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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
24EXERCISăClassify the following numbers as rationa |
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Answer» i) 2 - √5 is irrational. Reason Whole number when subtracted with irrational all gives irrational |
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| 2. |
Resolve into the partial fraction\frac{1}{x^{3}+3 x^{2}+2 x} |
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| 3. |
7. Arnav has bundles of rupee 10 notes. The serial number of the notes? 0from 825760 to 825980. What is the total value of the bundles of notes(1)2200 (2) 2210 (3) 2190 (4) 2220. |
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Answer» 220*102200 as 825980-825760= 220and there will be approx 100 notes |
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3. Find the factors of x + x+ y+ y4.Find the factors of xx+y- y |
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| 5. |
018. If both a and b are rational numbers, find the values of a and b in the givenoequalityV5+3V5-V-a+bv 15 |
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| 6. |
If both x 2 and x -,are the factors of the polynomial pa2+5x + r, show that, are the factors of the polynomial |
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| 7. |
4Resolve into partial fraction1 |
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| 8. |
Resolve the following rationax2 - a? |
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Answer» 1÷(x+a) (x-a)may be correct answer . Solution: 1/x^2 - a^21/(x -a)(x + a)Answer: 1/(x -a)(x + a)Some information: * a^2 - b^2 = ( a + b)(a - b) Hope it helps you! MasterYaduvanshi ( Brainly Moderator) |
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| 9. |
Resolve x18 - y18 into 5 factors, |
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| 10. |
Resolve x18 - y18 into 5 factors. |
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| 11. |
Find the mean by direct method |
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Answer» Mean = ( sum of f*x)/ (sum of f)= 281/40 = 7.025 |
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| 12. |
A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is5 cm. Find the outer curved surface area of the bowl |
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| 13. |
8. A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is5 cm. Find the outer curved surface area of the bowl. |
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Answer» Answer-173.25cm^2 Total diameter= 10 +0.25+0.25=10.5Radius= (5+0.25)=5.25curved surface area2πr²=2*3.14*5.25*5.25173.25cm^2 |
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| 14. |
is the given equality true? |
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Answer» Thanks |
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| 15. |
State when equality will hold: |
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| 16. |
Resolve into factors a^{4}+64 b^{4} |
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| 17. |
5. A well is to be dug 20 m deep, 2.25 minside diameter,with a brick lining of 0.35m thickness. What is the amount of brickwork done?(A) 14.75 m3 (B) 57.2 m3(C) 136.75 m' (D) 572 m3 |
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Answer» C to c dia is 2.25+0.35=2.60 m Center perimeter=3.14 x 2.6=8,16 m Volume ofthe stringing brick masonry wall will be 8.16 x0.35 x 20=57.12 cum hit like if you find it useful |
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| 18. |
Resolve into factors(a) 27a^3 -b^3+c^3 + 9abc. |
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Answer» tq |
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| 19. |
How many books each 1.5 cm thick can be kept in a shelf 1.45 m high. |
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Answer» thickness of books=1.5cm =0.015mheight of shelf=1.45mno. of books that can be kept in shelf=1.45/0.015=145*1000/15*100=290/3 m |
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| 20. |
Find the volume of wood required for makingthe closed box with internal dimensions : 20 cmby 12.5 cm by 9.5 cm; wood 1.25 cm thick. |
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Answer» Given outer length = 10 cmOuter breadth = 8 cmOuter height = 7 cmOuter volume = length × breadth × height= 10 × 8 × 7 = 560 cm3Thickness of wooden box, w = 1 cmInner length =l– 2w = 10 – 2 = 8 cmInner breadth =b– 2w = 8 – 2 = 6 cmInner height =h– 2w = 7 – 2 = 5 cmOuter volume = 8 × 6 × 5 = 240 c m3Volume of wood used = outer volume – inner volume= 560 – 240 = 320 cm3 thank u so much |
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| 21. |
17. Find the volume of wood required for makingthe closed box with internal dimensions : 20 cmby 12.5 cm by 9.5 cm ; wood 1.25 cm thick. |
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Answer» Given outer length = 10 cm Outer breadth = 8 cm Outer height = 7 cm Outer volume = length × breadth × height = 10 × 8 × 7 = 560 cm3 Thickness of wooden box, w = 1 cm Inner length =l– 2w = 10 – 2 = 8 cm Inner breadth =b– 2w = 8 – 2 = 6 cm Inner height =h– 2w = 7 – 2 = 5 cm Outer volume = 8 × 6 × 5 = 240 c m3Volume of wood used = outer volume – inner volume = 560 – 240 = 320 cm3 Given cost of 1 cm3of wood = Rs 2 Hence the total cost of wood required = Rs 2 × 32= Rs 640 |
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| 22. |
11. A bag contains 18 balls out of which x balls are red(6) If one ball is drawn at random from the bag, what is the probabilitythat it is not red?(i) If two more red balls are put in the bag, the probability of drawinga red ball will be times the probability of drawing a red ball in theCBSE 2015first case. Find the value of x. |
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| 23. |
. A fan is sold for 644. The gain is one-sixth of thecost price of the fan. Find the profit per cent. |
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Answer» SP = CP + CP/6SP = 7/6CP Profit % = [(SP - CP)/CP]*100= [(7/6-1)CP/CP]*100= (1/6)*100= 16.6% |
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| 24. |
(iv) 4x2-25x-21-0 |
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Answer» Solution:x = 7 or x = -3/4 Explanation:Consider the given equation 4x² - 25 x - 21= 0Split the middle term=> 4x² - 28x + 3x - 21= 0Regroup the terms=> 4x(x - 7) + 3(x - 7) = 0=>. (x - 7)(4x + 3) = 0=> x = 7 or x = -3/4 |
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| 25. |
w many pieces of plywood, each 0.35 cm thick, are required to make a pile 1.89 m highHint. 1.89 m = (1.89x100) cm = 189 cm.17. The product |
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Answer» 1.89m=189cmSo,189/.35=540So,540 pieces of plywood needed to make a pile |
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| 26. |
How many pieces of plywood, each 0.35 cm thick, are required to make a pile 1.89 m high? 16. 2.09Hint. 1.89 m = (1.89x100) cm = 189 cm.(a171. |
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| 27. |
44what is the radius of the circle so formed? | Take Ď7)-The wheel of a carrotated 1000 times in travelling a distance of 1.76 km. Find the radius of thewheel. | Take Ď =-7 |
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Answer» In one rotation the wheel travels a distance equal to it's circumference. (2πr) It's given that in 1000 rotations it travels 1.76 km. So 1000×2πr= 1.76 km. (1)1km =1000m 1.76 km = 1.76 ×1000 mSo (1) is written as1000×2πr=1.76×10002πr=1.76r=1.76/2πr=0.88/π Put π=22/7r=0.88×7/22r=0.4×7 r=2.8 m |
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| 28. |
3. If the circtumference of a circular sheet is 154 m, find its radius. Also find the area ofthe sheet. (Take)7ilensth of the |
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| 29. |
A wire of length 18 m had been tied with electric pole at an angle of elevationthe ground. As it i60° with the ground. How much length of the wire was cut?s covering a long distance, it was cut and tied at an angle of elevation |
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Answer» First, sinA=P/Hhere, sin30=1/2H=18 mso,P/H=1/2or,P=H/2=9 m In second case, the length of the pole i.e. P=9 m will be the same.sin60=√3/2=P/Hhere we have to find H.so,H=(9x2)/√3 =18/√3 =(18x√3)/3 =6x√3=6x1.72(approx.)=10.32so, new length=10.32so,decrease in length=18-10.32 m=7.68 m. |
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| 30. |
I. In the given figure LABC = ZDCB= 90°.8A (AABC)AB-6, DC = 8 then A (ADCB)-!6 |
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| 31. |
draw a parallel circuit with a compressor and a condensor fan motor |
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| 32. |
a) Draw a schematic labelled diagram of a domestic wiring circuit which includes (0,() a power meter (ii) one light point and (iv) a power plugb) Why is it necessary to connect an carth wire to electric appliances having metalc e |
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Answer» (b) (i) It prevents damage to appliance due to overloading or short-circuiting. (ii) Earth wire is connected to a metallic body buried deep inside the earth. It is used assafetymeasure. It providesa low resistance conducting path for the current any leakage of current to a metallic body does not giveshocktouser. |
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| 33. |
\frac { 25 \% \text { of } 50 \% \text { of } 100 \% } { 25 \times 50 } |
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| 34. |
13.(a) A rope of length 3 m 60 cm is cut into two pieces such that the ratio of the lenuhthe pleces is 7:5. Find the length of the larger piece. |
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Answer» Let the length of two pieces be 7x and 5xTotal length of the rope =360cm7x+5x=36012x=360x=30Length of the larger piece=210cm=2m10cm length of large piece is 2m 10cm. 2metre 10 centimeters is length of the rope |
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Q.1. What is bark? Give its importance. Whycertain barks used in medicines ?are |
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Answer» Ans :- Bark is the outermost layer of the stem and roots of a woody plant. It protects the plant from losing water. It prevents infections by fungus and bacteria. Certain barks has the properties to work against parasites. Such as willow bark which have the ability to kill lower back pain. It acts as aspirin. In the same way there is tree bark, todd's bark etc |
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| 36. |
the area over which8. A cow is tied to a pole on one end of a rectangular park with a string 14 m. Findthe cow can graze. (Take 7-22) |
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Answer» Adarsh Amita Ka pratirodh Hota Hai |
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| 37. |
. A rope by which a cow is tethered is increased from 16 m to 23 m. Howmuch additional ground does it have now to graze? |
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| 38. |
Find the length of a rope by which a cow must be tethered in order that it may be able tograze an area of 9856 m2.9856 m2 and radius eaual to the l |
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| 39. |
4. One train can accommodate 925 passengers. How many trains are required toaccommodate seats for 5,84,600 passenger? |
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Answer» One train can accommodate = 925passengersNo. Of trains required to accommodate 584600 passengers= 584600/925= 632 ans |
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| 40. |
d: (i) LB(ii) ZEDC(ii) ZADE (iv)(v) ZDEC(vi) ZDCBV110025(vii) LACBVilig, Q. 12 C |
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Answer» i) in triangle BDC Angle B = 180-(100+25) =55ii)angle EDC= DCB (alternate angles) =25iii)angle ADE = 180-( BDC+EDC) = 180-(100+25) = 55iv) in triangle ADE angle AED= 180-(A+ADE) = 180-(55+55)=70V)angle DEC = 180-(ADE) = 180-70 =110vi) angle ECB= AED ( corresponding angle ) angle ECD= 70-25 =45vii)angle ACB= AED ( corresponding angle ) ACB= 70 |
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| 41. |
1. Ajay cut a 199-m-long rope into two pleces of lengths 3 - m and 8-m. Find the length ofthe remaining rope. |
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Answer» lengths of two pieces is 47/4 the remaining length of rope is 98/5-47/4=157/20 |
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| 42. |
A circus artist is climbing a 20m long ropewhich is tightly stretched and tied from thetop of a vertical pole to the ground. the heightof the pole if the angle made by the rope withground level is 30. is |
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| 43. |
ybhichgroupoforganisms are not constituents ofa food chain?() Grass, lion, rabbit, wolfPlankton, man, fish, grasshopperX(iĂźi) Wolf, grass, snake, tigerfiv) Frog, snake, eagle, grass, grasshopper(A) () and (iii)(C) (ii) and (iii)20(B) (iii) and (iv)(D) (1) and (iv) |
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| 44. |
11.lfx2__7then find value of x,?(a) 9(b) 15(c) 27(d) 18 |
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Answer» Option-D (x + 1/x)^2= x^2+ 1/x^2+ 2(x + 1/x)^2= 9x + 1/x = 3now(x + 1/x)^3= x^3+ 1/x^3+ 3(x + 1/x)27 = x^3+ 1/x^3+ 9x^3+ 1/x^3= 27 - 9 = 18 proved that (1-tana/1-cota)
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| 45. |
(ii) The cat asked for(A) milk (B) grass (C) sickle (D) wood |
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Answer» The cat asked for milk Option A is correct |
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| 46. |
EXERCISE 9.1a 20 m long rope, which isghtly stretched and tied from the top of a verticalole to the ground. Find the height of the pole,ぱhe angle made by the rope with the ground level iso (see Fig 9.11) |
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| 47. |
. A cow is tied with a rope of length 7m at the corner of arectangular field of dimensions 20m x16m. Find the area of thefield in which the cow cannot graze |
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| 48. |
16. A cow is tied with a rope to one corner of a square field of side 50 m. If thelength of the rope is 14 m, find the area the cow cannot graze. |
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Answer» 2346.14 sq.m first you take out the perimeter of square,i.e.,side*side =50m x 50m = 2500 sq. m Now take out the area of the field that the cow can graze,i.e., angle of square/360 x 3.14r2 =900/3600x 3.14 x 14m2 =153.86 sq.m Now the area that it can't graze = (2500-153.86)sq. m =2346.14sq.m |
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| 49. |
Acircus artist is climbing a 20 m long rope, which isightly stretched and tied from the top of a verticalpole to the ground. Find the height of the pole, ifthe angle made by the rope with the ground level is30(see Fig. 9.11) |
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Answer» thankyu |
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| 50. |
RATIONAExercise I. Identify the rational numbers and then wtheir numerators and denominators:(in) -6(iv)(ii) 0(vi)oi)-8(vil) |
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Answer» Numerator Denominator (i) 5 1 (ii) -6 1(iii) 0 1(iv) 6 7(v) -7 8(vi) 5 0 |
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