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Given :

25x² + 36y² + 60xy

Compare with ( a+b)² = a² + b² + 2ab

(5x)² + (6y)² + 2 × (5x) × (6y)

( 5x + 6y)²

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2 miles=0.25inches1mile=.25/2210 mile=.25*210/2=26.25inches

area of sqaure is side × sideso here side is 25.4cm 1 centimetre= 0.394 inchso side in inch is 25.4 cm = 25.4 × 0.394 inch = 10.0076 inchso area is 10.0076² inch² = 100.15 inch²

no,because area of both rectangle are not same

No, the areas are not the same.

Why?1 square inch = 6.4516 square centimeters6 square inches = 38.7096 square centimetersZach's rectangle is bigger.

thank you guys

By hit and trailput X=1 the result is zerosince 1 is a zero of x³-7x+6

(x-1)is the factor of x³-7x+6

so if we divide x³-7x+6 with (x-1) then we will get x²+x-6

so we can write x³-7x+6 as (x-1)(x²+x-6)

=(x-1)(x²+3x-2x-6)

=(x-1)(x(x+3)-2(x+3))=(x-1)(x-2)(x+3)so the other zeros are 2 and -3

The area of one unshaded rectangle is length = (100-4)/2 = 48mbreath = (40-4)/2 = 18 m

so area of one unshaded rectangle = 48*18 for 4 unshaded areas it will be = 4*(48)*(18) =3456m²

now area of whole bigger rectangle = 100*40 = 4000 m²

so, area of shaded portion = 4000-3456m² = 544m²

it is wrong ans is 624cm2 how

1*2*3*4*5*6*7=5040 is the best answer

For log function , the domain should be such that the base should be 0 , or 1

and the number should > 0

[x+1/2] .. is the greatest integer function.. and for this function not to equal will 0 or 1 The minimum value of [x+1/2] = 2

=> X +1/2 ≥2 => x ≥ 2-1/2 ≥ 3/2....

also.=> |x²-5x+6| ≠ 0=> |(x-2)(x-3)| ≠ 0

so, 2 and 3 should also be excluded from the domain.

The final domain will be

[3/2) U (2,3) U (3,∞)

option A

Work done= Force× Displacement=10×2 = 20 J.

Given,Length l = 13 inches, Width b = 8 inches, Height h = 6 inches

Then required surface area of fish tank= 2(l*h + b*h) + l*b= 2(13*6 + 8*6) + 13*8= 2(78 + 48) + 104= 2*126 + 104= 256 + 104= 360 sq inch

Let Say A alone take = A mins

Then tank filled by A in 1 min = 1/A

Tank filled by A & B together in 1 min = 1/10

tank filled by B alone in 1 Min = 1/10 - 1/A = (A-10)/10A

if B id reversed then both takes 30 min

means tank filled in 1 min = 1/10

1/A - (A-10)/10A = 1/30

multiplying by 30A both sides

=> 30 - (3A-30) = A

=> 60 = 4A

=> A = 15

Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d)So, according to the question.a-3d + a - d + a + d + a + 3d = 324a = 32a = 32/4a = 8 ......(1)Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/1515(a² - 9d²) = 7(a² - d²)15a² - 135d² = 7a² - 7d²15a² - 7a² = 135d² - 7d² 8a² = 128d²Putting the value of a = 8 in above we get.8(8)² = 128d²128d² = 512d² = 512/128d² = 4d = 2So, the four consecutive numbers are 8 - (3*2)8 - 6 = 28 - 2 = 68 + 2 = 108 + (3*2)8 + 6 = 14Four consecutive numbers are 2, 6, 10 and 14

Thank you

tq

Join APNow in triangle APN and APMAP is common hypotneseangle ANP and AMP is 90 And PN is equal To PM (given)So by RHS rule both are congurenttherefore by CPCT angle PAM and PAN are equal so AP bisect angle A

I am assuming in place of triangle it should be Reactangle in question.

Given, Perimeter of Reactangle = 28 cm

Let breadth of Reactangle = xThen length of Reactangle = 5x/2

Perimeter of Reactangle= 2(length + breadth)

28 = 2(5x/2 + x)14 = 7x/27x = 28x = 28/7 = 4

Therefore,Length of Reactangle= 5*4/2 = 10 cmBreadth of Reactangle = 4 cm

1 whole contains 4 quartersand 1/2 contains 2 quartershence7 wholes contains 7*4=28 quarters28+2=30quarters

Area of base=600cm2Perimeter of base =2(l+b)=100cmThree quarters is filled with water =>Up to aheight of 15 cm=>Area of tank in contact with the water=Perimeter of base × height of water column+area of base=100 × 15×600=2100cm2

Let two consecutive numbers are x and (x + 1)

A/C to question,product of x and (x + 1) = 306 ⇒x(x + 1) = 306 ⇒x² + x - 306 = 0⇒ x² + 18x - 17x - 306 = 0⇒x(x + 18) - 17(x + 18) = 0⇒(x + 18)(x - 17) = 0⇒ x = 17 and -18

Hence, numbers are x = 17 and (x +1) = 18

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1. debtbecouse its a one tips of debt, banker will gave this

but answer is 21,24,27👈🙂✍️✍️

Step-by-step explanation:to prove:

AB+CD=AD+BC

Proof :

AP=AS

PB=BQ

CQ=CR

RD=DS (the length of tangent drawn from an external point to a circle are equal)

AP+PB+RD+CR=AS+BQ+DS+CQ

=>AB+CD=AD+BC

Hence proved

thanksss

thank u

5 log 3 - log 9

5 log 3 - log 3²

5 log 3 - 2 log 3

3 log 3

log 3³

log 27

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उसका पृष्ठ है= (2a)^2*6= 24a^2 cm^2