For any base, prove that\operatorname { log } ( 1 + 2 + 3 ) = \operato – InterviewSolution

1.

For any base, prove that\operatorname { log } ( 1 + 2 + 3 ) = \operatorname { log } 1 + \operatorname { log } 2 + \operatorname { log } 3

Answer»

Let log (1+2+3) = log 6 = log 1x2x3

We know that log abc = log a + log b + log c

∴ Let log (1+2+3) = log 6 = log 1 + log 2 + log 3.

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