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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
5. यदि (30 + 5b) : (30 -5b) = 5:1का मान होगाहो तो, d: b |
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Answer» 3a+5b/3a-5b=5/13a/b+5/3a/b-5=5/1(dividing by b)3a/b+5=15a/b-2530=12a/ba/b=5/3 |
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| 2. |
4^5*a^8b³/4^5*a^5b^2 |
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| 3. |
verify a-(-b)=a+b for a=-9 b=-11 |
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Answer» a-(-b)=a+b-9-(-(-11)=-9+(-11)-9-11=-9-11-20=-20 |
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| 4. |
if a=9 b= -6 so then (a-b) ≠(b-c) |
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Answer» Sorry but you haven't mentioned the value of c. Value of c is required to prove it. c ke jagha a hoga sry |
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| 5. |
iii) (a-b) (a + b) + (b-9(b + c) + (c-. Ifx7, find the value of(i) x2 + |
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| 6. |
(24.If 20 % A = 15%B,then find A: B |
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Answer» (20/100) A = (15/100) BA/B = 15/20A/B = 3/4A:B = 3:4 |
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| 7. |
\left( 4 a ^ { 2 } - 4 a b - 15 b ^ { 2 } \right) \div ( 2 a - 5 b |
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| 8. |
e 8: A cow is tied to a pote with a 10 m long rope. The cow sevesrope tight. Find the areas of ground swept by the cow (Using s |
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| 9. |
A cow is tied to a pole with a 14 m long rope.18.Find the area where the cow can graze |
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Answer» That means radius is 14m Area that cow can graze = pi × r² = 22/7 × 14² = 22 × 2 × 14 = 44 × 14 m² = 616 m² |
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| 10. |
v The figure made up two or more plane figureis called avi perinater og altside vil the equivalentdecimalo 2.3 is avillkom |
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Answer» v)Polygonvi)Squarevii)13.76viii)16000cmMARK AS THE BEST ANSWER PLEASE polygonsquare 13.7616000cm |
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| 11. |
Show that the following four conditions are equivalent:(i) A B (ii) A-B (iii) A u B B (iv) A B AV.va |
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| 12. |
25and BIthen compute 3A -5B722L5 5 5 |
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| 13. |
,5) Expand (3a -2b)^2 |
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Answer» (3a)^2-2(3a)(2b)+(2b)^2=9a^2-12ab+4b^2 |
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| 14. |
A choed of a circle is equal to the radius of thecncle. Find the angle subtended by the chord ata point on the minor arc and also at a point on the |
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| 15. |
holu Rat |
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| 16. |
Thx '9=(B-2) |
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Answer» x³-y³=234 is the answer 234 is the correct answer |
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| 17. |
84, Madhuboughthetes etVE1, 312mnaits value dutriates at'the rat01 10'/ă |
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Answer» full image |
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| 18. |
विनर N e g o ooy iR T T STt e| 92tan-l (l‘) जय कककककककककककररक9% | |
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| 19. |
10.ir3 tan = 3 sino then sin-e-cosin equal to(a) √(b) 213(0) 13(d) 113 |
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| 20. |
(3a + 5) (3a - 8) |
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Answer» (3a + 5)(3a - 8)=(9a^2-24a+15a-40) =9a^2- 9a -40 9a-40×15a-409a×15a-40×40135a-1600 (3a+5)(3a-8)=3a(3a-8)+5(3a-8)=9a²-24a+15a-40=9a²-9a-40 (3a +5)(3a-8)=(9a^2-24a+15a-40)=9a^2-9a-40 (3a +5) (3a -8)3a + 5 × 3a -83a +3a × 5 - 86a × (-3) |
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| 21. |
Expand: (1) (3x - 2y) |
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Answer» (a-b)^2=a^2+b^2-2ab(3x-2y)^2=9x^2+4y^2-12xy |
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| 22. |
: Expand (3a + 2y)^3 |
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Answer» (3a + 2y)³ (3a)³ + (2y)³ + 18ay(3a+2y) 27a³ + 8y³ + 18ay ( 3a + 2y) |
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| 23. |
Which of the following numbers are not perfect ube0216yヅ邇128y) 46656cubes?(im) 10001.in),her by which each of the following |
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Answer» 128, is not perfect cube |
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| 24. |
Gust - SEXTIMOFF THX), ube |
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Answer» It should be 8/31 in question so |
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| 25. |
The total surface area of a ube is13 50 99 m. find wts noleme. |
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Answer» 3375 is correct answer 3375 is the answer for that question 3375 is correct answer to that question 3375m3 is the correct answer 3375 m³ is the correct answer surface area of cube=1350msq =6a sq1350/6=a sq=225ma=15mvolume=a cube=15×15×15=3375m cube please like my answer everyone |
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| 26. |
noestas whi in tha ratcncle then2/22. |
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Answer» Thinks |
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| 27. |
sec 6 + tan 68. For a given frequency distribution, Z+M 34 and M+x#40. Then, find M. |
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| 28. |
a+b = 5 3a + 2 b = 20 ( 3a + b) = ? |
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| 29. |
Simplify: (a) [7 - 2x + 5y - (x - y)] - (5x + 3y - 7) (b) (2a-4) (2a2 - 5a + 1)-(2a - 1)(32? + 7a -5)(c) (5yz + 6x2)(5yz - 6x²) |
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Answer» 1. 2x +5y 🤣🤣🤣accept as best |
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| 30. |
bor07. Calculate the missing frequency from the following distribution, ibeing given that the median of the distribution is 24.ClassFrequenc10-2020-3030-4040-0-1052518 |
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| 31. |
7.Calculatethemissingfrequencyfromthefollowingdistribution,abeing given that the median of the distribution is 24.Class0-1010-20 20-303040456Frequency18258. The median of the following data is 16. Find the missing frequencies a |
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| 32. |
For a given frequency distribution, z+M=34 and M+x=40. Then. find the value of M |
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| 33. |
Expand (+2y) by the binomial theorem. |
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Answer» nCr. |
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| 34. |
Expand (2 +2y) by the binomial theorem. |
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Answer» using the expansion formulaX^10 + 10x^4 y +40x^6 y^2 +80x^4 y^3 + 80 x^2 y^4 +32 y^5 |
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| 35. |
24x â 3y = 8 - 18x â 3y = 29 |
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| 36. |
Expand (a +2y) by the binomial theorem. |
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Answer» putting in the above formulaX^10 + 10x^4 y +40x^6 y^2 +80x^4 y^3 + 80 x^2 y^4 +32 y^5 |
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| 37. |
ŕ¤ŕĽ 3y =8 .. (Dey -2 ... (8 |
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| 38. |
Find the domaifunctionsi) f(x) x2 |
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Answer» f(x) = x² here x can take all the values from -∞ to ∞ . so domain is (-∞, ∞) |
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| 39. |
SubtractCID -36 from 42 |
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Answer» -36 from 42that means 42-(-36)=42+36(- - = + )=78 😂😂 itz easyans=78 Subtract :--36 from 42=42-(-36)=78 42-(-36)42+36 -36 from 42 = 42-(-36) = 78 Given subtraction is 42 - ( -36 ) -36 from 42 that means 42-(-36)=42+36 (- + - = +)= 78 |
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| 40. |
(i)-7x2 + 18x2 + 3x2-5x2 |
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Answer» -7x²+18x²+3x²-5x²(-7+18+3-5)x²9x² |
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| 41. |
Evaluate:(0 -7x2+18x2+3x2-5x2 |
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| 42. |
यदि A10 -1102तथाB[35है तो AB का मान ज्ञात कीजिए00 |
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| 43. |
Consider a 7-digit number N = ABCDE15. If N is divisible by 11 then the maximum value of A+ C+E is(A) 18(B) 16(C) 23(D) 27 |
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Answer» C) is correct answer C) is the correct answer C) is correct answer C) the correct answer C is the correct answer C) the correct answer c was the correct answer C is correct answer c) is the right answer of the following option (c) is the right ans |
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| 44. |
The tens and units places of a two digit number are m and n respectively. Write the polynomial which represents the two-digit number. |
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Answer» it will be 10m+n this will be a two digit number |
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| 45. |
दिRत में, यदि 48 || (00, ८40 इन और ८12९0 न 1277 है, तो 2 ऊं |
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| 46. |
3. How do committees help the Municipal Corporations? |
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Answer» Eachmunicipal council willappoint standingcommitteeselected from among its members. Usually these include a financecommittee; servicecommitteessuch as water, sanitation, electricity; human resources; and developmentcommittees. |
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| 47. |
AC and BD are chords of a circle which bisect each other. Prove that (i) AC and BD arediameters, (ii) ABCD is a rectangle. |
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| 48. |
-311. By what number shouldml cobe divided to get |
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| 49. |
find the height of the lamp post.ĐĐž \ In a rhombus ABCD the diagonals bisect at 0. Prove that AC, BD" 4 AB2 |
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Answer» Let ABCD is rhombus AC and BD are diagonals we know that, AB=BC=CD=AD If O is centre, AO = OC = AC/2 BO = OD = BD/2 In triangle AOB, AB² = AO² + BO² => AB² = (AC/2)² + (BD/2)² => AB² = AC²/4 + BD²/4 => AB² = AC²+BD²/4 => 4AB² = AC² + BD² Hence proved |
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| 50. |
AC and BD are chords of a circle that bisect each other. Prove that:(i) AC and BD are diameters.(ii) ABCD is a rectangle. |
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