हि न 6o Teoncoes:of polapss dFeg skl s

1.	हि न 6o Teoncoes:of polapss dFeg skl s
Answer» By hit and trailput X=1 the result is zerosince 1 is a zero of x³-7x+6 (x-1)is the factor of x³-7x+6 so if we divide x³-7x+6 with (x-1) then we will get x²+x-6 so we can write x³-7x+6 as (x-1)(x²+x-6) =(x-1)(x²+3x-2x-6) =(x-1)(x(x+3)-2(x+3))=(x-1)(x-2)(x+3)so the other zeros are 2 and -3

Answer»

By hit and trailput X=1 the result is zerosince 1 is a zero of x³-7x+6

(x-1)is the factor of x³-7x+6

so if we divide x³-7x+6 with (x-1) then we will get x²+x-6

so we can write x³-7x+6 as (x-1)(x²+x-6)

=(x-1)(x²+3x-2x-6)

=(x-1)(x(x+3)-2(x+3))=(x-1)(x-2)(x+3)so the other zeros are 2 and -3

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