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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
2 \times 7 \times 8 %2B 78 \div 25 - 6 \times 77 |
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Answer» 2 x 7 x 8 + 78 ÷ 25 - 6 x 77= 112 + 78/25 - 462= 78/25 - 350= (78 - 8750)/25= - 8672/25= - 346.88 |
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| 2. |
-25 %2B 2 %2B 14 - 3 %2B 5 |
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| 3. |
6. Find the area of a trapezium whose parallel sides are 25 cm, 13 cm long and distancebetween them is 8 cm |
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Answer» 152 cm^2 is the Area of Trapezium.. 153cm2 is the correct answer 153cm sq is the correct answer of this question sorry 152 cm sq is the correct answer of this 152 is the correct answer 152cm^2 is correct answer. trapezium area 1/2×h(sum of parallel side)1/2×8(25+13)=1/2×8×48192cm sq 152 sq cm is correct answer 1/2 × height × sum of parallel sides1/2×8×(25+13)1/2 × 8× 384× 38152 cmsquare 1/2 * (sum of parallel sides)*h1/2 *(25+13)*81/2*38*819*8152 1/2*(sum of parallel sides)*h1/2*(25+13)*81/2*38*819*8152 |
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| 4. |
49In right-angled Δ ABC, BD AC.If AD 4, DC 9, then find BD |
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Answer» Step-by-step explanation In triangle ABC & ADB /_ A = /_A (common) /_ABC = /_ ADB (each 90) Therefore Triangle ABC similar to Triangle ADB => AB/AD = AC/AB => AB2= AD x AC => AB2= 4 x 9 (AC=AD+CD = 4+5 = 9 cm) => AB2= 36 => AB = 6 cm In Triangle ABD using Pythagoras Theorem AB2= AD2+ BD2 62 = 42 + BD2 BD2= 36 - 16 = 20 BD = 2√5 By geometric mean. BD square=AD into DC. therefore, BD=6 |
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| 5. |
Then BDDC |
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Answer» AD^2 = BD × CD AD ÷ CD = BD ÷ AD ΔADC ∼ ΔBDA (by SAS ∠D = 90°) ∠BAD = ∠ACD ; ∠DAC = ∠DBA (Corresponding angles of similar triangles) ∠BAD+ ∠ACD + ∠DAC + ∠DBA = 180° ⇒ 2∠BAD + 2∠DAC = 180° ⇒ ∠BAD + ∠DAC = 90° ∴ ∠A = 90° |
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| 6. |
4.In the given figure prove that BD=DC,i21=L2.112 |
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Answer» In ∆ ABD and ∆ ACD AB = AC ( given) angle 1 = angle 2 ( given) AD = AD ( common) By SAS rule ∆ ABD and ∆ ACD are congurent. By CPCT BD = DC |
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| 7. |
इक oका व e |
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Answer» 2/3 x + 9 = 3/4 x + 7 2x+27/3 = 3x+28/4 8x+108 = 9x+84 x = 108-84 x = 24 Like my answer if you find it useful! |
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| 8. |
श् ९५०5 2. l+sin & LO/ नव इक A cos A |
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Answer» LHS =cosA/(1+sinA) +(1+sinA)/cosA ={cos²A +(1+sinA)²}/cosA.(1+sinA) ={cos²A+1+sin²A+2sinA}/cosA.(1+sinA) use sin²∅ +cos²∅ =1 =(1+1+2sinA)/cosA(1+sinA) =2(1+sinA)/cosA(1+sinA) =2/cosA =2secA = RHS |
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| 9. |
plify : 42-36 รท [ 3 of { 2 x (16 รท 3+1 )-6)] |
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Answer» According to the question42-36%(3*(2*(16%3+1)-6))42-36%(3*(2*(16%4)-6))42-36%(3*(2*(4)-6))42-36%(3*(8-6))42-36%(3*2)42-36%66%61 |
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| 10. |
LT W (p)0६१७ (९6 W (q)0z 3¢ sbT &% R siahiekR (० |
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Answer» 3/5 = 12/20 = 9/15 = 18/30 = 27/45 |
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| 11. |
dependant_p] The-. Set-11,2,2).一(5,I,2)lintarlg independant 1(2,2rD-lslinearly |
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| 12. |
front. According to the laws, a minmum of 3 m, wide spaer shiiluand 2 m w ide space on each of other sides. Find the largest area where house cau be constructedL tt: A field ls in ih- share of a Irapezi um h:ning palaltei 、ides gn m and 30 m. These sides meet the thirdside at right angles. T he length of the foil rth side is loo ni I( İl eosts Rs 410 plongh 1m2 cif le field. tindthe total cost of ploughing the field. |
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| 13. |
-33450 %2B 6*(25*223) |
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Answer» 223(25*6-10*15) = 223 (150 - 150) = 0 223(25*6-10*15)=223(15 0-150)=0 223*25*6-223*10*15=33450-33450=0answar 0 is the correct answer 223×25×6=33,450223×10×15=33,45033,450-33,450=0 223*5*5*2*3-223*5*2*5*3=223*5*5*2*2(1-1)=223*100 (0)= 0 223x25x6=33,450223x10x15=33,45033,450-33,450=0answer is 0 correct 223*25*6-223*10*15= 0 this question answer is 0 ZERO(0) is the answer of this question 000000000000000000000000000 according to distributive property _# a(b-c) So, 223(25*6-10*15) =223*0=0 16 is answer of addition 223*25*6-223*10*50223*150-223*10*50=025*6=10010*50=150 0 223(25*6-10*15)= 223(150-150)=223*0= 0 223×25×6-223×10×1533450-33450=0 Answer is question ka answer 0 hoga you question answer is a it is a answers 0 wasn't of time its answer is 0using any method Right answer is 0 🤘 223(25×6-10×15)=223(150-150)=0 o is correct answer of your question 0 is a correct answer 0 is correct answer of this question 0 is the right answer 223×25×6-223×10×15=33450-33450=0 Ans 223x25x6-223x10x15 69536-33450 =36126 Take 223 as common 223×(20+5)×6-×(5+5)×(10+5)=(223×20)+(223×5)=4460+1115=5575×6=-(33450×5)+(33450×5) =-167250+167250 =-(334500×10)+(334500×5) =-3345000+1672500 =-501750 zero is the answer because there is distributive property so we have to distribute each and every unit 0 is the correct answer yes ya no (223)(25)(6)-(223)(10)(15)=033450-33450=0 223×25×6=33,450223×10×15=33,44033,450-33,450=0Answer is 0. 223 answer hoga bhai right 223×25×6-223×10×15=223(150-150)=223×0=0(Ans) 223(25*6-10*15) =223(150-150)=0 |
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| 14. |
A race track is ih D4400 m. Find the width and area of the tralA 3 m wide road is all around on the outside of a 125 m long and 60 mrepairing the road at the rate of Rs. 150 mSummary |
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Answer» a3m |
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| 15. |
14. The perimeter of a parallelogram is 36 cm. If the smaller side is 8 cm long, find themeasure of the longer side. |
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| 16. |
DNA copies |
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Answer» Before a cell divides, itsDNAis replicated (duplicated.) Because the two strands of aDNAmolecule have complementary base pairs, the nucleotide sequence of each strand automatically supplies the information needed to produce its partner. |
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| 17. |
A photographer offered to supply 3 copies of a photograph for Rs. 12 and 1for Rs. 30 and he estimated that his profit would be Rs. 4 and Rs. 9 resp.For what sum should be supply 30 copies in order to gain Rs. 13 as profit. |
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Answer» answer will be 105.0 for thus 1 unit = 1 rs100 unit = 120 rs but he sells 80 unit 120 rs one day :- 96 unit 120 rs so, 96*X% = 120-96=> 96*25% = 24 25% = answer |
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| 18. |
(i) 200 Uâ˘(W) 400 U = ........ 3(W) 1250 U = |
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Answer» (i) 200/1000= .2(ii)400/1000= .4(iii)1250/1000= 1.25 |
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| 19. |
Section-CUse Euclid's Division Algorithm to find the HCF of 726 and 275, |
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| 20. |
0.73V121-7361V529+2V36A. 3/5B. 477c. 1/4D. 275 |
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Answer» √121=11√361=19√529=23√36=6hence3*11-19/23+2*6=33-19/23+12=14/35=2/5 |
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| 21. |
In Fig. 11.22, BD DC and BA -CA. Is ABDA ACDA? If yes, why?Fig. 11.22 |
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Answer» In ∆ ABD and ∆ ACDAB = ACBD = DCAD = ADBy SSS ∆ BDA is congurent to ∆CDA |
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| 22. |
1254 लाग पर 2250 रुपये में बेचा गया। लाभ की।राशि क्या थी?(A)275 रुपये (B)250 रुपये (C) 225 रुप (D) 300 रुपये(A)(B)(D)} (C) |
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Answer» Let price be xProfit=12.5% of xS.p.=2250 rsSo, x+(12.5/100)x=2250 X+0.125x=2250 1.125x=2250So,x=2250/1.125=2000rsSo,profit=2250-2000=250rsB)250 rs B) 250 is the correct answer |
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| 23. |
9. Find the value of w in the following:6 423 w |
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Answer» a)w=6*3/(-2)w=18/-2=-9b)6/-7=42/ww=42*(-7)/6w=-49 |
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| 24. |
(c) 275°(d) 28521. In the given figure, ABI| CD. If ABLABO = 1300 and <OCD=110°,then BOC = ?110°130°(a) 50°(b) 60° |
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| 25. |
3. Two parallel lines I and m are cut by a transversal t. If the interior angles of the same sidedt be (2x-8)° and (3x - 7)", find the measure of each of these angles. |
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Answer» please select questions ok guys pls select questions ok (2x-8)°+(3x-7)°=1805x-15=180°5x=180/155x=12x=12/5 (2x-8)°+(3x-7)°=1805x-15=180°5x=180/155x=12x=12/5 answer f df d d ddbjssb s dbdhdbs. dhdjd. ddjdhbd |
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| 26. |
360. What is the price ofChhaya bought 20 copies fora single copy.s. |
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Answer» cost of 20 copies is 360cost of one copy is 360/20 = ₹18 |
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| 27. |
(b+c)2 abса1. aulaa siab (c+a)2 be2abc (a+ b+ c.=2abc (a + b + c2ca be (a+b)са |
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| 28. |
The area of trapezium is 182 cm^2.Its height is 14 cm .The larger parallel side is longer than the other by 16cm .Find the length of the parallel sided. |
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| 29. |
विविध उदा1 यदि 782= 20और 671= 17, तो 884 = 1(1)23(3)19व्याख्या- जिस प्रकार,7829 (7+8+2)+321743 |
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Answer» 884 = 238 + 8 + 4 = 2020 + 3 = 23(Sum of digits + 3)782 = 207 + 8 + 2 = 1717 + 3 = 20 671 = 176 + 7 + 1 = 1414 + 3 = 17 |
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| 30. |
Find the slope of line frowned by (532) 8 (223) |
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Answer» slope =( 3-2) / (2-1) slope = tanx = 1x= 45 |
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| 31. |
For any base, prove that\operatorname { log } ( 1 + 2 + 3 ) = \operatorname { log } 1 + \operatorname { log } 2 + \operatorname { log } 3 |
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Answer» Let log (1+2+3) = log 6 = log 1x2x3 We know that log abc = log a + log b + log c ∴ Let log (1+2+3) = log 6 = log 1 + log 2 + log 3. |
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| 32. |
. If 223 is divided by 5, what is the remainder? |
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Answer» can u explain in simpler form plz I'm a science student which grade can u specify the question is from which book that's a question in vro exam paper what is vro exam can u let me know it's xam conducted for the post of -village revenue officer ohh... ok fine.. there are other tactics but they will take to much time here I used a technique called modulo arthematic which will solve such question in seconds. OK alright thanq Ok you can also use this..observe that2¹ → 2 , 2²→ 4 , 2³→ 8 , 2⁴→1(6) 2^5 →3(2) , 2^6→ 6(4)... And so on.. So 2²³ = 2^(4n+3) = 2⁴ⁿ.2³ = 2⁴ⁿ.8. And 8/5 gives remainder as 3. |
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| 33. |
is (2r-3) afactor of p(x) = 223-9x2 +x+12? |
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| 34. |
इक ४४८0८ 0=5014XZ7-X (बॉ |
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| 35. |
In the given figure, ABACDAAC, 21-2/2 and 24-223. Prove that ABEA19.23 |
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| 36. |
(हा) (2द+ |) + (इक [)* न 6x+47 |
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| 37. |
(a) 200(b)275(c)250(d) 300 |
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Answer» 20%=(330-x/x)*10020/100=330-x/xx/5=330-xx+x/5=3305x+x/5=3306x/5=330 6x=330*5 x=330*5/6 x=55*5=275 (b)275 |
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| 38. |
Simplify (5(8} + 275)3w |
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| 39. |
.010a. 175b. 275c. 280d. 400 |
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| 40. |
1045166. Which of the following pairs represent the same rational number ?Ď: and-(ii) _ and(ii) and 2(iii) andand(ii)36 |
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Answer» i) as -16/36 will reduced to -4/9ii) not because 24/15 reduced to 8/5iii) because both are not same even they are in reduced form |
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| 41. |
\frac { \log \sqrt { 27 } + \log 8 - \log \sqrt { 1000 } } { \log 1.2 } |
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| 42. |
Five boys A, B, C, D and E are standing in a row.A is between C and D and B is between D and EWhich of the following pairs represent the boysstanding at both the ends? |
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Answer» a between c and db between d and e thus d in the middleand c and e at the ends arrangement is as:c a d b e therefore boys standing at the ends are c and e thanks |
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| 43. |
tan Aa , ส1 sin.Î.cosA srrr at/ |
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| 44. |
663:884::221:?? |
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Answer» 663:884 :: 221:X [let]=> 663/884 = 221/X=> X = (222*884)/663= 884/3. Please hit the like button if this helped you |
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| 45. |
aa 3.2ćä˝ TI(i) TRITX10 |
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| 46. |
222+223-221 |
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Answer» by basic addition and subtraction222+223-221=445-221=224 |
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| 47. |
310 x 1000 = |
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Answer» Sqroot (10) x Sqroot(1000)= Sqroot(10000)= 100 ans |
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| 48. |
310 \text { a term of the A.P. } 3,8,13,18 , \dots ? |
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| 49. |
06 Find the vatues of (a) ta221),(b) cos (310") |
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| 50. |
बिंदुओंA(6,8) और B(3,4) के बीच कीदूरी है।15 इकाई2 12 इकाई310 इकाई4 25 इकाई10:15am |
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Answer» (4) answers 25 is correct. answer is 5 . option 1 therefore, 5is right answer 25 is correct answer 5 is the right answer answer 25 is correct option( I) 5 is it's answer (1)= 5 is right answer I think option 1 means 5 is the correct answer of your question 5 is my answer My option is 1 answer =5unituse formula co-ordinate geometry =distance distance formula option 1 answer 5 is correct think by me will be the right answer distance between point (6;8)and(3;4)is equal 5 unit (1)5 unit will be answer of this question |
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