25, find the number
Answer» thanks

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29.	Prove that the sequence root7, root(7+root7), root(7+root (7+root7)) tends to have positive roots
Answer»

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30.	13. S andare the zeroes of the polynomial 1or' -6'+ 40 +0x -75. Find the other22zeroes of the polynomial.
Answer»

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31.	BSE 2010]18. If R(x, y) is a point on the line segment joining the points P (a, b) and Q (b a), then prove[CBSE 2010]that x + y = a + b.
Answer»

Discussion

32.	6.Find an integer which gives -13 on division by 5.
Answer» -65 is an integer which gives -13 on division by 5. -65 is integer which give -13 on divided by 5 -65 is interger which give -13 on divided by 5 -65 is a integer which give -13 when divided by 5 -65 is the integers which gives -13 on division by 5.please like my -65 is the integers which gives -13 on division by 5.please like my answer -65; is the correct answer of the given question -65 is the integer which gives -13 on division by 5

32.

6.Find an integer which gives -13 on division by 5.

Answer»

-65 is an integer which gives -13 on division by 5.

-65 is integer which give -13 on divided by 5

-65 is interger which give -13 on divided by 5

-65 is a integer which give -13 when divided by 5

-65 is the integers which gives -13 on division by 5.please like my

-65 is the integers which gives -13 on division by 5.please like my answer

-65; is the correct answer of the given question

-65 is the integer which gives -13 on division by 5

Discussion

33.	13.What is that fraction which when multiplied by itself gives 227.798649?
Answer»

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34.	x^2 %2B 5(sqrt(5)x) %2B 30
Answer»

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35.	(((x - 2)(x - 1))(2x %2B 5))(2*x %2B 3)=30
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36.	यदि \frac{d}{d x} f(x)=4 x^{3}-\frac{3}{x^{4}} जिस f(2)=0, then f(x) हैः
Answer»

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37.	A number exceeds its positive square root by 12. Find the number
Answer» thanks

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38.	n/2log (tan x)0
Answer»

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39.	\left. \begin{array} { l } { f ( x ) = 2 x + 3 } \\ { f ( x ) = \frac { x + 2 } { 5 x - 1 } } \end{array} \right.
Answer»

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40.	y=log(tan(pi/4 %2B x/2), 10)
Answer»

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41.	2x3 + 3y2 + 5xy,the function f(x,y)af0xGivenfind.
Answer»

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42.	3. 4 subtracted from a number and then divided by7, gives 13 as the quotient. Find the number,
Answer»

Discussion

43.	Find a rational number which when multiplied withgives the product 45.13
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44.	レ1 nandycm30 um
Answer»

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45.	-80x - 48y %2B 30(xy) %2B 25x^2 %2B 9y^2 %2B 64
Answer»

Discussion

46.	HOTS The length of the side of one squareexceeds the length of the side of the othersquare by 6 cm. If the sum of the areas of thetwo squares is 666 cm^2, then find the lengthof the sides of both the squares
Answer» Let the length of square be xthen length of another is x + 6(x)^2 + (x + 6)^2 = 666x^2 + x^2 + 36 + 12x = 6662x^2 + 12x + 36 = 666dividing eqn by 2x^2 + 6x + 18 - 333 = 0 x^2 + 6x - 315 = 0x^2 + 21x - 15x -315 = 0x(x+21) -15(x+21)=0so x=15hence the length one 1 □ is 15and of another is 21

Discussion

47.	2/45+ 3/202V513. Write whetheron simplification gives a rational or an irrational numberCBSE 2010]
Answer» simply it is in the form of p/q but your wrong

47.

2/45+ 3/202V513. Write whetheron simplification gives a rational or an irrational numberCBSE 2010]

Answer»

simply it is in the form of p/q

but your wrong

Discussion

48.	S 1575 Hhon рдкреА:Value &f 0779 '
Answer» well it is short one😅 Thanks

48.

S 1575 Hhon рдкреА:Value &f 0779 '

Answer»

well it is short one😅

Thanks

Discussion

49.	2 f(x) + 3 f(-x) = 15-4x find the value of f(2)
Answer»

Discussion

50.	2 aff (a) : 2x + 3xt2then find the value of f(2).
Answer» f(2)= 2(2)^2+3(2)+2= 8+6+2= 16

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

cost of the Cow.7. Mr Kannan had deposited 2,500 in a bank at 12% per annum. After3 years, he withdraws this amount. Out of this money, he wants to buya dressing table costing R 4,000. How much more money does he need?2

1 + \frac { x ^ { 3 } } { 729 }

pter covers 600 km. in 1 hour. How much distance will it cover in 4 hougyour answer in meters.

Find the value of m 3^(2m)*81=729

\frac { \sin 30 ^ { \circ } + \tan 45 ^ { \circ } - \csc 60 ^ { \circ } } { \sec 30 ^ { \circ } + \cos 60 ^ { \circ } + \cot 45 ^ { \circ } }

18 \times [ - \frac { 2 } { 3 } ] ^ { n - 1 } = \frac { 512 } { 729 }

x=2+\sqrt{3}2 \text { (b) } 2 \sqrt{3} \text { (c) } 4 \text { (d) } 2-\sqrt{3}

\left. \begin array l l \text (a) \sqrt 3 &amp; \text (b) \frac 1 \sqrt 3 &amp; \text (c) \frac 2 \sqrt 3 \end array \right. \quad \text (d) 1

\left. \begin{array} { l } { \text { If } \sqrt { 2 + \sqrt { x } } = 3 , \text { then } x = } \\ { \text { (A) } 1 } &amp; { \text { (B) } \sqrt { 7 } } \\ { \text { (C) } 7 } &amp; { \text { (D) } 49 } \end{array} \right.

EXERCISE 11A1. Find the amount and the compound interest on2500 for 2 years at 10% per annumcompounded annuallyuseo5 for 3 vears at 12% per annun

-n/227n/ 223. If(3" x2)3729then, prove that m-2

I. In sequence an-2n2-1 the second term is,A) IB) 7C) 17D) 3

- \frac { \sin 30 ^ { \circ } + \tan 45 ^ { \circ } - \csc 60 ^ { \circ } } { \sec 30 ^ { \circ } + \cos 60 ^ { \circ } + \cot 45 ^ { \circ } }

\frac{\sin 30^{\circ}+\tan 45^{\circ}-\csc 60^{\circ}}{\sec 30^{\circ}+\cos 60^{\circ}+\cot 45^{\circ}}

5*(sqrt(3)*(text*(sqrt(2)*(a*(d*n))))) %2B 3*sqrt(2) - 3*sqrt(3)

\left. \begin array l \text in \theta ) \text and n = ( \operatorname cos \theta %2B \operatorname sin \theta ) \\ \sqrt \frac m n %2B \sqrt \frac n m = \frac 2 \sqrt 1 - \operatorname tan ^ 2 \theta \end array \right.

Y, Ariftook a loan of 80000 from abank, Iftherateofínterest is 10% per annumyears if the interest isfind the difference in amounts he would be paying after 10) compounded annually.ii) compounded half yearly

In sequence anA) I= 2n2-1 the second term is,B) 7I.C) 17D) 3

o lorge Mo = xsmall No ydifferentbetweentuonois 26.:large No isthreetimesmall mox=3420 a 390B1= 26+y

अति लघु उत्तरीय प्रश्न || हर समीकरण 227 + ke + 1 =0 90 मूल हो तो 4 ज्ञात क

6)Arif took a loan of80,000 from a bank. If the rate of interest is 10%per annunfind the difference in amounts he would be paying after 1yersifthe interesti0) compounded annually(i) compounded half yearly.

5*sin(30**circ) %2B 3*tan(45**circ)

((5*sqrt(2) %2B 5*sqrt(3))*(x - 2*sqrt(6)))/(-5*sqrt(2) %2B 5*sqrt(3))=1

N=-sqrt(-2*sqrt(2) %2B 3) %2B (sqrt(-2 %2B sqrt(5)) %2B sqrt(2 %2B sqrt(5)))/sqrt(1 %2B sqrt(5))

(i) Show that number of the form 7". n âŹ N cannot have unit digit 0. [CBSE 2010]

(sqrt(-2 %2B sqrt(5)) %2B sqrt(2 %2B sqrt(5)))/sqrt(1 %2B sqrt(5))

The sum of a number and it's positive square root is 6/25, find the number

Prove that the sequence root7, root(7+root7), root(7+root (7+root7)) tends to have positive roots

13. S andare the zeroes of the polynomial 1or' -6'+ 40 +0x -75. Find the other22zeroes of the polynomial.

BSE 2010]18. If R(x, y) is a point on the line segment joining the points P (a, b) and Q (b a), then prove[CBSE 2010]that x + y = a + b.

6.Find an integer which gives -13 on division by 5.

13.What is that fraction which when multiplied by itself gives 227.798649?

x^2 %2B 5*(sqrt(5)*x) %2B 30

(((x - 2)*(x - 1))*(2*x %2B 5))*(2*x %2B 3)=30

यदि \frac{d}{d x} f(x)=4 x^{3}-\frac{3}{x^{4}} जिस f(2)=0, then f(x) हैः

A number exceeds its positive square root by 12. Find the number

n/2log (tan x)0

\left. \begin{array} { l } { f ( x ) = 2 x + 3 } \\ { f ( x ) = \frac { x + 2 } { 5 x - 1 } } \end{array} \right.

y=log(tan(pi/4 %2B x/2), 10)

2x3 + 3y2 + 5xy,the function f(x,y)af0xGivenfind.

3. 4 subtracted from a number and then divided by7, gives 13 as the quotient. Find the number,

Find a rational number which when multiplied withgives the product 45.13

レ1 nandycm30 um

-80*x - 48*y %2B 30*(x*y) %2B 25*x^2 %2B 9*y^2 %2B 64

HOTS The length of the side of one squareexceeds the length of the side of the othersquare by 6 cm. If the sum of the areas of thetwo squares is 666 cm^2, then find the lengthof the sides of both the squares

2/45+ 3/202V513. Write whetheron simplification gives a rational or an irrational numberCBSE 2010]

S 1575 Hhon рдкреА:Value &amp;f 0779 '

2 f(x) + 3 f(-x) = 15-4x find the value of f(2)

2 aff (a) : 2x + 3xt2then find the value of f(2).

\left. \begin array l l \text (a) \sqrt 3 & \text (b) \frac 1 \sqrt 3 & \text (c) \frac 2 \sqrt 3 \end array \right. \quad \text (d) 1

\left. \begin{array} { l } { \text { If } \sqrt { 2 + \sqrt { x } } = 3 , \text { then } x = } \\ { \text { (A) } 1 } & { \text { (B) } \sqrt { 7 } } \\ { \text { (C) } 7 } & { \text { (D) } 49 } \end{array} \right.

5(sqrt(3)(text(sqrt(2)(a(dn))))) %2B 3sqrt(2) - 3sqrt(3)

((5sqrt(2) %2B 5sqrt(3))(x - 2sqrt(6)))/(-5sqrt(2) %2B 5sqrt(3))=1

(i) Show that number of the form 7". n âŹ N cannot have unit digit 0. [CBSE 2010]

x^2 %2B 5(sqrt(5)x) %2B 30

(((x - 2)(x - 1))(2x %2B 5))(2*x %2B 3)=30

-80x - 48y %2B 30(xy) %2B 25x^2 %2B 9y^2 %2B 64

S 1575 Hhon рдкреА:Value &f 0779 '