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A wire of length 18 m had been tied with electric pole at an angle of elevationthe ground. As it i60° with the ground. How much length of the wire was cut?s covering a long distance, it was cut and tied at an angle of elevation |
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Answer» First, sinA=P/Hhere, sin30=1/2H=18 mso,P/H=1/2or,P=H/2=9 m In second case, the length of the pole i.e. P=9 m will be the same.sin60=√3/2=P/Hhere we have to find H.so,H=(9x2)/√3 =18/√3 =(18x√3)/3 =6x√3=6x1.72(approx.)=10.32so, new length=10.32so,decrease in length=18-10.32 m=7.68 m. |
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