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HOTS The length of the side of one squareexceeds the length of the side of the othersquare by 6 cm. If the sum of the areas of thetwo squares is 666 cm^2, then find the lengthof the sides of both the squares |
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Answer» Let the length of square be xthen length of another is x + 6(x)^2 + (x + 6)^2 = 666x^2 + x^2 + 36 + 12x = 6662x^2 + 12x + 36 = 666dividing eqn by 2x^2 + 6x + 18 - 333 = 0 x^2 + 6x - 315 = 0x^2 + 21x - 15x -315 = 0x(x+21) -15(x+21)=0so x=15hence the length one 1 □ is 15and of another is 21 |
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